I got a question about the ladder system. So obviously blizzard has implemented some sort of MMR-system (something like ELO). At legend rank, we know they use the MMR to give a skill-rating comparable to everyone else. Obviously, it makes perfect sense for them to record the MMR for all players, not just legend players, in order to get the most accurate stats.
Now, I was under the impression that before legend, players are not matched according to MMR, but rather rank. But, you can be matched with legend players as a rank 1-3 players, and usually the lower tier. So doesn't this mean that they are really using the MMR to match players even in rank 1-3?
I'm just wondering what we know about the matchmaking system. My personal speculation is that it is basically purely based on MMR, perhaps with a few modifications so that a rank 19 would never meet a rank 1 despite even MMR.
u could be matched with legend if u are 1-3 rank because there are not that many players in the said ranks (from legend to 3 or so), especially earlier in the season. Plus the fact that if u play in abnormal time, like 4am etc.
Sure, and therefore I believe it uses the MMR to compare, at least whenever there are no one with approximate rank in queue. But the question remains: are players matched according to MMR or rank in general? Two players with similar MMR will in general have similar rank. But are they matched because of their rank or their MMR?
Just to make it clear, this is really a question about the inner mechanism of queued search - the actual code behind it - and not about what happens superficially in practice.
The text on Cult apothecary is slightly ambiguous in how it will function. (Battlecry For each enemy minion, restore 2 health to your hero)
Now is this effect staggered; they have two minions the effect heals 2 then another 2, or does it clump that into healing 4? Because if it's staggered I would consider this card top tier in priest.
On April 26 2016 00:49 Ovid wrote: The text on Cult apothecary is slightly ambiguous in how it will function. (Battlecry For each enemy minion, restore 2 health to your hero)
Now is this effect staggered; they have two minions the effect heals 2 then another 2, or does it clump that into healing 4? Because if it's staggered I would consider this card top tier in priest.
Lil Exorcist gets the buff a single time. Unlikely that it's staggered.
On April 26 2016 00:49 Ovid wrote: The text on Cult apothecary is slightly ambiguous in how it will function. (Battlecry For each enemy minion, restore 2 health to your hero)
Now is this effect staggered; they have two minions the effect heals 2 then another 2, or does it clump that into healing 4? Because if it's staggered I would consider this card top tier in priest.
Lil Exorcist gets the buff a single time. Unlikely that it's staggered.
Paladin has multiple 1 health minions and Redemption secret, Hunter plays Knife Juggler and Unleash the Hounds. Which minion gets Redemption? One who gets killed first or one who was played first?
It's whichever of the ones that is killed that was played first. The death resolution happens at the end of the UTH action stack, not in the middle: same reason why you have to wait for C'thun to finish thwopping to see the minions die. At that time, Redemption activates as if it had been an ordinary AoE spell.
On May 24 2016 02:28 Acritter wrote: It's whichever of the ones that is killed that was played first. The death resolution happens at the end of the UTH action stack, not in the middle: same reason why you have to wait for C'thun to finish thwopping to see the minions die. At that time, Redemption activates as if it had been an ordinary AoE spell.
I read that if Yogg-Saron, Hope's End battle cry kills Sylvanas and it gets stolen then it will keep casting spells for the opponent. Will it reset number of spells to cast to one that opponent has casted or keep casting remaining number of spells as if it was not stolen?
On May 24 2016 02:28 Acritter wrote: It's whichever of the ones that is killed that was played first. The death resolution happens at the end of the UTH action stack, not in the middle: same reason why you have to wait for C'thun to finish thwopping to see the minions die. At that time, Redemption activates as if it had been an ordinary AoE spell.
I read that if Yogg-Saron, Hope's End battle cry kills Sylvanas and it gets stolen then it will keep casting spells for the opponent. Will it reset number of spells to cast to one that opponent has casted or keep casting remaining number of spells as if it was not stolen?
Cast the remaining number as if it was not stolen. Due note that Brann on your side still multiplies it by two.
Text states "If your C'thun has at least 10 attack", tho it clearly has not.
I have no idea whether this is a bug or intended, but it's covered in a recent Toast video:
It would seem that "If your C'Thun has at least 10 attack" refers to what could be described as an individual player's C'Thun score, which is dictated by the buffs applied, not specifically by C'Thun as a single card or minion.
This is the same reason why you can still increase your C'Thun score without even having the card in your deck, or how you can have multiple copies of a 16/16 C'Thun in your deck, though the one on the field has been Aldor'd.
The animation for buffing has been patched to only happen if you actually have C'Thun in your deck now. As for the rest, it's something I discovered during launch:
On May 26 2016 02:17 Wuster wrote: The animation for buffing has been patched to only happen if you actually have C'Thun in your deck now. As for the rest, it's something I discovered during launch:
At the start of game when I have option to replace cards, if I press "Confirm" without replacing any cards, does opponent see that I did not replace any cards? or it's the same as if I haven't done anything?
Just played a game where Yogg Sarron was played after i had stealth-ed my board. First two spells were target a minion spells and Yogg targeted itself and destroyed itself.
Question was this coincidence or did the stealth afect Yogg.