EPTInitially, I drew the picture like this.
![[image loading]](http://img156.imageshack.us/img156/4411/95222056.jpg)
F=pgAd
p=840 A=2(4(3)^(1/2)-y)/(3)^(1/2)dy
g=9.8 d=4(3)^(1/2)-y
So, I took the integral using all of that with boundaries [0,4(3)^(1/2)] and got 1053696 (twice as much as the actual answer).
So, I looked up the problem on google and one of the sites showed the picture as the following:
![[image loading]](http://img34.imageshack.us/img34/2285/24595462.jpg)
So I solved the problem using that picture and got the right answer.
My question is, does it matter how you draw the picture or did I just have a wrong set up for my own interpretation?
