[Math Puzzle] Day 1 - Page 2
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thunk
United States6233 Posts
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MasterReY
Germany2708 Posts
gj evan and sean | ||
stenole
Norway868 Posts
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MasterReY
Germany2708 Posts
On April 28 2009 06:34 stenole wrote: It's never fun to start a puzzle when there are + show spoiler + all over the place and comments of admiration and awe. I see these threads too late. why? you just don't open the spoilers and you can try yourself =D | ||
edahl
Norway483 Posts
(a^n)(a^m)=a^(n+m)=a^(m+n)=(a^m)(a^n). I just had to read the section first :-P | ||
MasterReY
Germany2708 Posts
On April 28 2009 06:48 edahl wrote: Btw, (a^n)(a^m)=a^(n+m)=a^(m+n)=(a^m)(a^n). I just had to read the section first :-P dude wtf......thats so useless haha 3*5 = 5*3 has the same message^^ | ||
edahl
Norway483 Posts
No it's not. It's proof that all cyclic groups are abelian. EDIT: http://en.wikipedia.org/wiki/Cyclic_group Evan challenged me to prove it quickly, you see, but I didn't know how yet :-P | ||
evanthebouncy!
United States12796 Posts
On April 28 2009 06:48 edahl wrote: Btw, (a^n)(a^m)=a^(n+m)=a^(m+n)=(a^m)(a^n). I just had to read the section first :-P | ||
MasterReY
Germany2708 Posts
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edahl
Norway483 Posts
The axioms are 1. (a*b)*c=a*(b*c) (associative property) 2. there is an element e in G so that a*e=e*a=a 3. for every a in G, there is an inverse called a^(-1), so that a*a^(-1)=a^(-1)*a=e (4. if a*b=b*a (commutative property) holds true for all a, b in G, the group is called abelian.) A cyclic group is a group generated by one element a in <a>, so that a^n is in the group for every n, where n is a whole number. n means the same as with exponents: repeated operation, so a^3 = a*a*a, and a^(-2)=a^(-1)*a^(-1). PS: It's got nothing to do with the riddle. Evan just asked me to prove it yesterday or something :-P | ||
MasterReY
Germany2708 Posts
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edahl
Norway483 Posts
On April 28 2009 07:07 MasterReY wrote: oh well. i had that stuff in german, but i can't recall with the english version now German mathematicians are awesome. http://en.wikipedia.org/wiki/Gauss http://en.wikipedia.org/wiki/Riemann | ||
phase
United States399 Posts
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Deleted User 3420
24492 Posts
I didn't read the thread or anthing in it | ||
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