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The Big Programming Thread - Page 866

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Thread Rules
1. This is not a "do my homework for me" thread. If you have specific questions, ask, but don't post an assignment or homework problem and expect an exact solution.
2. No recruiting for your cockamamie projects (you won't replace facebook with 3 dudes you found on the internet and $20)
3. If you can't articulate why a language is bad, don't start slinging shit about it. Just remember that nothing is worse than making CSS IE6 compatible.
4. Use [code] tags to format code blocks.
Nesserev
Profile Blog Joined January 2011
Belgium2760 Posts
Last Edited: 2017-03-30 23:37:35
March 30 2017 23:18 GMT
#17301
--- Nuked ---
WarSame
Profile Blog Joined February 2010
Canada1950 Posts
March 31 2017 00:24 GMT
#17302
Thanks! That's what all the answers are talking about with typedefs, right? The ability to alias a more complicated name for a simpler name?
Can it be I stayed away too long? Did you miss these rhymes while I was gone?
Manit0u
Profile Blog Joined August 2004
Poland17713 Posts
Last Edited: 2017-03-31 06:38:40
March 31 2017 06:37 GMT
#17303
On March 31 2017 09:24 WarSame wrote:
Thanks! That's what all the answers are talking about with typedefs, right? The ability to alias a more complicated name for a simpler name?


Here's a nice example:
http://ee.hawaii.edu/~tep/EE160/Book/chap14/subsection2.1.3.1.html

And here's a more convoluted explanation:
http://stackoverflow.com/questions/10758811/c-syntax-for-functions-returning-function-pointers
Time is precious. Waste it wisely.
Manit0u
Profile Blog Joined August 2004
Poland17713 Posts
March 31 2017 10:09 GMT
#17304
Time is precious. Waste it wisely.
Deleted User 3420
Profile Blog Joined May 2003
24492 Posts
March 31 2017 12:30 GMT
#17305
linear algebra question

is the column space of a matrix the same as the basis of a set of vectors that compose that matrix ?
Prillan
Profile Joined August 2011
Sweden350 Posts
March 31 2017 14:36 GMT
#17306
On March 31 2017 21:30 travis wrote:
linear algebra question

is the column space of a matrix the same as the basis of a set of vectors that compose that matrix ?

The column space is, by definition, the span of the column vectors. I have no idea what you're trying to say in the second part.
TheBB's sidekick, aligulac.com | "Reality is frequently inaccurate." - Douglas Adams
Djagulingu
Profile Blog Joined December 2010
Germany3605 Posts
March 31 2017 14:57 GMT
#17307
On March 31 2017 19:09 Manit0u wrote:
https://www.youtube.com/watch?v=VgC4b9K-gYU

We are rolling this feature out to most users on March 31, and all accounts will have access by April 1.
and all accounts will have access by April 1.
will have access by April 1.
by April 1.
April 1.
April 1
April 1
April 1
April 1
.
.
.

APRIL FOOLS GUYS :D:D:D
"windows bash is a steaming heap of shit" tofucake
Deleted User 3420
Profile Blog Joined May 2003
24492 Posts
March 31 2017 16:00 GMT
#17308
On March 31 2017 23:36 Prillan wrote:
Show nested quote +
On March 31 2017 21:30 travis wrote:
linear algebra question

is the column space of a matrix the same as the basis of a set of vectors that compose that matrix ?

The column space is, by definition, the span of the column vectors. I have no idea what you're trying to say in the second part.


what I mean is

for an nxn matrix, is the basis of it's column space the same as a basis for the matrix itself.

like if I have a question that gives me 5 vectors of 5 variables each that comprise a vector space
and it asks me to find the basis of the vector space
do I just find the pivot columns and then those vectors are the basis?
CoughingHydra
Profile Blog Joined May 2012
177 Posts
Last Edited: 2017-03-31 16:32:54
March 31 2017 16:32 GMT
#17309
The expression "basis for the matrix itself" has no meaning as far as I know.

And yes, pivot columns (I assume that by this you mean the vectors you get by Gaussian elimination with only column operations) are one of the possible bases for the space the original five column vectors span.
emperorchampion
Profile Blog Joined December 2008
Canada9496 Posts
March 31 2017 17:08 GMT
#17310
Afair the column space is all possible combinations of the basis. So no not the same.
TRUEESPORTS || your days as a respected member of team liquid are over
emperorchampion
Profile Blog Joined December 2008
Canada9496 Posts
Last Edited: 2017-03-31 17:22:09
March 31 2017 17:21 GMT
#17311
On April 01 2017 01:00 travis wrote:
Show nested quote +
On March 31 2017 23:36 Prillan wrote:
On March 31 2017 21:30 travis wrote:
linear algebra question

is the column space of a matrix the same as the basis of a set of vectors that compose that matrix ?

The column space is, by definition, the span of the column vectors. I have no idea what you're trying to say in the second part.


what I mean is

for an nxn matrix, is the basis of it's column space the same as a basis for the matrix itself.

like if I have a question that gives me 5 vectors of 5 variables each that comprise a vector space
and it asks me to find the basis of the vector space
do I just find the pivot columns and then those vectors are the basis?


To this yes (although I think your wording is wrong) the matrix will contain n out of the infinite possible columns in the column space that is defined by the basis.
TRUEESPORTS || your days as a respected member of team liquid are over
Acrofales
Profile Joined August 2010
Spain18251 Posts
March 31 2017 17:31 GMT
#17312
Wait. Won't it depend on what pivots you choose whether your pivot columns will form a basis for your matrix?

"Pivot columns" will not automatically form the basis. If you follow a suitable algorithm then yes, your pivot columns will form the basis, but if you choose the pivots wrong (lets say, picking random elements), then you'll just end up with a mess, rather than linearly independent vectors.
emperorchampion
Profile Blog Joined December 2008
Canada9496 Posts
March 31 2017 17:47 GMT
#17313
On April 01 2017 02:31 Acrofales wrote:
Wait. Won't it depend on what pivots you choose whether your pivot columns will form a basis for your matrix?

"Pivot columns" will not automatically form the basis. If you follow a suitable algorithm then yes, your pivot columns will form the basis, but if you choose the pivots wrong (lets say, picking random elements), then you'll just end up with a mess, rather than linearly independent vectors.


This is due to numerical errors in a GE procedure though if I understand correctly
TRUEESPORTS || your days as a respected member of team liquid are over
CoughingHydra
Profile Blog Joined May 2012
177 Posts
March 31 2017 17:47 GMT
#17314
Yes, it depends what you mean by pivot columns. I assumed something like in this wiki, except, as is said in the article, you should do column operations instead of row operations.
Hanh
Profile Joined June 2016
146 Posts
April 01 2017 01:29 GMT
#17315
You can use row echelon form for column space. No need to use column operations.
Zess
Profile Joined July 2012
Adun Toridas!9144 Posts
April 01 2017 08:00 GMT
#17316
What's the best way to translate this javascript that relies on jQuery object to be pure javascript?

jQuery("div.watched-badge").parents("ol.item-section").parent("li").remove();


I have almost no javascript knowledge, but based on a 20 minute documentation read, it seems that it is very difficult to traverse parent DOM elements while trivial to traverse child elements with querySelector

It seems that my best option is to
1) grab all of the "div.watched-badge" elements of the page
2) manually loop over each element's parent until I get to "ol.item-section" and then grab it's parent and remove it

The reason why I want to do this without jQuery is that this code cleans up my youtube subscription feed of watched videos (who knows why that doesn't happen by default) and I want to turn it into a bookmark or extension, so I feel that doing it in a way that doesn't require loading jquery into the page is probably the best (right now I'm manually injecting a jquery script in from their cdn and then running that code into the console).
Administrator@TL_Zess
| (• ◡•)|八 (❍ᴥ❍ʋ)
Nesserev
Profile Blog Joined January 2011
Belgium2760 Posts
Last Edited: 2017-04-01 08:31:08
April 01 2017 08:30 GMT
#17317
--- Nuked ---
Deleted User 173346
Profile Blog Joined April 2011
16169 Posts
April 01 2017 09:09 GMT
#17318
--- Nuked ---
Prillan
Profile Joined August 2011
Sweden350 Posts
April 01 2017 10:59 GMT
#17319
On April 01 2017 01:00 travis wrote:
like if I have a question that gives me 5 vectors of 5 variables each that comprise a vector space
and it asks me to find the basis of the vector space
do I just find the pivot columns and then those vectors are the basis?

Basically, yes. (As Hanh pointed out)

Put your vectors as columns in a matrix and reduce it with Gauss-Jordan elimination. See this for an example: https://en.wikipedia.org/wiki/Row_and_column_spaces#Basis

As a former teacher in linear algebra, please take care when using the different terms. They are precisely defined and should be used as such.

"5 vectors of 5 variables": vectors don't have variables. Did you mean 5 vectors in R^5?
"it asks me to find the basis of the vector space": a basis. There are (usually) infinitely many choices for a basis.
"then those vectors are the basis": same here.
"for an nxn matrix, is the basis of it's column space the same as a basis for the matrix itself.": I don't know what "a basis for the matrix" means. Is this something your professor has defined?
TheBB's sidekick, aligulac.com | "Reality is frequently inaccurate." - Douglas Adams
tofucake
Profile Blog Joined October 2009
Hyrule19200 Posts
April 01 2017 15:09 GMT
#17320
On April 01 2017 17:00 Zess wrote:
What's the best way to translate this javascript that relies on jQuery object to be pure javascript?

jQuery("div.watched-badge").parents("ol.item-section").parent("li").remove();


I have almost no javascript knowledge, but based on a 20 minute documentation read, it seems that it is very difficult to traverse parent DOM elements while trivial to traverse child elements with querySelector

It seems that my best option is to
1) grab all of the "div.watched-badge" elements of the page
2) manually loop over each element's parent until I get to "ol.item-section" and then grab it's parent and remove it

The reason why I want to do this without jQuery is that this code cleans up my youtube subscription feed of watched videos (who knows why that doesn't happen by default) and I want to turn it into a bookmark or extension, so I feel that doing it in a way that doesn't require loading jquery into the page is probably the best (right now I'm manually injecting a jquery script in from their cdn and then running that code into the console).


You'd basically have to go in reverse, start with a document.getElementsByClassName('item-section') and then traverse that and pick out the watched-badge subnodes
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