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The Big Programming Thread - Page 868

Forum Index > General Forum
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Thread Rules
1. This is not a "do my homework for me" thread. If you have specific questions, ask, but don't post an assignment or homework problem and expect an exact solution.
2. No recruiting for your cockamamie projects (you won't replace facebook with 3 dudes you found on the internet and $20)
3. If you can't articulate why a language is bad, don't start slinging shit about it. Just remember that nothing is worse than making CSS IE6 compatible.
4. Use [code] tags to format code blocks.
Deleted User 3420
Profile Blog Joined May 2003
24492 Posts
April 03 2017 18:56 GMT
#17341
Need to make sure I have the right idea on 1 discrete math question, and see if maybe I can get help on another

first one


Show that, (∀n ≥ 0)[7^(4n+2) ≡ 9 (mod 10)]. Use weak induction.


what I came up with
+ Show Spoiler +

I.B: n = 0 -> 7^2 = 49 -> is congruent to 9 (mod 10)

I.H: make a claim it holds true up to k

I.S: show the claim holds for k+1
the claim is that 7^(4k+4+2) is congruent to 9 (mod 10)

I can simplify the LHS to 7^4 * 7^(4k+2)
7^4 = 2401 which is congruent to 1 (mod 10)

1 (mod 10) * 9 (mod 10) = 9 (mod 10)

is it this easy or did I botch this up?




2nd one.. hard

a_2 = 40
a_3 = 300
(∀n ≥ 4)[a_n = 2a_(floor of n/2) + 7n]

find naturals A, B s.t.
(∀n ≥ 2)[a_n ≤ A*n*log(n) + B*n]

log meaning log_2
and make A as small as possible


the stuff I have came up with
+ Show Spoiler +

Our base

a_2 = 40, 40 <= 2A + 2B
a_3 = 300, 300 <= 3A*log_2(3)+3B

Hypothesis: they gave us a hint to solve for p(n-1) --> p(n) so I'll just say the claim above holds true to p(n-1)

Step:

a_n = 2a_(floor of n/2) + 7n

2a_(floor of n/2) + 7n <= n + 7n

8n <= A*n*log(n) + B*n

uh I don't know what I am doing anymore I am so lost lol

Acrofales
Profile Joined August 2010
Spain18215 Posts
April 03 2017 19:52 GMT
#17342
On April 04 2017 03:56 travis wrote:
Need to make sure I have the right idea on 1 discrete math question, and see if maybe I can get help on another

first one


Show that, (∀n ≥ 0)[7^(4n+2) ≡ 9 (mod 10)]. Use weak induction.


what I came up with
+ Show Spoiler +

I.B: n = 0 -> 7^2 = 49 -> is congruent to 9 (mod 10)

I.H: make a claim it holds true up to k

I.S: show the claim holds for k+1
the claim is that 7^(4k+4+2) is congruent to 9 (mod 10)

I can simplify the LHS to 7^4 * 7^(4k+2)
7^4 = 2401 which is congruent to 1 (mod 10)

1 (mod 10) * 9 (mod 10) = 9 (mod 10)

is it this easy or did I botch this up?




2nd one.. hard

a_2 = 40
a_3 = 300
(∀n ≥ 4)[a_n = 2a_(floor of n/2) + 7n]

find naturals A, B s.t.
(∀n ≥ 2)[a_n ≤ A*n*log(n) + B*n]

log meaning log_2
and make A as small as possible


the stuff I have came up with
+ Show Spoiler +

Our base

a_2 = 40, 40 <= 2A + 2B
a_3 = 300, 300 <= 3A*log_2(3)+3B

Hypothesis: they gave us a hint to solve for p(n-1) --> p(n) so I'll just say the claim above holds true to p(n-1)

Step:

a_n = 2a_(floor of n/2) + 7n

2a_(floor of n/2) + 7n <= n + 7n

8n <= A*n*log(n) + B*n

uh I don't know what I am doing anymore I am so lost lol


First one is indeed that easy.

Second one, I'd start by filling in some numbers and getting a feel for the thing. How much is a_4? a_5? a_100? What A, B could you think that works for those a? Now that you have a feel for it, start thinking what it means that for any a_n there is an upper bound, and what A, B you can think of that might work for that. Once you have some basic idea of what the proof should look like, it's easier to actually write the proof.
Deleted User 3420
Profile Blog Joined May 2003
24492 Posts
Last Edited: 2017-04-03 23:22:09
April 03 2017 21:32 GMT
#17343
Well, I am closer
but I am screwing something up

I went through expamples like you said and could see that it held true but it didn't feel like that brought me closer to the proof

anyways this is what I have now:

+ Show Spoiler +

a_n = 2a(floor of n/2) + 7n

which should be <= A*(n/2)log(n/2)+B(n/2)

we know this because the floor of n/2 is less than or equal to n/2

now comparing that right hand side against the original claim

((A*log(n/2)+B)*n) / 2 <= A*nlog(n) + Bn

divide everything by n and multiply both sides by 2

A*log(n/2)+B = 2A*log(n)+2B

subtract B

Alog(n/2) = 2Alog(n)+B

=

A(log(n)-1) = 2Alog(n)+B

=

Alog(n)-A = 2Alog(n)+B

this can't be right

where am I screwing up
math is hard lol
w/e I will take a break for a bit and come back maybe you will point some stuff out to me


edit: oh i left out 7n huh
well i gotta do dishes i will come back to this


edit: i found my errors and fixed them. i believed I have solved it.
WarSame
Profile Blog Joined February 2010
Canada1950 Posts
April 03 2017 22:00 GMT
#17344
I am going to start applying to places again. My current job has me sitting on the sidelines a lot, not doing much work. I've been practicing C with my free time, but I want to actually do work, and get hands-on experience.

Does anyone have advice looking in the market of Southern Ontario? In general?

I'm mostly looking for backend jobs. What do y'all feel I should know/am expected to know if I am a 1 year out of school dev?

I'll probably be following up with help on interviews at some point, but thank you for any advice you have.
Can it be I stayed away too long? Did you miss these rhymes while I was gone?
dsyxelic
Profile Joined May 2010
United States1417 Posts
Last Edited: 2017-04-03 22:31:11
April 03 2017 22:15 GMT
#17345
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.
TL/SKT
Blitzkrieg0
Profile Blog Joined August 2010
United States13132 Posts
April 03 2017 22:43 GMT
#17346
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.
I'll always be your shadow and veil your eyes from states of ain soph aur.
dsyxelic
Profile Joined May 2010
United States1417 Posts
April 03 2017 22:59 GMT
#17347
On April 04 2017 07:43 Blitzkrieg0 wrote:
Show nested quote +
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns
TL/SKT
Blitzkrieg0
Profile Blog Joined August 2010
United States13132 Posts
Last Edited: 2017-04-03 23:09:43
April 03 2017 23:09 GMT
#17348
On April 04 2017 07:59 dsyxelic wrote:
Show nested quote +
On April 04 2017 07:43 Blitzkrieg0 wrote:
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns


It's more of a big company bureaucracy issue. There's a lot of moving parts to getting hardware for new employees and as an intern it isn't at the top of any ones list.

PS: Hardware that you can't use doesn't count.
I'll always be your shadow and veil your eyes from states of ain soph aur.
dsyxelic
Profile Joined May 2010
United States1417 Posts
April 03 2017 23:11 GMT
#17349
On April 04 2017 08:09 Blitzkrieg0 wrote:
Show nested quote +
On April 04 2017 07:59 dsyxelic wrote:
On April 04 2017 07:43 Blitzkrieg0 wrote:
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns


It's more of a big company bureaucracy issue. There's a lot of moving parts to getting hardware for new employees and as an intern it isn't at the top of any ones list.

PS: Hardware that you can't use doesn't count.


I see, definitely encouraging to know this is commonplace.

Oh well I guess I am not one of the lucky ones haha. Hopefully it will be usable tomorrow.
TL/SKT
Blitzkrieg0
Profile Blog Joined August 2010
United States13132 Posts
April 03 2017 23:20 GMT
#17350
On April 04 2017 08:11 dsyxelic wrote:
Show nested quote +
On April 04 2017 08:09 Blitzkrieg0 wrote:
On April 04 2017 07:59 dsyxelic wrote:
On April 04 2017 07:43 Blitzkrieg0 wrote:
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns


It's more of a big company bureaucracy issue. There's a lot of moving parts to getting hardware for new employees and as an intern it isn't at the top of any ones list.

PS: Hardware that you can't use doesn't count.


I see, definitely encouraging to know this is commonplace.

Oh well I guess I am not one of the lucky ones haha. Hopefully it will be usable tomorrow.


I would suggest just talking to people. Building relationships is the most important thing you can do at an internship. Don't bother people if they're busy working on something, but throw yourself out there.
I'll always be your shadow and veil your eyes from states of ain soph aur.
dsyxelic
Profile Joined May 2010
United States1417 Posts
Last Edited: 2017-04-04 00:18:30
April 04 2017 00:12 GMT
#17351
On April 04 2017 08:20 Blitzkrieg0 wrote:
Show nested quote +
On April 04 2017 08:11 dsyxelic wrote:
On April 04 2017 08:09 Blitzkrieg0 wrote:
On April 04 2017 07:59 dsyxelic wrote:
On April 04 2017 07:43 Blitzkrieg0 wrote:
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns


It's more of a big company bureaucracy issue. There's a lot of moving parts to getting hardware for new employees and as an intern it isn't at the top of any ones list.

PS: Hardware that you can't use doesn't count.


I see, definitely encouraging to know this is commonplace.

Oh well I guess I am not one of the lucky ones haha. Hopefully it will be usable tomorrow.


I would suggest just talking to people. Building relationships is the most important thing you can do at an internship. Don't bother people if they're busy working on something, but throw yourself out there.


hm my full-time co-workers always seemed busy so it felt like I was bothering them. they were nice about it though. I just asked a few times during the day whether I can shadow someone or if anyone needs anything I can do done. they pretty much all ended up with like 'nah just hang on for a bit till we know what the heck we're doing with you'.
got along with my other interns pretty well tho. no problems there. thanks for the advice
TL/SKT
vik7
Profile Joined May 2009
United States227 Posts
April 04 2017 06:52 GMT
#17352
hey would any1 here be willing to show me how to use blizzards api for calling profile ladder statistics? I know there is websites already that do that But I want to learn how
NA player, go KT Flash, ST Life( ;( ) , IMMvp, EGJD, CMStorm Polt, SKT Rain, KT Zest, Bisu, RootherO, Stats and teamliqiud
Blisse
Profile Blog Joined July 2010
Canada3710 Posts
April 04 2017 07:08 GMT
#17353
On April 04 2017 09:12 dsyxelic wrote:
Show nested quote +
On April 04 2017 08:20 Blitzkrieg0 wrote:
On April 04 2017 08:11 dsyxelic wrote:
On April 04 2017 08:09 Blitzkrieg0 wrote:
On April 04 2017 07:59 dsyxelic wrote:
On April 04 2017 07:43 Blitzkrieg0 wrote:
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns


It's more of a big company bureaucracy issue. There's a lot of moving parts to getting hardware for new employees and as an intern it isn't at the top of any ones list.

PS: Hardware that you can't use doesn't count.


I see, definitely encouraging to know this is commonplace.

Oh well I guess I am not one of the lucky ones haha. Hopefully it will be usable tomorrow.


I would suggest just talking to people. Building relationships is the most important thing you can do at an internship. Don't bother people if they're busy working on something, but throw yourself out there.


hm my full-time co-workers always seemed busy so it felt like I was bothering them. they were nice about it though. I just asked a few times during the day whether I can shadow someone or if anyone needs anything I can do done. they pretty much all ended up with like 'nah just hang on for a bit till we know what the heck we're doing with you'.
got along with my other interns pretty well tho. no problems there. thanks for the advice


Something I've found useful is asking my coworkers what is the best and most non-intrusive way I can ask them for help if I need it, after I've made a reasonable attempt to solve it myself.

Communication is always key, but different people/coworkers have different styles, especially influenced by your workplace. Some coworkers wanted me to schedule a meeting via email, some were okay with Slack/Lync, others were happy if I tapped their back (though they'd ask for 1s time first), others were okay with just saying things out loud. I don't mind being bothered in any way, some others mind a whole lot. Everyone has their own quirks, that hopefully you'll start picking up on as you become more familiar with them. Directly asking can help speed that along.

I read a couple of lines before you edited your post, but in all honesty, it sucks that HR could mess up your placement like that, but if a team suddenly got a new intern they had no idea what to do with, unless the manager was super welcoming they'd probably have nothing ready for you either for a while.

Also I've been at big and small companies where the first week is basically a wash in terms of getting my computer and dev environment set up. It's not a big deal.
There is no one like you in the universe.
Acrofales
Profile Joined August 2010
Spain18215 Posts
April 04 2017 08:43 GMT
#17354
On April 04 2017 06:32 travis wrote:
Well, I am closer
but I am screwing something up

I went through expamples like you said and could see that it held true but it didn't feel like that brought me closer to the proof

anyways this is what I have now:

+ Show Spoiler +

a_n = 2a(floor of n/2) + 7n

which should be <= A*(n/2)log(n/2)+B(n/2)

we know this because the floor of n/2 is less than or equal to n/2

now comparing that right hand side against the original claim

((A*log(n/2)+B)*n) / 2 <= A*nlog(n) + Bn

divide everything by n and multiply both sides by 2

A*log(n/2)+B = 2A*log(n)+2B

subtract B

Alog(n/2) = 2Alog(n)+B

=

A(log(n)-1) = 2Alog(n)+B

=

Alog(n)-A = 2Alog(n)+B

this can't be right

where am I screwing up
math is hard lol
w/e I will take a break for a bit and come back maybe you will point some stuff out to me


edit: oh i left out 7n huh
well i gotta do dishes i will come back to this


edit: i found my errors and fixed them. i believed I have solved it.


I'm glad you solved it. The way I would approach this is thus:
+ Show Spoiler +

For n sufficiently large:

a_n = 2a_(floor of n/2) + 7n
a_n = 2(2a_(floor of n/4) + 7(n/2)) + 7n
a_n <= 2^(log n)*300 + 7 * log(n) *n <--- money step, if you got here, you're set.

Let A=7 and B=300, then

Basic step:

a_2 = 40 < 7*2*1 + 300*2
a_3 = 300 < 7*3*log3 + 300*3

Inductive step

Let a_k ≤ 7*k*log(k) + 300*k

Then:

a_(k+1) = 2a_(floor of (k +1)/2) + 7(k +1)

If k+1 odd:

a_(k+1) = 2a_(k/2) + 7k + 7
a_(k+1) <= 7*k*log(k) + 300*k + 7
a_(k+1) < 7*(k+1)*log(k+1) + 300*(k+1)
QED

If k+1 even

a_(k+1) <= 2^(log(k+1))*300 + 7 * log(k+1) *(k+1) (money step above)
QED

The money step is a bit poorly explained, but is essentially derived from the Taylor expansion of log(n). You should know it from complexity calculations on binary trees.

Wrath
Profile Blog Joined July 2014
3174 Posts
April 04 2017 19:20 GMT
#17355
Hey guys, I'm toying around on hackerrank these days and I got this problem:

https://www.hackerrank.com/challenges/kangaroo

I'm thinking that brute force is not really an option as it goes to infinity. As alternative, I'm considering it a problem similar to finding a tangent between two lines. Basically writing an equation like this:

v1p+x1 = v2p+x2 where p is a variable.

Issue is not sure how progress from there, never know how to solve equations in a programming language.

Thoughts?
frogmelter
Profile Blog Joined April 2009
United States971 Posts
Last Edited: 2017-04-05 06:41:20
April 04 2017 20:11 GMT
#17356
On April 05 2017 04:20 Wrath wrote:
Hey guys, I'm toying around on hackerrank these days and I got this problem:

https://www.hackerrank.com/challenges/kangaroo

I'm thinking that brute force is not really an option as it goes to infinity. As alternative, I'm considering it a problem similar to finding a tangent between two lines. Basically writing an equation like this:

v1p+x1 = v2p+x2 where p is a variable.

Issue is not sure how progress from there, never know how to solve equations in a programming language.

Thoughts?


What is actually important in the question is the difference between the starting positions and the difference in rate.

I believe that if | v1p - v2p | % | x1 - x2 | == 0, then then they will eventually overlap. Otherwise, they won't.

In plainer English, if you find the distance between two points [let's call this Y] and at every hop it decreases by X amount, if X goes into Y evenly, they will eventually overlap in Y/X steps. Since we don't really care how many hops it takes, you can probably see if there is a remainder.
TL+ Member
Deleted User 3420
Profile Blog Joined May 2003
24492 Posts
Last Edited: 2017-04-04 21:24:08
April 04 2017 20:13 GMT
#17357
If the kangaroo that is further back takes a bigger jump, then each iteration brings that kangaroo closer to the other by an amount that is the difference between the two jumps. If you use this information then there is just one more step to having a fairly simple solution.
dsyxelic
Profile Joined May 2010
United States1417 Posts
April 05 2017 04:50 GMT
#17358
one of my test cases failing because of run time. looks like naiive solution won't work haha but too sleepy to think about it deeper

print no if v2 > v1
elif print yes if (x2-x1)%(v1-v2)==0 // if you divide instead you get the # of iterations it takes to overlap
else print no

@2 posts above me, think you forgot to change to subtraction. you did mention difference of starting position in your post so looks like a typo.

On April 04 2017 16:08 Blisse wrote:
Show nested quote +
On April 04 2017 09:12 dsyxelic wrote:
On April 04 2017 08:20 Blitzkrieg0 wrote:
On April 04 2017 08:11 dsyxelic wrote:
On April 04 2017 08:09 Blitzkrieg0 wrote:
On April 04 2017 07:59 dsyxelic wrote:
On April 04 2017 07:43 Blitzkrieg0 wrote:
On April 04 2017 07:15 dsyxelic wrote:
-concern about first day of internship doing absolutely jack and no one knowing what to do with me-

edit: nvm apparently this is normal looking through reddit.


That is very normal. If you have hardware on your desk already consider it a blessing.


I do have a computer but definitely not usable yet haha.

I guess only the really prestigious companies are on top of these things? or am I overrating them as well on how prepared they are for interns


It's more of a big company bureaucracy issue. There's a lot of moving parts to getting hardware for new employees and as an intern it isn't at the top of any ones list.

PS: Hardware that you can't use doesn't count.


I see, definitely encouraging to know this is commonplace.

Oh well I guess I am not one of the lucky ones haha. Hopefully it will be usable tomorrow.


I would suggest just talking to people. Building relationships is the most important thing you can do at an internship. Don't bother people if they're busy working on something, but throw yourself out there.


hm my full-time co-workers always seemed busy so it felt like I was bothering them. they were nice about it though. I just asked a few times during the day whether I can shadow someone or if anyone needs anything I can do done. they pretty much all ended up with like 'nah just hang on for a bit till we know what the heck we're doing with you'.
got along with my other interns pretty well tho. no problems there. thanks for the advice


Something I've found useful is asking my coworkers what is the best and most non-intrusive way I can ask them for help if I need it, after I've made a reasonable attempt to solve it myself.

Communication is always key, but different people/coworkers have different styles, especially influenced by your workplace. Some coworkers wanted me to schedule a meeting via email, some were okay with Slack/Lync, others were happy if I tapped their back (though they'd ask for 1s time first), others were okay with just saying things out loud. I don't mind being bothered in any way, some others mind a whole lot. Everyone has their own quirks, that hopefully you'll start picking up on as you become more familiar with them. Directly asking can help speed that along.

I read a couple of lines before you edited your post, but in all honesty, it sucks that HR could mess up your placement like that, but if a team suddenly got a new intern they had no idea what to do with, unless the manager was super welcoming they'd probably have nothing ready for you either for a while.

Also I've been at big and small companies where the first week is basically a wash in terms of getting my computer and dev environment set up. It's not a big deal.


+ Show Spoiler +
thanks, it's definitely a bit difficult to navigate the workplace as a new intern. still haven't got my desk set up lol.
was navigating through our project and found a couple of bugs, most with easy fixes and my supervisor told me to send it to the project head when he passed by and asked me what I was up to. So I did and immediately the head came over and seemed almost upset (think I may have seemed like overstepping as a new intern on the 2nd day) and kinda gave me a mini lecture on how the parts I found bugs weren't under their department. Not my fault though, my superior didnt know either and told me to send it. Anyways I managed to calmly explain myself and eventually the guy was a lot nicer and said he'd report one of the bigger bugs I found and introduced me to some more of the codebase. So all in all ended up pretty well but was pretty scary for a bit hah. Maybe I should take it slower.. I was getting deathly bored though reading through endless tutorials and documentation on a lab pc.
TL/SKT
Wrath
Profile Blog Joined July 2014
3174 Posts
April 05 2017 05:12 GMT
#17359
Thanks guys.

I understand the idea that k1 is getting closer to k2 each iteration by v1-v2 steps. But not sure what the x1+x2 represent here. What is the summation of the starting point for each Kangaroo should represent?
slmw
Profile Blog Joined October 2010
Finland233 Posts
April 05 2017 06:00 GMT
#17360
Just solve the point where the kangaroos would meet (if they do) by yourself. You said you don't know how to solve equations by programming. Do it on paper first and then do it by programming? Should be rather clear once you work out the equation on paper.
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