|
On October 21 2012 22:36 GhostLink wrote:Show nested quote +On October 21 2012 22:33 Grumbels wrote:
This is really silly, you can't start out by excluding the number one. MVP had his first championship in his first finals. One is not a prime number, therefore your theory doesn't work. But neither do all of the current proposed theories to finding the solution the the prime number questions that have been puzzling mathematicians for centuries. Maybe it's time to take a fresh new approach, and Mvp has found a solution, by excluding the number 1 from the equation.
All we know for sure is that he's not perfect
|
Pretty sure you have this wrong, prime numbers are MVP numbers.
|
On October 21 2012 22:38 eieio wrote:
Pretty sure you have this wrong, prime numbers are MVP numbers.
:D
That will be what they'll be called after Mvp revolutionizes and redefines them. 100 years from now, kids in school will be studying Mvp numbers.
|
wow, not a coincidence at all that theres a tonne of prime numbers from 1- 10.... wtf is this thread
|
I'm waiting for the day we get a Fibonacci Protoss
|
On October 21 2012 22:41 GhostLink wrote:Show nested quote +On October 21 2012 22:38 eieio wrote:
Pretty sure you have this wrong, prime numbers are MVP numbers. :D That will be what they'll be called after Mvp revolutionizes and redefines them. 100 years from now, kids in school will be studying Mvp numbers.
hahahaha, "these are the nestea numbers cause they're consistent, these are the MVP numbers cause they just keep increasing"
seriously though this thread cracked me up, nice post.
|
Haha thats a funny coincidence xD
|
now: prove that MVP will win infinitely many gsl titles!
|
On October 21 2012 22:30 wozzot wrote:
You're Mersenne around with us, aren't you
afFermative !
|
That's propably the best conspiracy theory I've read in a while 
|
On October 21 2012 22:52 JustPassingBy wrote:
now: prove that MVP will win infinitely many gsl titles!
Corollary. MVP will win an infinite number of GSLs.
Proof. Suppose that GSL2, GSL3, GSL5, GSL7, ..., GSLr are all of the GSLs MVP will win. Let q = (2*3*5*7...*r)+1 and let p be a prime GSL number dividing q. Then GSLp cannot be any of GSL2, GSL3, GSL5, GSL7, ..., GSLr, as otherwise p would divide the difference q-(2*3*5*7...*r) = 1, which is impossible. Therefore, GSLp must be another GSL that MVP will win. Q.E.D.
|
On October 21 2012 23:02 Dayrlan wrote:Show nested quote +On October 21 2012 22:52 JustPassingBy wrote:
now: prove that MVP will win infinitely many gsl titles! Corollary. MVP will win an infinite number of GSLs.Proof. Suppose that GSL2, GSL3, GSL5, GSL7, ..., GSLr are all of the GSLs MVP will win. Let q = (2*3*5*7...*r)+1 and let p be a prime GSL number dividing q. Then GSLp cannot be any of GSL2, GSL3, GSL5, GSL7, ..., GSLr, as otherwise p would divide the difference q-(2*3*5*7...*r) = 1, which is impossible. Therefore, GSLp must be another GSL that MVP will win. Q.E.D.
....................................wut?
|
On October 21 2012 23:05 Clazziquai10 wrote:Show nested quote +On October 21 2012 23:02 Dayrlan wrote:On October 21 2012 22:52 JustPassingBy wrote:
now: prove that MVP will win infinitely many gsl titles! Corollary. MVP will win an infinite number of GSLs.Proof. Suppose that GSL2, GSL3, GSL5, GSL7, ..., GSLr are all of the GSLs MVP will win. Let q = (2*3*5*7...*r)+1 and let p be a prime GSL number dividing q. Then GSLp cannot be any of GSL2, GSL3, GSL5, GSL7, ..., GSLr, as otherwise p would divide the difference q-(2*3*5*7...*r) = 1, which is impossible. Therefore, GSLp must be another GSL that MVP will win. Q.E.D. ....................................wut?
Day[9] would appreciate it. :>
|
your Country52797 Posts
On October 21 2012 23:02 Dayrlan wrote:Show nested quote +On October 21 2012 22:52 JustPassingBy wrote:
now: prove that MVP will win infinitely many gsl titles! Corollary. MVP will win an infinite number of GSLs.Proof. Suppose that GSL2, GSL3, GSL5, GSL7, ..., GSLr are all of the GSLs MVP will win. Let q = (2*3*5*7...*r)+1 and let p be a prime GSL number dividing q. Then GSLp cannot be any of GSL2, GSL3, GSL5, GSL7, ..., GSLr, as otherwise p would divide the difference q-(2*3*5*7...*r) = 1, which is impossible. Therefore, GSLp must be another GSL that MVP will win. Q.E.D.
I laughed pretty hard :D
But this also proves that SC2 will never die, it will last for an infinite amount of time :o
|
On October 21 2012 22:08 Alejandrisha wrote:Show nested quote +On October 21 2012 22:00 GhostLink wrote:
Mvp will lose the next 4 finals, unfortunately. Then he will win 6 championships on his 11th final. tall order for one man, even mvp
MVP is no man.
|
..finding prime numbers is a problem resolved like 2100 years ago; a bit precise formulation is how to find them in a polynomial time, which is at this time unknown.
|
On October 21 2012 23:02 Dayrlan wrote:Show nested quote +On October 21 2012 22:52 JustPassingBy wrote:
now: prove that MVP will win infinitely many gsl titles! Corollary. MVP will win an infinite number of GSLs.Proof. Suppose that GSL2, GSL3, GSL5, GSL7, ..., GSLr are all of the GSLs MVP will win. Let q = (2*3*5*7...*r)+1 and let p be a prime GSL number dividing q. Then GSLp cannot be any of GSL2, GSL3, GSL5, GSL7, ..., GSLr, as otherwise p would divide the difference q-(2*3*5*7...*r) = 1, which is impossible. Therefore, GSLp must be another GSL that MVP will win. Q.E.D.
Well, there we have it!
LOL btw :D thank you so much for this post
Can i include this in the OP?
|
If he loses the next four finals after winning the 7th one, wouldn't that include losing his 11th final?
|
On October 21 2012 23:37 bLo0d wrote:
If he loses the next four finals after winning the 7th one, wouldn't that include losing his 11th final?
.... Corrected, haha thanks.
|
You're wrong. Mvp isn't a prime player. Primes are mvp numbers.
|
|
|
|
|
|
EPT
