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On November 21 2004 20:41 seeyoulater wrote:Show nested quote +On November 21 2004 20:36 baal wrote:On November 21 2004 20:24 LTT wrote:
I don't want to go through the calculations, but it's obviously based on the time delay. Like for the monk puzzle, assuming the monks are smart, say that there are 5 monks 3 of which have red eyes. So each monk with red eyes sees two other monks with red eyes. After two midnights of no suicides, all three monks will commit suicide. they dont know how many have red eyes -_- duh! The tourist says at least one of you has red eyes. The 1 guy that has red eyes will look around, see everyone else's brown eyes, and kill himself. If there are 2, one of the people with red eyes will see the other guy with red eyes and assume that he can come up with the same reasoning above to kill himself the first night. If he didn't kill himself, that means he has red eyes as well. So on to infinity.
And if this same reasoning is applied to the 1st question, the answer is 6 guys are hanged. (edit hung to hanged)
If only 1 guy is committing adultrey, his wife will observe and see that no one else has been cheating when the king has said that some men were unfaithful. She will know it was her man, etc.
If a woman has a loyal husband, she will have seen 6 men cheating, if her husband was not loyal, she will have seen 5 men cheating, and they would automatically come forward.
Assuming the women are retarded.
And it is 6 or 7. I don't know if I should count day 0 ;o
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dude...you could have given somebody else a chance.
And what's the answer to the jungle explorer one?
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On November 21 2004 20:46 gg_hertzz wrote:
dude...you could have given somebody else a chance.
And what's the answer to the jungle explorer one?
you're right, i'll edit it so you don't have to look unless you want to.
the guy who replied right away was correct, the answer was "i will be eaten by lions"
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On November 21 2004 20:41 seeyoulater wrote:Show nested quote +On November 21 2004 20:36 baal wrote:On November 21 2004 20:24 LTT wrote:
I don't want to go through the calculations, but it's obviously based on the time delay. Like for the monk puzzle, assuming the monks are smart, say that there are 5 monks 3 of which have red eyes. So each monk with red eyes sees two other monks with red eyes. After two midnights of no suicides, all three monks will commit suicide. they dont know how many have red eyes -_- duh! The tourist says at least one of you has red eyes. The 1 guy that has red eyes will look around, see everyone else's brown eyes, and kill himself. If there are 2, one of the people with red eyes will see the other guy with red eyes and assume that he can come up with the same reasoning above to kill himself the first night. If he didn't kill himself, that means he has red eyes as well. So on to infinity.
Given what you've said..
Then is there anyway to relate it to.. Only till the 7th day, do people finally commit suicide??
Opps.. Just saw another post about it..
Thinking now..
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famouzze - isn't that the same as the riddle where there are 3 doors (one has mega cash prize behind it)? then you choose one door and the host shows you one of the three doors and it's empty and asks if you would like to switch to the other door. then do you change or not and why?
it's 2/3 there as well (if you switch you have better chance).
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yah, thats what i think is the hardest, even though its the same concept. i love those two....i know so many ppl who refuse to believe its 2/3 and not 1/2 lol
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On November 21 2004 20:50 Famouzze wrote:
yah, thats what i think is the hardest, even though its the same concept. i love those two....i know so many ppl who refuse to believe its 2/3 and not 1/2 lol
I have understood the door riddle since the 1st time reading it, but yours doesn't make any sense. You don't know the gender of either child going in. If you had said "The woman has 2 children, and she has told you that at least one of them is a girl." That would make more sense.
But from your riddle, I would call it 50/50, unless you want to include genetics or some bs
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can u explain it in more detail famouzze?
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So you now know one of her children is a girl, what are the chances that the other child is a boy?
Actually, from your wording it does seem 50/50.
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it is 50/50.. because the gender of the first child doesn't affect if the Y sperm or the X sperm gets to the egg on the second time around -_-
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sure, it's very counter-intuitive so here's the explanation. the mother has 2 children, with four possible and equally likely gender outcomes: two girls (GG), one girl then one boy (GB), one boy then one girl (BG), or two boys (BB). if you know one of the children is a girl, then that eliminates the possibility of BB. the 3 other possiblities remain, each equally likely :D.
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actually, famouzze is right. That's a pretty good one.
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ah.. now I see.. the other sibling can be younger or older..
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On November 21 2004 20:25 travis wrote:Show nested quote +On November 21 2004 20:24 LTT wrote:
I don't want to go through the calculations, but it's obviously based on the time delay. Like for the monk puzzle, assuming the monks are smart, say that there are 5 monks 3 of which have red eyes. So each monk with red eyes sees two other monks with red eyes. After two midnights of no suicides, all three monks will commit suicide. that doesnt make any sense or maybe i just don't understand?
Think of it like this. To any of the three red eyed monks, they don't know what color eyes they have. So to them, there are either 2 or 3 red eyed monks. After the first night, no one commits suicide because each red eyed monk can see another red eyed monk. Forget the above scenario for one second. Imagine that there are only 2 red eyed monks, they wouldn't suicide on the first night, but since the other monk didn't suicide and they only see other browns, they each know they have red eyes and suicide on the second night. Back to the case of 3 monks, after the second night, each monk now knows that there are at least 3 monks with red eyes, otherwise the other two would have figured it out and suicided like the side example above. So on the third night, all three red eyed monks suicide.
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wow that is a really good riddle +_+
the girl/boy one
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ltt and I should nuke our posts so lostdesire can return to his class with the theory of gay butt sex
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Valhalla18444 Posts
On November 21 2004 20:58 Famouzze wrote:
sure, it's very counter-intuitive so here's the explanation. the mother has 2 children, with four possible and equally likely gender outcomes: two girls (GG), one girl then one boy (GB), one boy then one girl (BG), or two boys (BB). if you know one of the children is a girl, then that eliminates the possibility of BB. the 3 other possiblities remain, each equally likely :D.
if you dont know which of the two children is older, GB and BG are the same thing
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On November 21 2004 21:06 LTT wrote:Show nested quote +On November 21 2004 20:25 travis wrote:On November 21 2004 20:24 LTT wrote:
I don't want to go through the calculations, but it's obviously based on the time delay. Like for the monk puzzle, assuming the monks are smart, say that there are 5 monks 3 of which have red eyes. So each monk with red eyes sees two other monks with red eyes. After two midnights of no suicides, all three monks will commit suicide. that doesnt make any sense or maybe i just don't understand? Think of it like this. To any of the three red eyed monks, they don't know what color eyes they have. So to them, there are either 2 or 3 red eyed monks. After the first night, no one commits suicide because each red eyed monk can see another red eyed monk. Forget the above scenario for one second. Imagine that there are only 2 red eyed monks, they wouldn't suicide on the first night, but since the other monk didn't suicide and they only see other browns, they each know they have red eyes and suicide on the second night. Back to the case of 3 monks, after the second night, each monk now knows that there are at least 3 monks with red eyes, otherwise the other two would have figured it out and suicided like the side example above. So on the third night, all three red eyed monks suicide.
yea but none of the brown eyed monks know they have brown eyes so there is a possibility that one of them commits suicide by accident...?
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On November 21 2004 21:10 Meta wrote:Show nested quote +On November 21 2004 21:06 LTT wrote:On November 21 2004 20:25 travis wrote:On November 21 2004 20:24 LTT wrote:
I don't want to go through the calculations, but it's obviously based on the time delay. Like for the monk puzzle, assuming the monks are smart, say that there are 5 monks 3 of which have red eyes. So each monk with red eyes sees two other monks with red eyes. After two midnights of no suicides, all three monks will commit suicide. that doesnt make any sense or maybe i just don't understand? Think of it like this. To any of the three red eyed monks, they don't know what color eyes they have. So to them, there are either 2 or 3 red eyed monks. After the first night, no one commits suicide because each red eyed monk can see another red eyed monk. Forget the above scenario for one second. Imagine that there are only 2 red eyed monks, they wouldn't suicide on the first night, but since the other monk didn't suicide and they only see other browns, they each know they have red eyes and suicide on the second night. Back to the case of 3 monks, after the second night, each monk now knows that there are at least 3 monks with red eyes, otherwise the other two would have figured it out and suicided like the side example above. So on the third night, all three red eyed monks suicide. yea but none of the brown eyed monks know they have brown eyes so there is a possibility that one of them commits suicide by accident...?
If you include the possibility of the monks commiting suicide without certainty, this is a waste of time.
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EPT
