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[H] Calc I

Blogs > Rev0lution
Post a Reply
Rev0lution
Profile Blog Joined August 2007
United States1805 Posts
Last Edited: 2008-10-16 14:46:37
October 16 2008 14:45 GMT
#1
I forgot how to do this and I dont have my calc book with me if anyone can give me a bump in the right direction??

Consider e^(Cos(x))^4 thats e to cos x to the 4th btw

Differentiate completely:

EDIT: also could you NOT do it in dy/dx du/dx form cuz that just confuses. me lol.....

*****
My dealer is my best friend, and we don't even chill.
kpcrew
Profile Blog Joined December 2007
Korea (South)1071 Posts
October 16 2008 14:46 GMT
#2
could have sworn it was outer * derivative of inner + inner * derivative of outer
Clan Lzuruha
micronesia
Profile Blog Joined July 2006
United States24667 Posts
Last Edited: 2008-10-16 14:53:13
October 16 2008 14:52 GMT
#3
On October 16 2008 23:46 kpcrew wrote:
could have sworn it was outer * derivative of inner + inner * derivative of outer

This looks like the product rule which is not what this is. More like the chain rule.

do you mean [e^(cos(x)]^4
ModeratorThere are animal crackers for people and there are people crackers for animals.
Rev0lution
Profile Blog Joined August 2007
United States1805 Posts
October 16 2008 14:54 GMT
#4
Yes I think thats it. Excuse my bad writing of functions.
My dealer is my best friend, and we don't even chill.
micronesia
Profile Blog Joined July 2006
United States24667 Posts
Last Edited: 2008-10-16 14:57:31
October 16 2008 14:56 GMT
#5
The derivitive of [f(x)]^4 should be 4*[f(x)]^3*df/dx(x)

in this case df/dx is -sin(x)*e^cos(x)
ModeratorThere are animal crackers for people and there are people crackers for animals.
Rev0lution
Profile Blog Joined August 2007
United States1805 Posts
Last Edited: 2008-10-16 15:13:43
October 16 2008 15:02 GMT
#6
nvm i got it ^^
My dealer is my best friend, and we don't even chill.
micronesia
Profile Blog Joined July 2006
United States24667 Posts
October 16 2008 15:51 GMT
#7
As in you figured it out on your own in the meantime, or as in you looked at my work and it made sense?
ModeratorThere are animal crackers for people and there are people crackers for animals.
BlackStar
Profile Blog Joined July 2007
Netherlands3029 Posts
Last Edited: 2008-10-16 16:14:28
October 16 2008 16:11 GMT
#8
Chain rule, http://en.wikipedia.org/wiki/Chain_rule.

Derivative of [u(x)]^4 is 4[u(x)]^3 times the derivative of u(x)

So:

f(x)=[e^(cos(x)]^4
f'(x)=4[e^(cos(x)]^3 * [e^(cos(x)]'
f'(x)=4[e^(cos(x)]^3 * -sin(x)[e^(cos(x)]

Be sure you remember what is the derivative of e^u(x).


No need to be confused by dy/dx = dy/du * du/dx and stuff like that. Know the derivative operators. No real math involved here. Just remember the symbols eventhough there are several with the same meaning.

could have sworn it was outer * derivative of inner + inner * derivative of outer


Yes, product rule confusing. (f*g)' = f*g' + f'*g
inlagdsil
Profile Joined May 2008
Canada957 Posts
October 16 2008 19:11 GMT
#9
On October 16 2008 23:45 Rev0lution wrote:
I forgot how to do this and I dont have my calc book with me if anyone can give me a bump in the right direction??

Consider e^(Cos(x))^4 thats e to cos x to the 4th btw

Differentiate completely:

EDIT: also could you NOT do it in dy/dx du/dx form cuz that just confuses. me lol.....

In the beginning I found dy/dx form confusing but as you go on in math it will make sense and in fact be less confusing.
Example: f = 35x+27y-3z, WTF is f ' ??
There is nothing cuter than a zergling when it has just started taking crack
Mastermind
Profile Blog Joined April 2008
Canada7096 Posts
October 16 2008 20:54 GMT
#10
On October 17 2008 04:11 inlagdsil wrote:
Show nested quote +
On October 16 2008 23:45 Rev0lution wrote:
I forgot how to do this and I dont have my calc book with me if anyone can give me a bump in the right direction??

Consider e^(Cos(x))^4 thats e to cos x to the 4th btw

Differentiate completely:

EDIT: also could you NOT do it in dy/dx du/dx form cuz that just confuses. me lol.....

In the beginning I found dy/dx form confusing but as you go on in math it will make sense and in fact be less confusing.
Example: f = 35x+27y-3z, WTF is f ' ??

In that case it doesnt make sense to ask what f' is. There is no single derivative. You could ask what is the partial derivative with respect to x or y or z, but to just ask for a derivative makes no sense. Unless of course 2 of those symbols are actually constants and not variables, but I assume you meant for all 3 to be variables.
HeavOnEarth
Profile Blog Joined March 2008
United States7087 Posts
Last Edited: 2008-10-17 18:22:43
October 17 2008 18:17 GMT
#11
the algebra in calculus is harder than the actual calculus imo =/
"come korea next time... FXO house... 10 korean, 10 korean"
Ecael
Profile Joined February 2008
United States6703 Posts
October 17 2008 20:31 GMT
#12
On October 18 2008 03:17 HeavOnEarth wrote:
the algebra in calculus is harder than the actual calculus imo =/

Amen to that, addition and division is way harder than calculus. At times I wonder why we teach math the way we do.
HeavOnEarth
Profile Blog Joined March 2008
United States7087 Posts
Last Edited: 2008-10-19 01:24:06
October 19 2008 01:23 GMT
#13
On October 18 2008 05:31 Ecael wrote:
Show nested quote +
On October 18 2008 03:17 HeavOnEarth wrote:
the algebra in calculus is harder than the actual calculus imo =/

Amen to that, addition and division is way harder than calculus. At times I wonder why we teach math the way we do.

usa is quickly falling so far behind in math and science
"come korea next time... FXO house... 10 korean, 10 korean"
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