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@ zerg legend
I simply meant that my previous elimination method would not work, but on my rethink I went down a totally different track. As for your follow up question, I don't recall it, I'll have to go back and see, and then perhaps tomorrow when I'm free for a bit again (: I enjoyed the riddle though!
edit:
Went back and the only follow up question I can see is whether the ball is heavier or lighter, which I did mention in the solution I posted 
+ Show Spoiler +If it's the codes I picked, it's heavier, or if it's the "reciprocal" code then it's lighter.
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On March 16 2009 00:35 EffOrt wrote:
A man went on a trip with a fox, a goose and a sack of corn. He came upon a stream which he had to cross and found a tiny boat to use to cross the stream. He could only take himself and one other - the fox, the goose, or the corn - at a time. He could not leave the fox alone with the goose or the goose alone with the corn. How does he get all safely over the stream?
Well first of all... what is a farmer doing with a fox? A fox is a farmers worse nightmare, he should just drown the fox and take the other two.
If he really must keep the fox then he should just put the grain on a wall while he takes the fox.
Or he could just get his wife to help him? Unless he's gay of course, in which case he shouldn't be working with animals anyway!
+ Show Spoiler +
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Four people want to cross a river. Whole thing happens at night and they have only one flashlight. The bridge is very narrow and shaky, thus only two people (with the flashlight) could walk simultaneously over it. Each person is able to cross it the in different time: 1 minute, 2 minutes, 5 minutes and 10 minutes, respectively. What is the minimal time for all of them to cross the river?
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On March 17 2009 09:03 myzael wrote:
Four people want to cross a river. Whole thing happens at night and they have only one flashlight. The bridge is very narrow and shaky, thus only two people (with the flashlight) could walk simultaneously over it. Each person is able to cross it the in different time: 1 minute, 2 minutes, 5 minutes and 10 minutes, respectively. What is the minimal time for all of them to cross the river?
+ Show Spoiler +
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On March 17 2009 09:03 myzael wrote:
Four people want to cross a river. Whole thing happens at night and they have only one flashlight. The bridge is very narrow and shaky, thus only two people (with the flashlight) could walk simultaneously over it. Each person is able to cross it the in different time: 1 minute, 2 minutes, 5 minutes and 10 minutes, respectively. What is the minimal time for all of them to cross the river?
+ Show Spoiler + 17 min: 1 and 2 cross, 1 comes back, 5 and 10 cross, 2 comes back, 1 and 2 cross: 2+1+10+2+2 = 17
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On March 17 2009 09:10 SickTighT wrote:Show nested quote +On March 17 2009 09:03 myzael wrote:
Four people want to cross a river. Whole thing happens at night and they have only one flashlight. The bridge is very narrow and shaky, thus only two people (with the flashlight) could walk simultaneously over it. Each person is able to cross it the in different time: 1 minute, 2 minutes, 5 minutes and 10 minutes, respectively. What is the minimal time for all of them to cross the river? + Show Spoiler +
+ Show Spoiler +I'd go with 20 minutes unless im misreading the problem or just being stupid
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l10f
United States3241 Posts
On March 17 2009 09:32 pSikh0 wrote:Show nested quote +On March 17 2009 09:10 SickTighT wrote:On March 17 2009 09:03 myzael wrote:
Four people want to cross a river. Whole thing happens at night and they have only one flashlight. The bridge is very narrow and shaky, thus only two people (with the flashlight) could walk simultaneously over it. Each person is able to cross it the in different time: 1 minute, 2 minutes, 5 minutes and 10 minutes, respectively. What is the minimal time for all of them to cross the river? + Show Spoiler + + Show Spoiler +I'd go with 20 minutes unless im misreading the problem or just being stupid
sigh its
+ Show Spoiler +17 minutes.
1minute and 2 minutes go = 2 minutes
2 minute comes back = 4 minutes
10 minutes and 5 minutes go = 14 minutes
1 minute comes back = 15 minutes
1 minute and 2 minutes go = 17 minutes
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There are 100 prisoners in solitary cells. There's a central living room with one light bulb; this bulb is initially off. No prisoner can see the light bulb from his or her own cell. Everyday, the warden picks a prisoner equally at random, and that prisoner visits the living room. While there, the prisoner can toggle the bulb if he or she wishes. Also, the prisoner has the option of asserting that all 100 prisoners have been to the living room by now. If this assertion is false, all 100 prisoners are shot. However, if it is indeed true, all prisoners are set free and inducted into MENSA, since the world could always use more smart people. Thus, the assertion should only be made if the prisoner is 100% certain of its validity. The prisoners are allowed to get together one night in the courtyard, to discuss a plan. What plan should they agree on, so that eventually, someone will make a correct assertion?
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Can prisoners be chosen randomly more than once?
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Prisoners know how many days are passing as well, correct?
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On March 17 2009 10:46 terr13 wrote:
There are 100 prisoners in solitary cells. There's a central living room with one light bulb; this bulb is initially off. No prisoner can see the light bulb from his or her own cell. Everyday, the warden picks a prisoner equally at random, and that prisoner visits the living room. While there, the prisoner can toggle the bulb if he or she wishes. Also, the prisoner has the option of asserting that all 100 prisoners have been to the living room by now. If this assertion is false, all 100 prisoners are shot. However, if it is indeed true, all prisoners are set free and inducted into MENSA, since the world could always use more smart people. Thus, the assertion should only be made if the prisoner is 100% certain of its validity. The prisoners are allowed to get together one night in the courtyard, to discuss a plan. What plan should they agree on, so that eventually, someone will make a correct assertion?
+ Show Spoiler +if the prisoner is going there for the first time, leave the light off. if he is there for the 2nd time, then turn it on. if a prisoner goes in there and sees it on and it's his first time, he turns it off. he knows that the person before him has been there. if a prisoner goes in there and sees it on and he's also been there before, leave it on. eventually, everyone will go in and see it on.
this is where im not sure what to do next. supposedly over time it will always be on, but i dont know how they can be 100% sure everyone has been in the room
maybe some one can take it from here
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On March 16 2009 13:50 Whyzguy wrote:Show nested quote +On March 16 2009 13:09 Tensai176 wrote:
A man is facedown in the middle of the dessert dead. If he had opened his knapsack he would have survived. What was in his backpack? + Show Spoiler +
Winnar!
There are three women. One is crying but could never be happier. The other two are smiling but could never be sadder. What is happening?
Another! A Taxi Driver is going the other way on a oneway street, however, The police do not stop him! Assuming that the cops are totally zealous in their line of duty, what is happenings?
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On March 17 2009 10:46 terr13 wrote:
There are 100 prisoners in solitary cells. There's a central living room with one light bulb; this bulb is initially off. No prisoner can see the light bulb from his or her own cell. Everyday, the warden picks a prisoner equally at random, and that prisoner visits the living room. While there, the prisoner can toggle the bulb if he or she wishes. Also, the prisoner has the option of asserting that all 100 prisoners have been to the living room by now. If this assertion is false, all 100 prisoners are shot. However, if it is indeed true, all prisoners are set free and inducted into MENSA, since the world could always use more smart people. Thus, the assertion should only be made if the prisoner is 100% certain of its validity. The prisoners are allowed to get together one night in the courtyard, to discuss a plan. What plan should they agree on, so that eventually, someone will make a correct assertion?
Well, I am working on this guy now. This is the lines I'm thinking a long:
The prisoners have two other important pieces of information they can keep track of:
The number of days that have passed.
Some sort of initial numbers they assign to themselves.
Using these 2 pieces of information I think we can get the solution
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example 1 of op could be 'a train/bus/ride/etc'.
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On March 17 2009 12:41 Tensai176 wrote:
Another! A Taxi Driver is going the other way on a oneway street, however, The police do not stop him! Assuming that the cops are totally zealous in their line of duty, what is happenings?
+ Show Spoiler +He's walking, not driving.
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United States7488 Posts
#1 When is a door not a door?
#2 You come to a fork in the road. You know that one direction leads to certain death while the other will provide safe passage. At this fork you know there is a pair of identical twins except that one of them will always tell the truth and the other will always tell a lie. You can only ask one twin one question before choosing which direction to go. What do you ask to ensure safe passage?
#3 People who are dead eat this, but if a living person eats this, they die. What is it?
#4 What always runs but has no feet; has a mouth but doesn't speak; has a bed but will never sleep; and has a head but cannot think?
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On March 17 2009 16:15 semioldguy wrote:
#3 People who are dead eat this, but if a living person eats this, they die. What is it?
+ Show Spoiler +
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EPT
