EPTThe answer isnt that obvious. Depending on the exact meaning it can have 2 answers. If were specificly looking at a game where always one of the games was zvz the answer would be 1/5. If we happen to stumble upon a game of zvz and then look at the other game the answer would be 1/3. Either way, not really that usefull to discuss over and over again.
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Marradron
Netherlands1586 Posts
The answer isnt that obvious. Depending on the exact meaning it can have 2 answers. If were specificly looking at a game where always one of the games was zvz the answer would be 1/5. If we happen to stumble upon a game of zvz and then look at the other game the answer would be 1/3. Either way, not really that usefull to discuss over and over again. | ||
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Llama
United Kingdom69 Posts
On June 10 2011 21:33 Tektos wrote: Or, there is the other question: "I played as Zerg at least once. What is the probability that my other game was as Zerg as well?" Played zerg at least once, so the possible outcomes are: ZZ ZT ZP TZ PZ Then "other game was zerg" if we take it as game 1 is the "other" game then the probability is 3/5. If you take it as game 2 is the "other" game then it is also 3/5. There is no 3/5 in here. The "other" refers to the game that is not already confirmed as zerg, not a random pick out of the two games. This is a simple failing of English comprehension on your part. | ||
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Tektos
Australia1321 Posts
On June 10 2011 21:41 Llama wrote: No, you're simply failing to understand the wording of the original question. There is no 3/5 in here. The "other" refers to the game that is not already confirmed as zerg, not a random pick out of the two games. This is a simple failing of English comprehension on your part. "The "other" refers to the game that is not already confirmed as zerg" So you are not CONFIRMING that one game is already zerg? Then it is 1/3 It is not a failing of English comprehension on my part, it is ambiguity and interpretation of the meaning of "OTHER". Hence why you wont ever see a real math problem worded using this use of "OTHER" due to the ambiguity. | ||
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aRRoSC2
Denmark241 Posts
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Llama
United Kingdom69 Posts
On June 10 2011 21:44 Tektos wrote: "The "other" refers to the game that is not already confirmed as zerg" So you are not CONFIRMING that one game is already zerg? Then it is 1/3 It is not a failing of English comprehension on my part, it is ambiguity and interpretation of the meaning of "OTHER". One game has already been confirmed as zerg. "I played as Zerg at least once". This confirms one game as zerg. There is no real ambiguity here. | ||
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tomnov
Israel148 Posts
explanation: there are 5 scenarios in witch at least one game was as Zerg: (first T, second Z) , (first P, second Z) , (first Z, second Z) , (first Z, second T) , (first Z, second P) in only one of those the other game is as Zerg as well, so the odds are 1 in 5 Q.E.D | ||
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Tektos
Australia1321 Posts
On June 10 2011 21:45 Llama wrote: One game has already been confirmed as zerg. "I played as Zerg at least once". This confirms one game as zerg. There is no real ambiguity here. "OTHER" Other than what? Other than the game already confirmed as zerg? IT IS INCREDIBLY AMBIGUOUS. Tell me please what the "OTHER" refers to and I will give you the probability. OP has given no indication of the starting point as to where the "OTHER" is based. On June 10 2011 21:47 tomnov wrote: it's 1/5! explanation: there are 5 scenarios in witch at least one game was as Zerg: (first T, second Z) , (first P, second Z) , (first Z, second Z) , (first Z, second T) , (first Z, second P) in only one of those the other game is as Zerg as well, so the odds are 1 in 5 Q.E.D So you're implying that the original game to what the "OTHER" is based off is indeed confirmed to be a zerg sample. That is your interpretation of the word other. Given that interpretation, yes 1/5 is correct. | ||
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Llama
United Kingdom69 Posts
On June 10 2011 21:50 Tektos wrote: "OTHER" Other than what? Other than the game already confirmed as zerg? IT IS INCREDIBLY AMBIGUOUS. Tell me please what the "OTHER" refers to and I will give you the probability. OP has given no indication of the starting point as to where the "OTHER" is based. How can it refer to anything else? "At least one game is zerg, what is the other?" How can you interpret other as anything else? I don't understand. There are only two elements in this question. One has been identified and the asker is now asking for the other. Where is the ambiguity? | ||
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Tektos
Australia1321 Posts
On June 10 2011 21:54 Llama wrote: How can it refer to anything else? "At least one game is zerg, what is the other?" How can you interpret other as anything else? I don't understand. There are only two elements in this question. One has been identified and the asker is now asking for the other. Where is the ambiguity? "at least one game" is not a starting position for a reference of the word OTHER. If you're implying that at least one game is zerg, given that you choose that game which is zerg what is the probability of the other game being zerg. THEN IT WOULD BE 1/3. It is incredibly ambiguous. At least one game is zerg, you're choose that game and then looking at the other game to that one zerg game? The "at least one zerg" condition is already fulfilled so there is no dependence on that constraint for the other game that you choose hence it being 1/3. Answer this: Both games are zerg. What is the "OTHER" game. | ||
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Llama
United Kingdom69 Posts
vv Damn I forgot about that haha, pretty unambiguous | ||
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aRRoSC2
Denmark241 Posts
I played as Zerg at least once. What is the probability that my other game was as Zerg as well? You see that "as well" at the end? Or do you just randomly pick what words of the OP you want to read and completely disregard those you don't like? | ||
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Tektos
Australia1321 Posts
On June 10 2011 21:59 aRRoSC2 wrote: I went to OP, opened the spoiler with original problem, and found this: I played as Zerg at least once. What is the probability that my other game was as Zerg as well? You see that "as well" at the end? Or do you just randomly pick what words of the OP you want to read and completely disregard those you don't like? By that logic it is 1/3 because you've chosen the zerg game, from that starting point you're asking what the OTHER game will be. You've already got at least 1 zerg game so that condition is fulfilled so your possibilities for the OTHER game are Z, T, P = 0.33333333333333333333333333333333333 | ||
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Dimagus
United States1004 Posts
On June 10 2011 22:02 Tektos wrote: By that logic it is 1/3 because you've chosen the zerg game, from that starting point you're asking what the OTHER game will be. You've already got at least 1 zerg game so that condition is fulfilled so your possibilities for the OTHER game are Z, T, P = 0.33333333333333333333333333333333333 This is "setting" the first game as the zerg and only looking at Z_ You completely ignore the possibility of _Z | ||
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DarkPlasmaBall
United States44362 Posts
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Tektos
Australia1321 Posts
On June 10 2011 22:03 Dimagus wrote: This is "setting" the first game as the zerg and only looking at Z_ You completely ignore the possibility of _Z No I'm not setting the FIRST game as zerg, I'm setting the game chosen at random as to which the "OTHER" positioning statement is based off. We're arguing semantics on an ambiguous statement. | ||
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DarkPlasmaBall
United States44362 Posts
On June 10 2011 22:03 Dimagus wrote: This is "setting" the first game as the zerg and only looking at Z_ You completely ignore the possibility of _Z This. In other words, "What's the probability of me ending up getting Zerg twice in two games if I'm a Random player, given the knowledge that I'll get Zerg at least once (doesn't have to be the first game)." ZT ZP ZZ TZ PZ 1 out of 5 Zerg choices give me double Zerg. Therefore, 1/5. QED ^^ | ||
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Dimagus
United States1004 Posts
On June 10 2011 22:04 Tektos wrote: No I'm not setting the FIRST game as zerg, I'm setting the game chosen at random as to which the "OTHER" positioning statement is based off. We're arguing semantics on an ambiguous statement. Both games have already occurred. You are arguing the position that only the first game has been determined and only look at the probability for the 2nd game. He could even show you the replay of a zerg game, but you don't know whether it was the first or the second that he played. | ||
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jlim
Spain943 Posts
it cannot be 1/3 cuz there's three races and zerg has already been played so it's either 1/4 or 1/5 but 1/4 is a pair number and there's 3 races, which is unpair so it's gotta be 1/5 not the most efficient nor accurate thinking process, but i earn success nevertheless  and i'm an arts student! | ||
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Fenrax
United States5018 Posts
He defines one game as vs. Zerg and then asks for the probability of the other game while referencing to the Zerg game. | ||
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Tektos
Australia1321 Posts
On June 10 2011 22:07 DarkPlasmaBall wrote: In other words, "What's the probability of me ending up getting Zerg twice in two games if I'm a Random player, given the knowledge that I'll get Zerg at least once (doesn't have to be the first game)." That is a different question to "What is the probability of the other game being zerg" though. Answering the question you stated, then yes you are correct with your math. | ||
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