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Thread Rules 1. This is not a "do my homework for me" thread. If you have specific questions, ask, but don't post an assignment or homework problem and expect an exact solution. 2. No recruiting for your cockamamie projects (you won't replace facebook with 3 dudes you found on the internet and $20) 3. If you can't articulate why a language is bad, don't start slinging shit about it. Just remember that nothing is worse than making CSS IE6 compatible. 4. Use [code] tags to format code blocks. |
I'm wondering if anyone has a idea for a novice program with objects in java, i've currently finished three programs for my programming course which has to include your own made objects but i can't think of what to do for the last program. I'd be thankful if anyone could just throw me a idea!
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On December 10 2012 09:47 omarsito wrote: I'm wondering if anyone has a idea for a novice program with objects in java, i've currently finished three programs for my programming course which has to include your own made objects but i can't think of what to do for the last program. I'd be thankful if anyone could just throw me a idea! Make a card game. Blackjack is easy, but you could go as complex as you'd like, depending on which game you use.
It works pretty intuitively as far as objects go, you can have stuff like Players, Hands, Cards, Decks, etc., or however you decide to implement it.
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1019 Posts
On December 10 2012 08:51 Marradron wrote:Show nested quote +On December 10 2012 08:34 white_horse wrote:How do you "scale" an array so that its maximum value is 1? Our professor wants us to do that to the array "body" (below) but I have no idea what that means. This is for MATLAB not c++, Row = 30; Col = 40; body = zeros(Row, Col);
A = 2 3 5 7 >> A=A./max(A(: )) A = 0.2857 0.4286 0.7143 1.0000 Bassically you scale the array by the maximum value in the array. One problem is that the array in your code is defined as an array with only zeroes. For that case it is not clear what the professor wants.
cool thank you
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Hey guys, I need a bit of help with PHP.
I have a user click a link in a list for the content he wants to see on the next page. the problem is that each one of the options is a line in a file with a delimiter of ~ for each part of the page.
I know how to read it if each page is a different text file but how would I do this?
I know how to explode the delimiter, but how do I explode each line aswell?
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On December 10 2012 09:47 omarsito wrote: I'm wondering if anyone has a idea for a novice program with objects in java, i've currently finished three programs for my programming course which has to include your own made objects but i can't think of what to do for the last program. I'd be thankful if anyone could just throw me a idea! I like a basic adventure game as an object-oriented exercise, since it allows for using inheritiance in a fairly intuitive way: Creatures have HP, MP, and stats. Player derives from Creature and has inventory, spells, equipped weapons, experience points, etc. Objects have HP (if you want everything to be destructible), value in gold, and weight. Item derives from Object and defines slots in which it's allowed to be equipped. Weapon derives from Object and has damage. And so on.
One of the problems with learning inheritance is that it can be a fairly abstract concept. Mapping your classes to familiar things and then figuring out what commonalities they have to derive parent classes makes the process more intuitive for a beginner.
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On December 10 2012 16:47 dapierow wrote: Hey guys, I need a bit of help with PHP.
I have a user click a link in a list for the content he wants to see on the next page. the problem is that each one of the options is a line in a file with a delimiter of ~ for each part of the page.
I know how to read it if each page is a different text file but how would I do this?
I know how to explode the delimiter, but how do I explode each line aswell?
Can't you just explode the line delimiter first, then do a loop and explode the part delimiters?
So if you have part1~part2$part3~part4, and $ is a delimiter for the lines, you would explode $, then loop through the resulting array, exploding the ~. You could save the results in a 2d array. If you grab them from the file so there's no line delimiter, I assume you could explode on "\n" for the lines?
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On December 10 2012 09:19 Poopi wrote:Hey guys. So I just finished a project (well there is this problem so it's not literally finished) in PHP with some mySQL. However I had a problem with a basic search bar. It won't matter since I already sent my project, with the problem, because of the deadline, but my curiosity wants to know what was the solution for this problem. I could not really find the right key words on google so here I ask you if you can help me. So I want the request to search in a precised table the word typed, but I want it to only show the results from this table associated with the current userid. Here is my request showing it but for every id : SELECT * FROM products WHERE name LIKE '%$search%' ORDER BY name (not sure about the syntax Im on mobile don't have access to the files). I would like something like that instead : SELECT * FROM products WHERE fournid='$fournid' AND name LIKE etc $search the $_post of the searchbar and $fournid the $_cookie['userid'] of the current user. Problem this request won't work and I know it but I don't know how I'm supposed to do it. Any ideas? Thanks in advance. Well, right off the bat I noticed that you're using quotes to compare the value in the fournid column... the fact that it ends with id suggests to me that this is actually an integer field and thus you shouldn't be using quotes.
Other than that, both queries looks fine to me. It's impossible to say what is going wrong without knowing the schema of your tables. I think it's worth noting that while I of course don't know anything about your problem domain, the notion of having a "user id" column on a product table suggests something grossly incorrect with your design...
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does this help?
SqlCommand sqlCom = new SqlCommand("UPDATE StudentInfo SET StudentFirstName ='" + takeStudentFirstName + "', StudentSurname ='" + takeStudentSurname + "', CourseID ='" + takeCourseID + "'WHERE StudentID = " + combospStudentID.Text, dbconn);
do shit WHERE studentID = (name of your combo box.Text)
my whole page + Show Spoiler + using System; using System.Collections.Generic; using System.ComponentModel; // ***************************** using System.Data; // using System.Drawing; // using System.Linq; // ***************************** using System.Text; using System.Windows.Forms; using System.Data.SqlClient; // We're going to be using sqlclient library
namespace WindowsFormsApplication1 { public partial class StudentPage : Form // Here's our StudentPage form { private string connectionString = "user id=TestUser;password=password;server=PERCY-PC\\SQLEXPRESS;Trusted_Connection=yes;database=Enrolment"; // Here we give our database connection info, including path, title; in this case we've called the database "Enrolment"
public StudentPage() { InitializeComponent();
combospStudentID.Items.Clear(); // Make sure our combo box is clear SqlConnection dbconn = new SqlConnection(connectionString); // Create the database connection using our (connectionString)
try { dbconn.Open(); // Open the connection } catch // If the above fails, show this error message.. { MessageBox.Show("Connection to database failed. Please check and try again."); }
SqlDataAdapter sqlAdapt = new SqlDataAdapter("SELECT * FROM StudentInfo", dbconn); // Query the database. We are wanting to fill our combobox with StudentIDs, so we retrieve all from the database...
DataTable dt = new DataTable(); sqlAdapt.Fill(dt); // ...and put this data into a temp datatable.
foreach (DataRow dr in dt.Rows) // We can now fill our combobox with StudentIDs (do it for each row in the datatable until exhausted). { combospStudentID.Items.Add(dr["StudentID"]); }
dbconn.Close(); // Close the database connection now it is no longer needed. }
private void button2_Click(object sender, EventArgs e) { this.Close(); AddStudent ac = new AddStudent(); // This button closes the current page and takes us on to Add Student page. ac.ShowDialog(); }
private void button1_Click(object sender, EventArgs e) { this.Close(); // This is our "back" button which will get us back to the Welcome page menu. }
private void spcomboStudentID_SelectedIndexChanged(object sender, EventArgs e) // This is going to be what happens when we select an item in the StudentID combo that we filled earlier
{ SqlConnection dbconn = new SqlConnection(connectionString); // Get ready with a new connection try { dbconn.Open(); // Open the connection } catch { MessageBox.Show("Connection to database failed. Please check and try again."); // Just incase! }
SqlDataAdapter sqlAdapt = new SqlDataAdapter("SELECT * FROM StudentInfo WHERE StudentID = '" + combospStudentID.Text + "'", dbconn); // Here we retrieve everything in a row from StudentInfo table where that row's StudentID is equal to the StudentID we // selected in our combo box!
DataTable dt = new DataTable();
sqlAdapt.Fill(dt); // Stick it in a datatable
foreach (DataRow row in dt.Rows) // And now use it to fill our textboxes, outputting the relevant Firstname, Surname { txtspFirstName.Text = row["StudentFirstName"].ToString(); txtspSurname.Text = row["StudentSurname"].ToString(); }
SqlDataAdapter sqlAdapt2 = new SqlDataAdapter("SELECT * FROM StudentInfo INNER JOIN CourseInfo ON StudentInfo.CourseID=CourseInfo.CourseID WHERE StudentID = '" + combospStudentID.Text + "'", dbconn); // We're not finished yet. We're outputting a Firstname & Surname alongside the associated StudentID.. // But we also want to output a CourseName & CourseID that are associated with our selected student's CourseID. // We join the StudentInfo table to the CourseInfo table, and the CourseIDs on these match up together, allowing us to retrieve..
DataTable dt2 = new DataTable(); sqlAdapt2.Fill(dt2); // ...fill a datatable...
foreach (DataRow dr2 in dt2.Rows) { txtspCourse.Text = dr2["CourseName"].ToString(); // ...and output the relevant values to our GUI textboxes. txtCourseIDgo.Text = dr2["CourseID"].ToString(); }
dbconn.Close(); // Close the connection. Take a deep breath. }
private void button4_Click(object sender, EventArgs e) // This is surely our delete button. { SqlConnection dbconn = new SqlConnection(connectionString); try { dbconn.Open(); } catch { MessageBox.Show("Connection to database failed. Please check and try again."); }
SqlCommand sqlCom = new SqlCommand("DELETE FROM StudentInfo WHERE StudentID = " + combospStudentID.Text, dbconn); // Here we have connected to the database, and are now requesting a deletion from StudentInfo where StudentID is equal // to the Student ID we have selected in our combo box.
try { sqlCom.ExecuteNonQuery(); } catch // Our code doesn't know what to delete if we don't have a Student ID selected in the combo box (ie if nothing is selected).. // ..so to avoid any problems we provide an informative error message if the ExecuteNonQuery() fails. { MessageBox.Show("Please select a Student ID to delete a student."); }
dbconn.Close(); this.Close(); // Close the window after the deletion. Necessary to update the form's values, otherwise the changes won't // be apparent to the user. }
private void btnspUpdate_Click(object sender, EventArgs e) // Our update button. { string takeStudentFirstName = txtspFirstName.Text; // We are going to take whatever values the user inputs into these string takeStudentSurname = txtspSurname.Text; // textboxes and then submit them for update! string takeStudentCourse = txtspCourse.Text; string takeCourseID = txtCourseIDgo.Text;
SqlConnection dbconn = new SqlConnection(connectionString); // Prepare and open connection.
try { dbconn.Open(); } catch { MessageBox.Show("Connection to database failed. Please check and try again."); }
try { SqlCommand sqlCom = new SqlCommand("UPDATE StudentInfo SET StudentFirstName ='" + takeStudentFirstName + "', StudentSurname ='" + takeStudentSurname + "', CourseID ='" + takeCourseID + "'WHERE StudentID = " + combospStudentID.Text, dbconn); sqlCom.ExecuteNonQuery(); // A simple update. Replaces the database values in a row relevant to our selected Student ID. Notice that we don't want // the user editing/updating CourseName because they could write any old thing in there! CourseName is explicitly linked to // CourseID and we only want someone to change a Course Name when they go to the appropriate Course Details page. This prevents // the user from thinking that in order to change the course of a student he can just edit in any old thing on the Student Page // without adhearing to any formatting standards or realising that an associated Course ID is required for database function.
} catch { MessageBox.Show("Please check your input. Course ID must be a valid Course ID. Refer to Course Page for more information."); } // Damn right you will check your input.
dbconn.Close(); } } }
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France12886 Posts
On December 11 2012 00:54 neSix wrote:Show nested quote +On December 10 2012 09:19 Poopi wrote:Hey guys. So I just finished a project (well there is this problem so it's not literally finished) in PHP with some mySQL. However I had a problem with a basic search bar. It won't matter since I already sent my project, with the problem, because of the deadline, but my curiosity wants to know what was the solution for this problem. I could not really find the right key words on google so here I ask you if you can help me. So I want the request to search in a precised table the word typed, but I want it to only show the results from this table associated with the current userid. Here is my request showing it but for every id : SELECT * FROM products WHERE name LIKE '%$search%' ORDER BY name (not sure about the syntax Im on mobile don't have access to the files). I would like something like that instead : SELECT * FROM products WHERE fournid='$fournid' AND name LIKE etc $search the $_post of the searchbar and $fournid the $_cookie['userid'] of the current user. Problem this request won't work and I know it but I don't know how I'm supposed to do it. Any ideas? Thanks in advance. Well, right off the bat I noticed that you're using quotes to compare the value in the fournid column... the fact that it ends with id suggests to me that this is actually an integer field and thus you shouldn't be using quotes. Other than that, both queries looks fine to me. It's impossible to say what is going wrong without knowing the schema of your tables. I think it's worth noting that while I of course don't know anything about your problem domain, the notion of having a "user id" column on a product table suggests something grossly incorrect with your design... There is no userid in the product table. There is a fournid and in my request it corresponds to the userid because this fournid is in this case = to the userid. Basically it's a search bar of a "supplier" (fournissor?) and it's supposed to only show his products.
By the way yeah the second request works LOL. Maybe I inversed the AND the first time, I don't know, the fact that yesterday I was almost only programming maybe prevented me from thinking calmly and clearly, and since I wrote the second request maybe 2 or 3 hours after stopping the work it was easier to get it right.
Too bad I could not send my project with this search bar working right T;T.
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Please, please learn how to use parameterized queries when using any database. That is much safer against SQL injection.
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Guys is there a more efficient way to do this?
The assignment(I just completed as shown) is to use single for loop(s) to:
User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown)
I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[]) { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
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I'm so pissed right now. I've aced everything in my Python class all year. The last week I've done a lot of coding, and I tried to do two earlier exams, and got EVERYTHING right on both of them(this is the first time I've ever gotten everything right on an exam). But today everything have been shitty, I've forgot a lot of syntax, and my brain just don't work, and my exam is tomorrow Hope I just had a bad day.
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On December 11 2012 06:57 3FFA wrote: Guys is there a more efficient way to do this?
+ Show Spoiler [yes] +#include <stdio.h>
int main( void ) { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i", &num);
//check input and output result for (; num > 0; num--) { printf("*"); } }
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On December 11 2012 06:57 3FFA wrote:Guys is there a more efficient way to do this? The assignment(I just completed as shown) is to use single for loop(s) to: User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown) I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[] { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
Maybe just declare an int stars, then make a loop for ( stars == 0; stars < num; stars ++ )
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On December 11 2012 06:57 3FFA wrote:Guys is there a more efficient way to do this? The assignment(I just completed as shown) is to use single for loop(s) to: User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown) I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[] { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
Use the input the as the upper bound
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On December 11 2012 07:07 GwSC wrote:Show nested quote +On December 11 2012 06:57 3FFA wrote:Guys is there a more efficient way to do this? The assignment(I just completed as shown) is to use single for loop(s) to: User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown) I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[] { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
Maybe just declare an int stars, then make a loop for ( stars == 0; stars < num; stars ++ )
Careful there, you want the assignment operator, =, not the equivalence operator, ==.
Do you get bonus points if you do this with 0 loops using regex? j/k, don't do that. Seriously, don't.
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On December 11 2012 06:57 3FFA wrote:Guys is there a more efficient way to do this? The assignment(I just completed as shown) is to use single for loop(s) to: User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown) I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[] { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
This would also work if you removed all but any one of these loops. By coincidence I guess. Read up on assignment operators vs equality operators again and see if you can figure out what happens.
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On December 11 2012 06:57 3FFA wrote:Guys is there a more efficient way to do this? The assignment(I just completed as shown) is to use single for loop(s) to: User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown) I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[] { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
As people above pointed out, yes, you do it with a simple, single loop. But since the code you wrote would imply that you're a beginner, here are a couple of super helpful tips for the future.
1) Generally, if you find yourself doing a similar action over and over with little change, or a measurable change, you should be doing it in a loop. Every time you copy paste something, you should double check to make sure you changed everything that needed to be changed, and that you actually need to be copy pasting in the first place. In this case, you do it with one for loop and using num as the bound. Always watch out for this simplification.
2) Don't trust the user to input a number. Users are idiots. Check what they input to make sure it's within sensible bounds, in this case 1 <= num <= 15. You can use a do { input; } while(num <= 1 || num >= 15); loop to force them to input a correct number, or just spit an error out and quit if they don't do it right.
3) As above, be careful with assignment and the difference between = and ==.
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Thank you so much guys! This was amazingly helpful to me. :D
edit especially Mr.Fish above! You made me realize I forgot to check that the user wasn't stupid >.>;; while teaching a few things!
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On December 11 2012 06:57 3FFA wrote:Guys is there a more efficient way to do this? The assignment(I just completed as shown) is to use single for loop(s) to: User inputs a number from 1-15 I check the input and output the result in the form of "*" 's so if the user inputs 5 the program outputs ***** (in a row as shown) I would like to know if there is a more efficient way to do this since this felt a bit too repetitive (especially since the for loops were just copy + paste + change 1 number over and over again)... + Show Spoiler +
#include <stdio.h>
int main(int argc, const char * argv[] { //declare variables int num; //number entered by user //user input printf("Please input an integer between 1 and 15: "); scanf("%i",& num);
//check input and output result for (num == 1; num > 0; num--) { printf("*"); } for (num == 2; num > 0; num--) { printf("*"); } for (num == 3; num > 0; num--) { printf("*"); } for (num == 4; num > 0; num--) { printf("*"); } for (num == 5; num > 0; num--) { printf("*"); } for (num == 6; num > 0; num--) { printf("*"); } for (num == 7; num > 0; num--) { printf("*"); } for (num == 8; num > 0; num--) { printf("*"); } for (num == 9; num > 0; num--) { printf("*"); } for (num == 10; num > 0; num--) { printf("*"); } for (num == 11; num > 0; num--) { printf("*"); } for (num == 12; num > 0; num--) { printf("*"); } for (num == 13; num > 0; num--) { printf("*"); } for (num == 14; num > 0; num--) { printf("*"); } for (num == 15; num > 0; num--) { printf("*"); }
Ah, covered above.. *ediT*
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