|
meh, i worked on this problem along, i couldn't figure out, i called a friend to help he doesn't know either...
The machinist's square below consists of a thin, rectangular blade and connected to a rectangular handle. Determine the X and Y coordinates of the center of gravity. Let the lower left corner be x=0 y=0...
The vertical rectangle has a mass of 40g, and is 11cm high, and 4 cm wide. The 80 g rectangle is 3cm high, and 12cm wide... But if you place them like that, all together it is 16cm wide...
Edit: Please click on the image to make it bigger, if it needs to be even bigger, click on that image hold ctrol and scroll with your mouse wheel.... The answer in the back of the book is (8.7cm, 8.2 cm) I have no idea how to get it...T_T
THANKS ALL
 
|
Easiest way to do this, since this is kind of a joke question with these co-ordinates, is to label the obvious center of gravity of both rectangles, then weight them according to their mass and average their co-ordinates.
|
I would suggest you re-read the definition of center of mass. Where are you getting your numbers? What do the distances x_i represent?
|
On December 22 2008 12:53 Daveed wrote:
I would suggest you re-read the definition of center of mass. Where are you getting your numbers? What do the distances x_i represent?
X1 is the distance from the origin, M1 is the mass...
|
Also, the answers in the book aren't wrong. However, your figure is - that "16 cm" line should start at the beginning of the horizontal block.
X_1 is the distance from the origin of the center of mass of the object. Does that make sense?
|
On December 22 2008 12:57 Daveed wrote:
Also, the answers in the book aren't wrong. However, your figure is - that "16 cm" line should start at the beginning of the horizontal block.
X_1 is the distance from the origin of the center of mass of the object. Does that make sense?
oh no, i did that on purpose the 16 cm is the combined of the 2 blocks like that i double checked the image from the book... 
|
United States24494 Posts
On December 22 2008 12:51 L wrote:
Easiest way to do this, since this is kind of a joke question with these co-ordinates, is to label the obvious center of gravity of both rectangles, then weight them according to their mass and average their co-ordinates.
This. Do you need help doing this?
|
I've said it before, I'll say it again: I imagine micronesia as some sort of cape wearing hero in a physics classroom. Once the Teamliquid Forum Physics Thread Detector goes off, he immediately comes and resolves the topic.
Even when someone beats him too it, he somehow manages to take control of the topic.
|
Helping people with their homework on a broodwar forum, my my..
|
The green markings looked like a penis to me at first glance.
|
On December 22 2008 14:37 Cloud wrote:
Helping people with their homework on a broodwar forum, my my..
Did you just now realize this?
|
Sometimes, I feel that people just don't try anymore...
|
|
|
|
|
|
EPT![[image loading]](http://img368.imageshack.us/img368/718/29954062ur4.jpg)
![[image loading]](http://g.imageshack.us/img368/29954062ur4.jpg/1/)
