EPTOn June 17 2005 13:37 Xeofreestyler wrote:
Bigballs, its
13112221
Bigballs, its
13112221
booyah
hmm, lets see if i can come up with more...
Math Puzzles - Page 3
| Forum Index > General Forum |
|
BigBalls
United States5354 Posts
booyah hmm, lets see if i can come up with more... | ||
|
Malmis
Sweden1569 Posts
On June 17 2005 13:43 loloko2 wrote: Why do you have to ruin my joke to the teamliquidians T__T i hate you ^_^ I'm sure it was x^n+y^n=z^n doesn't have any integer solutions if n > = 2 And it was solved in 1993 by Andrew Wiles. Edit: oops someone already mentioned it t.,t | ||
|
-_-
United States7081 Posts
On June 17 2005 13:49 Xeofreestyler wrote: Err, wtf no? 312211 -> one 3 one 1 two 2 two 1 -> 13112221 then that one would be one 1 one 3 two 1 three 2 one 1 -> 1113213211 Kthxbai. -_-, do you see the three before the 1? 3 ones. do you see the 2 before the 2? Two 2's. Do you see the 1 before the 1? One one KTHXBAIBITCH | ||
|
BigBalls
United States5354 Posts
if the first pirate were gone, then it were split equally, each would get 25% 50-1, 25+1, 25, 0,0 | ||
|
LTT
Shakuras1095 Posts
On June 17 2005 13:49 Xeofreestyler wrote: Err, wtf no? 312211 -> one 3 one 1 two 2 two 1 -> 13112221 then that one would be one 1 one 3 two 1 three 2 one 1 -> 1113213211 Kthxbai. I haven't been following the puzzle, so the numbers might prove me wrong, but there are two general forms for this one. In one, all the digits are looked at and then written, in another it goes by differences. Let me give an example 312211 in the former case would be 132231 (one 3 two 2s three 1s) in the latter it would be 13112221 (one 3 one 1 two 2s two 1s) | ||
|
LTT
Shakuras1095 Posts
On June 17 2005 13:53 BigBalls wrote: if it was all split equally, each pirate would get 20% if the first pirate were gone, then it were split equally, each would get 25% 50-1, 25+1, 25, 0,0 Closer, but still thinking about it the wrong way. Start with the 2 pirate case and work your way to 5 | ||
|
MPXMX
Canada4309 Posts
| ||
|
LTT
Shakuras1095 Posts
On June 17 2005 13:56 MPXMX wrote: Must the first pirate propose specific proportions of splitting the loot or can he say things like "2nd pirate can take as much as he wants as long as 2/3 of the rest of you agree with it" ? I'm sure he can, but his optimal solution involves a specific number of coins going to certain pirates. | ||
|
BigBalls
United States5354 Posts
fourth pirate 100, last pirate 0 - passes 3 pirates third pirate 99, fourth pirate 0, last pirate 1 - improvement 4 pirates second pirate 99, third pirate 0, fourth pirate 0, last pirate 1 5 pirates first pirate 98, second pirate 0, third pirate 1, fourth pirate 0, last pirate 1 | ||
|
LTT
Shakuras1095 Posts
On June 17 2005 13:58 BigBalls wrote: 2 pirates fourth pirate 100, last pirate 0 - passes 3 pirates third pirate 99, fourth pirate 0, last pirate 1 - improvement 4 pirates second pirate 99, third pirate 0, fourth pirate 0, last pirate 1 5 pirates first pirate 98, second pirate 0, third pirate 1, fourth pirate 0, last pirate 1 Yeah, that's the right way to do it, but the 4 pirates case, the 4th pirate gets 1 and the last gets 0. Edit: Remember that they are bloodthirsty as well. fourth and last pirate have no improvement over the 3 pirate setup so all else being equal, they'd like the proposer to die. since the third pirate is really losing out, it'd end up 3-1 against the proposal. | ||
|
BigBalls
United States5354 Posts
| ||
|
wasted
Germany1789 Posts
On June 17 2005 13:20 Pistachio wrote: Here's a better one: Three woman go to their favorite restaurant and each order some food that costs £30 overall. So they each give £10 to the waiter who then gives it to the manager. The manager however decides to give £5 back to the women as a good will gesture since the women have been such loyal customers over the years. Now the waiter thinks he can make some money out of this so he secretely takes £2 for himself and only gives £1 back to each women. This means each woman has payed £9 each, having originally payed £10 and gotten £1 back. The waiter has £2 thus the overall money payed is 3x9 + 2 = £29. So where'd the extra pound go? the overall money payed is 3x9=27. the 2 bucks are just split from that, so the manager gets 25 and the waiter 2. | ||
|
BigBalls
United States5354 Posts
fourth pirate 100, last pirate 0 - 1/2 passes 3 pirates third pirate 99, fourth pirate 0, last pirate 1 - improvement for last pirate, 2/3 passes 4 pirates second pirate 99, third pirate 0, fourth pirate 1, last pirate 0 - fourth pirate will improve and will vote for the second pirate 2/4 passes 5 pirates first pirate 98, second pirate 0, third pirate 1, fourth pirate 0, last pirate 1 3/5 passes | ||
|
Pacifist
Israel1683 Posts
On June 17 2005 13:20 Pistachio wrote: Here's a better one: Three woman go to their favorite restaurant and each order some food that costs £30 overall. So they each give £10 to the waiter who then gives it to the manager. The manager however decides to give £5 back to the women as a good will gesture since the women have been such loyal customers over the years. Now the waiter thinks he can make some money out of this so he secretely takes £2 for himself and only gives £1 back to each women. This means each woman has payed £9 each, having originally payed £10 and gotten £1 back. The waiter has £2 thus the overall money payed is 3x9 + 2 = £29. So where'd the extra pound go? they paid 9 each to the manager, who essentially received 27 but has 25 now cuz the waiter took 2. why would u add 2 to 27? | ||
|
LTT
Shakuras1095 Posts
 | ||
|
MPXMX
Canada4309 Posts
| ||
Xeofreestyler
Belgium6772 Posts
On June 17 2005 13:52 -_- wrote: -_-, do you see the three before the 1? 3 ones. do you see the 2 before the 2? Two 2's. Do you see the 1 before the 1? One one KTHXBAIBITCH Your way of solving it would be wrong since then the first 5 elements of the row would be wrong. Kthxstfubainub Now lets stop this silly riddle and I'll here's a fresh one: On a small planet not far away lived a strange race. A long time ago all the members of that species had one of three eye colors: blue, green or brown. In some point in history a famous war took place, initiated by the blue and brown eye faction. They genocided all green eyes, thus eliminating the green eye color from their race, and reducing the population of the planet to a few hundred. Soon after that war the factions were disbanded, and eye color was from that point on considered an inappropriate topic. Some rules were later established for the benefit of the whole society, so that something like this could never, ever happen again. The rules were as follows: 1. Nobody is allowed to talk about eyecolors. 2. If anyone gets to know his own eyecolor he must commit suicide at midnight in the town square. Now I must explain the way this species was thinking, so you understand their reactions later on. You must understand that they all were really strict about those rules. In the beginning some people happened to accidently see their eyecolor in some reflective surface or puddle of water, and every last one of them faithfully comitted suicide the night after. After a few incidences all mirroring surfaces were removed from the cities, to minimize the risk. Also, this species was a very logical thinking. Although they still lacked knowledge in some areas, they thought clearly and logically, and trusted in the results they got, even if it led to their own death. Last, the way it worked after the rules were established was that everyone knew the eyecolor of everyone else on the planet, but not his own. Of course, on a small planet like this, they all saw everyone everyday, so a suicide was immediately noted. Well, the people on this little planet were living for a few hundred years in peace and harmony, when something bad happened: A little spacecraft crashed down in the desert near one of the large cities, leaving a big crater. Immediately the friendly people tried to rescue the astronauts, but it was too late. The only thing they recovered from the craft was a book about mathematics. In the same night a big meeting was called on, and everyone came together in a large hall. The book was read to the whole population, because it offered new concepts that were so impressive and striking that everyone had to know about them. But, knowledge isn't always a good thing. The knowledge in that book made the people aware of facts they didnt know about before, and made them realize a few things. In the following nights everyone was really nervous. Then, in the 250th night after the dreaded meeting, all brown eyes committed suicide, thus eliminating the whole species, and leaving the planet an empty brick in the wide universe. Blue eyes present during the meeting: Are there more blue or brown eyes in the meeting? Number of nights in which suicides happened: Which mathematical concept made them kill themselves? | ||
|
LTT
Shakuras1095 Posts
| ||
|
LTT
Shakuras1095 Posts
You might want to change it from blue to brown on your first question. | ||
|
Xeofreestyler
Belgium6772 Posts
| ||
| ||
