
Puzzleing Question! (HARD) - Page 57
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radar14
United States1437 Posts
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BigBalls
United States5354 Posts
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BigBalls
United States5354 Posts
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Shiv
France447 Posts
On November 24 2004 14:32 Catyoul wrote: Elaborate, you're just reformulating : "no no no, you are wrong." Let's take the statistical approach with big numbers, which will tend to the correct probability. So we have our 1000 houses again. Let's say you are going to knock on all doors, because that's what you do to get the probability for all the cases. What happens at the 3 different type of houses : - The girl / girl houses : a girl answer the door. ALWAYS. That makes 250 houses with a girl always answering - The girl / boy houses : a girl answer the door, 1/2 the time. That makes 500/2 = 250 houses with a girl answering and 250 with a boy answering - The boy / boy houses : a boy answers the door, always. That makes 250 houses with a boy answering. Totals : 500 houses with a girl answering, 500 with a boy answering... of course ! Now the problem tells us, as you underline, that a girl opens the door. So we are in the 500 cases where a girl has opened the door. In those 500 cases, we see that 250 come from girl/girl houses and 250 from girl/boy houses. That makes 1/2 for the second child to be a boy and 1/2 for the second child to be a girl. Let's see if we agree on basic probabilities just to be sure. 1. I show you the first 9 flips, they happen to be tails. What's the probability for the 10th one ? 2. I tell you there are at least 9 tails. What's the probability for the 10th one (the one that isn't included in the 9 tails I told you) ? If you don't understand how these 2 questions are different, sorry I can't say much more. 3rd question, more tricky 3. I tell you there are at least 9 tails. Now, what's the probability of the flip number 10 (not the 10th one like in question 2) to be head or tail ? Btw, the correct answers are : 1. 50% tail 50% head 2. 1/11= ~9% tail 10/11 = ~91% head 3. 10/11 tails, 1/11 heads I agree. And I totally agree with you on your first reasoning except that: you're dividing the probabilities of a girl of a girl/boy house by two by saying they can equally answer the door. Again the problem states that a girl opens the door, which means in my example that: at every single house where it is possible, a girl member of the family (one because girls won't go open the door together, if yes, they would have and the problem would have been solved, for obvious reasons) will open the door. | ||
Catyoul
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France2377 Posts
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NoSteratu
Turkey770 Posts
On November 24 2004 14:43 Catyoul wrote: (7+1/7)*(7+7) = 100 yeah xD | ||
BigBalls
United States5354 Posts
100/7 = 14 2/7. shit, no where 100/14 = 7 1/7 AH A HAHAHAHAHHAHAHAHA nice problem 100/(7+7) = 7 + 1/7 | ||
BigBalls
United States5354 Posts
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Catyoul
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France2377 Posts
![]() edit : the technical answer was "with a pen and paper" btw :p | ||
BigBalls
United States5354 Posts
Consider the following game. There are N cards face down on a table. Each card has a number on it, which need not be an integer and need not be positive. You know nothing about the values on the cards, i.e. you have no knowledge of the lowest nor highest card. You are to play the following game. You can turn cards over one at a time and look at the value on the card. Once a card is turned over, it stays turned over. You win the game if and only if the last card you turn over is the card with the maximum number. Devise a strategy that will let you win, on average, at least one quarter of the time. Put another way, your strategy must guarantee that the probability that you win any game, regardless of the number of cards on the table, is at least 0.25. | ||
Shiv
France447 Posts
Bastards. You're right in 2 of 3 cases. Or is it 3 of 4? Crap ![]() | ||
Catyoul
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France2377 Posts
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Shiv
France447 Posts
On November 24 2004 15:20 Catyoul wrote: Although I find your idea a bit far-fetched Lies and calumnies! Oh god I'm spamming. Sorry. | ||
Catyoul
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France2377 Posts
*****SPOILERS******* It's pretty good, it will even let you win all the time. So, you turn the cards one by one. With great carefulness, your skilled broodwar hand reverses every one of them. Then in a stroke of genius, now that you see all the cards, you turn over the biggest one and you stop. The last card you turned over was the biggest one, no lies, no tricks (well ok it's a bit dirty but I'm exploiting the weaknesses of the terms :p) | ||
BigBalls
United States5354 Posts
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BigBalls
United States5354 Posts
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Taguchi
Greece1575 Posts
catyoul's is the most likely i can imagine of right now :p u sure uve worded everything correctly bigballs? | ||
BigBalls
United States5354 Posts
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Catyoul
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France2377 Posts
edit : anyway, gn ![]() | ||
Jim
Sweden1965 Posts
you turn up half of the cards. after that you stop if you find a card higher than the previous cards. the chance that the highest card was in the first half is 50%. however if you find a card which is higher than all of the first half's cards you should win atleast 50% of the time(worst case being you find the highest card right after the middle). 1/2^2 is 25%. | ||
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