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micronesia
United States24723 Posts
On October 23 2008 09:29 travis wrote: so it comes down to: drag force VS force of gravity and the force of gravity is based upon mass of the objects? Correct. edit: but I wouldn't consider that alone a sufficient explanation | ||
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Deleted User 3420
24492 Posts
On October 23 2008 09:30 micronesia wrote: Correct. edit: but I wouldn't consider that alone a sufficient explanation why not? oh, because of terminal velocity? | ||
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micronesia
United States24723 Posts
Well I suppose if you just wanted to know which one would have a bigger acceleration, everything else besides mass being equal, then that would be acceptable. If you want to discuss how the objects' motion would change over time, then you'd need to also recognize that the force of friction depends on the speed (in this case) | ||
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Mooga
United States575 Posts
On October 23 2008 09:37 micronesia wrote: Well I suppose if you just wanted to know which one would have a bigger acceleration, everything else besides mass being equal, then that would be acceptable. If you want to discuss how the objects' motion would change over time, then you'd need to also recognize that the force of friction depends on the speed (in this case) micronesia, drag force already accounts for velocity. | ||
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Deleted User 3420
24492 Posts
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micronesia
United States24723 Posts
On October 23 2008 09:40 Mooga wrote: micronesia, drag force already accounts for velocity. You were going on the assumption that by saying 'drag force' you realize how the drag force works, besides the fact that it is simply a force that opposes motion in a fluid (such as air). I don't believe that was true, however it doesn't need to be given the nature of Travis' request. BTW Travis who won? | ||
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Deleted User 3420
24492 Posts
So I pay $100, rather than winning $1000. It's alright, i expected to lose the bet from the start. I assumed I must have been missing something  | ||
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Luddite
United States2315 Posts
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Mooga
United States575 Posts
On October 23 2008 10:12 micronesia wrote: You were going on the assumption that by saying 'drag force' you realize how the drag force works, besides the fact that it is simply a force that opposes motion in a fluid (such as air). I don't believe that was true, however it doesn't need to be given the nature of Travis' request. BTW Travis who won? The drag force is a force F (you can double-check this by reducing the units of [check picture]) and this applies at any given time. ![[image loading]](http://upload.wikimedia.org/math/7/6/1/7613c56c8438ae8fa328dcbd4f4f4e7c.png) where p=density=F(L^-4)(T^2) u=velocity=L(T^-1) Cd= dimensionless A= L^2 Thus, the drag force can be expressed as single force (at any given time). Edit: Fixed the link to the pic | ||
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micronesia
United States24723 Posts
On October 23 2008 10:34 Mooga wrote: The drag force is a force F (you can double-check this by reducing the units of [check picture]) and this applies at any given time. where p=density=F(L^-4)(T^2) u=velocity=L(T^-1) Cd= dimensionless A= L^2 Thus, the drag force can be expressed as single force (at any given time). Edit: Fixed the link to the pic I'm not disagreeing with your analysis of what a drag force is (honestly I didn't even read the above). I'm just saying, when Travis refers to the 'drag force', he isn't referring to the specifics, but just to the basics. edit: oh sorry, I made it sound like you didn't understand it, rather than that Travis didn't. My apologies for the miss-communication. | ||
Bill307
Canada9103 Posts
On October 23 2008 08:06 travis wrote: here is my question. 2 objects, same shape, surface, and size. different masses. both are dropped from an airplane. before either object reaches terminal velocity, will they accelerate at the same rate? Their accelerations will be close, but not the same. The two objects experience different gravity forces and the same air resistance force (at equal speeds). They have different masses, and whereas the acceleration from gravity is the same, the air resistance force will affect the objects by different amounts because of their different masses. | ||
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