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Math Homework Help

Blogs > micronesia
Post a Reply
1 2 Next All
micronesia
Profile Blog Joined July 2006
United States24782 Posts
April 19 2008 02:57 GMT
#1
1) 1+7

2) 4*3

3) 12-9

4) 14/7

5) How many two dimensional surfaces does a seven dimensional (hyper) cube have? Justify your answer.

*****
ModeratorThere are animal crackers for people and there are people crackers for animals.
EmeraldSparks
Profile Blog Joined January 2008
United States1451 Posts
April 19 2008 03:02 GMT
#2
1. 42
2. 42
3. 42
4. 42
5. 42
But why?
MeriaDoKk
Profile Blog Joined July 2007
Chile1726 Posts
April 19 2008 03:19 GMT
#3
1.-9
2.-15
3.-7
4.-67
5.-2
Boblion
Profile Blog Joined May 2007
France8043 Posts
April 19 2008 03:24 GMT
#4
1) 8
2) 12
3) 3
4) 2
5) + Show Spoiler +
[image loading]
you are kidding ? This one is too easy


[image loading]
fuck all those elitists brb watching streams of elite players.
Lemonwalrus
Profile Blog Joined August 2006
United States5465 Posts
Last Edited: 2008-04-19 03:29:25
April 19 2008 03:28 GMT
#5
1. 8
2. 12
3. 3
3. 2
5. 672. (E sub m,n = 2 to the n-m * (n! / m!(n-m)!) where n equals cube dimensions and m equals surface dimensions.)
Boblion
Profile Blog Joined May 2007
France8043 Posts
April 19 2008 03:31 GMT
#6
I see a lot of Romanian potential here.
fuck all those elitists brb watching streams of elite players.
micronesia
Profile Blog Joined July 2006
United States24782 Posts
Last Edited: 2008-04-19 03:34:23
April 19 2008 03:32 GMT
#7
On April 19 2008 12:28 Lemonwalrus wrote:
5. 672. (E sub m,n = 2 to the n-m * (n! / m!(n-m)!) where n equals cube dimensions and m equals surface dimensions.)

Is that what you get when the take the matrix:

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 23 7 1

and square it?
ModeratorThere are animal crackers for people and there are people crackers for animals.
Lemonwalrus
Profile Blog Joined August 2006
United States5465 Posts
Last Edited: 2008-04-19 03:35:09
April 19 2008 03:33 GMT
#8
I just found a formula to solve the problem, the actual math/reasoning involved is way above my head, sorry.

Edit: And I don't even remember how to do the simplest of calculations using matrices.
Boblion
Profile Blog Joined May 2007
France8043 Posts
Last Edited: 2008-04-19 03:40:49
April 19 2008 03:34 GMT
#9
Hawk could help you to do your homework i think.

[spoiler][spoiler][spoiler][spoiler]+ Show Spoiler +
+ Show Spoiler +
you are mocking him ?
[spoiler][/spolier]
fuck all those elitists brb watching streams of elite players.
micronesia
Profile Blog Joined July 2006
United States24782 Posts
April 19 2008 03:34 GMT
#10
On April 19 2008 12:33 Lemonwalrus wrote:
I just found a formula to solve the problem, the actual math/reasoning involved is way above my head, sorry.

Tomorrow when I have time I'll run through the calculations for my method to check if you are correct (unless someone else comes here and gives a convincing response)
ModeratorThere are animal crackers for people and there are people crackers for animals.
Lemonwalrus
Profile Blog Joined August 2006
United States5465 Posts
April 19 2008 03:36 GMT
#11
What level math is this for?
azndsh
Profile Blog Joined August 2006
United States4447 Posts
Last Edited: 2008-04-19 03:37:20
April 19 2008 03:36 GMT
#12
if you fix 5 coordinates, the remaining 2 coordinates determine a unit square... thus 632
micronesia
Profile Blog Joined July 2006
United States24782 Posts
Last Edited: 2008-04-19 03:38:10
April 19 2008 03:37 GMT
#13
On April 19 2008 12:36 Lemonwalrus wrote:
What level math is this for?

It's just satire but I didn't want to make a COMPLETELY insubstantial post so I added a random math procedure I vaguely understand (with no other exigency for posting it).

azndsh I think you need to explain that..
ModeratorThere are animal crackers for people and there are people crackers for animals.
Lemonwalrus
Profile Blog Joined August 2006
United States5465 Posts
April 19 2008 03:40 GMT
#14
On April 19 2008 12:37 micronesia wrote:
azndsh I think you need to explain that..

Second.
azndsh
Profile Blog Joined August 2006
United States4447 Posts
Last Edited: 2008-04-19 03:46:26
April 19 2008 03:45 GMT
#15
say your hypercube has coordinates either 0 or 1 in 7 dimensional space.
Thus, one of these squares would be the following four points
(0, 0, 0, 0, 0, 0 ,0)
(1, 0, 0, 0, 0, 0, 0)
(0, 1, 0, 0, 0, 0, 0)
(1, 1, 0, 0, 0, 0, 0)

Notice that only the first 2 coordinates are different. Its easy to see that is true for any unit square. I could describe this square as
(x, x, 0, 0, 0, 0, 0)
Thus 5 coordinates are fixed, while the remaining 2 describe the square.

There are (7 choose 5) * 2^5 ways to fix 5 coordinates

The other formula corresponds to the general case.
micronesia
Profile Blog Joined July 2006
United States24782 Posts
April 19 2008 03:53 GMT
#16
According to my method I get 21x1 + 35x3 + 35x6 + 21x10 + 7x15 + 1x21 = 672. I think lemonwalrus' method was correct azndsh
ModeratorThere are animal crackers for people and there are people crackers for animals.
Lemonwalrus
Profile Blog Joined August 2006
United States5465 Posts
Last Edited: 2008-04-19 03:57:33
April 19 2008 03:55 GMT
#17
Azndsh's method, as far as I can tell, supports my method, but simply shows that my method is only applicable under certain conditions, where his is more universal. Then again I might be trying to understand things that I simply cannot.

Edit: (7 choose 5) * 2^5 = 672, right?
azndsh
Profile Blog Joined August 2006
United States4447 Posts
April 19 2008 04:03 GMT
#18
yes, my method is exactly how to arrive at your formula

you can extend the argument to arbitrary (m,n)
micronesia
Profile Blog Joined July 2006
United States24782 Posts
April 19 2008 04:06 GMT
#19
So... is it 632 or 672...
ModeratorThere are animal crackers for people and there are people crackers for animals.
Lemonwalrus
Profile Blog Joined August 2006
United States5465 Posts
April 19 2008 04:10 GMT
#20
Where are you getting 632?
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