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Math Help

Blogs > cz
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cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:19 GMT
#1
I'm writing a public service exam soon and need some help on number series.

For example: 1, 2, 3, 4, X, what is X?

Now that's an easy and obvious one, but the test I'm going to do has some extremely difficult questions. How do I go about studying this? I've tried googling but haven't found an effective method? Any of you math people have a good idea of a way to learn how to identify and do these number series quickly?

****
infinitestory
Profile Blog Joined April 2010
United States4053 Posts
October 14 2011 05:20 GMT
#2
http://oeis.org/
Translator:3
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:22 GMT
#3
On October 14 2011 14:20 infinitestory wrote:
http://oeis.org/


Can this help me train for a closed-book test?
infinitestory
Profile Blog Joined April 2010
United States4053 Posts
Last Edited: 2011-10-14 05:26:01
October 14 2011 05:24 GMT
#4
most likely not; it's very good at finding the formula behind integer sequences, and not much else

if you haven't already, you should learn to derive a polynomial sequence by finite differences
Translator:3
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:26 GMT
#5
On October 14 2011 14:24 infinitestory wrote:
most likely not; it's very good at finding the formula behind integer sequences, and not much else


Yeah, it's definitely a beast for that. I need basically:

1) Some examples of integer sequences from medium to hard
2) How to solve them
3) Their solutions

I just need a thought process here. I can almost just go with steps 1 and 3 though, and work it out from there - I assume there a limited number of patterns that you can realistically give for a general public service test, and if I solve 100 or so of them before the test the ones on the best will fit somewhat closely to the ones I practiced.

Anyone have a bunch of medium to hard number sequences to solve and break down?
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:28 GMT
#6
On October 14 2011 14:24 infinitestory wrote:
most likely not; it's very good at finding the formula behind integer sequences, and not much else

if you haven't already, you should learn to derive a polynomial sequence by finite differences


How do I do that? Also I just need to find the next number in the series, not find an expression that would generate the series.

There's also trick stuff like 1,5,2,6,X with X being 3 as it's basically 1,2,X and 5,6,Y basic +1 pattern being interspliced together.
super_sonic
Profile Joined August 2011
Singapore5 Posts
Last Edited: 2011-10-14 05:43:32
October 14 2011 05:38 GMT
#7
try learning some basic series, like arithmetic, geometric, Fibonacci. and check if they have something to do with what you are given. Alternatively, you may look for some patterns, like how fast a series is growing, let's say you have a series of 2,10,26,50,X, the differences between two consecutive members are 8, 16, 24, so it is natural to assume that the next is number is 32 plus previous one, 50. So the answer is 82. In fact, that series is (2*n+1)^2+1, for n = 0,1,2,3
Plexa
Profile Blog Joined October 2005
Aotearoa39261 Posts
Last Edited: 2011-10-14 05:42:30
October 14 2011 05:40 GMT
#8
Well its hard to know what you define as medium to hard difficulty though for instance what level would you consider 1 1 2 6 24 120 X to be?

btw these are sequences not series :3
Administrator~ Spirit will set you free ~
whatthefat
Profile Blog Joined August 2010
United States918 Posts
October 14 2011 05:40 GMT
#9
I would make sure you know the most commonly used sequences. Specifically:
1) Know your squares and cubes
2) Know the Fibonacci sequence
3) Know the triangular numbers
4) Also be aware of modular arithmetic. The example you gave:
There's also trick stuff like 1,5,2,6,X with X being 3 as it's basically 1,2,X and 5,6,Y basic +1 pattern being interspliced together.
is actually an arithmetic progression in mod 7 (1, 1+4=5, 5+4=2, 2+4=6, 6+4=3).
SlayerS_BoxeR: "I always feel sorry towards Greg (Grack?) T_T"
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:49 GMT
#10
On October 14 2011 14:40 Plexa wrote:
Well its hard to know what you define as medium to hard difficulty though for instance what level would you consider 1 1 2 6 24 120 X to be?

btw these are sequences not series :3


Medium. Right in the middle.
Plexa
Profile Blog Joined October 2005
Aotearoa39261 Posts
October 14 2011 05:49 GMT
#11
Somehow I get the feeling modular arithmetic isn't covered in this!
Administrator~ Spirit will set you free ~
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:50 GMT
#12
I basically don't have much time to spend on this either. Think 2-4 hours tops. I just need to get through the basic stuff, then I have to move on to studying the logic puzzles and some other basic math.
whatthefat
Profile Blog Joined August 2010
United States918 Posts
Last Edited: 2011-10-14 05:54:49
October 14 2011 05:53 GMT
#13
On October 14 2011 14:49 Plexa wrote:
Somehow I get the feeling modular arithmetic isn't covered in this!
Perhaps not! Although it can help with some puzzles, even if it isn't the necessary or intended way to solve the puzzle. I'm not sure what difficulty level this test is at though.

I basically don't have much time to spend on this either. Think 2-4 hours tops. I just need to get through the basic stuff, then I have to move on to studying the logic puzzles and some other basic math.
EDIT: In that case, definitely don't worry about modular arithmetic. I would just familiarize yourself with some well known types of number sequences.
SlayerS_BoxeR: "I always feel sorry towards Greg (Grack?) T_T"
cz
Profile Blog Joined August 2007
United States3249 Posts
Last Edited: 2011-10-14 05:54:54
October 14 2011 05:54 GMT
#14
On October 14 2011 14:53 whatthefat wrote:
Show nested quote +
On October 14 2011 14:49 Plexa wrote:
Somehow I get the feeling modular arithmetic isn't covered in this!


Perhaps not! Although it can help with some puzzles, even if it isn't the necessary or intended way to solve the puzzle. I'm not sure what difficulty level this test is at though.


Test spans all difficulties. Starts off really easy then goes up to insanely hard / impossible. I'll find my level of competence / skill, and want to use a few hours of studying to increase that while I can. I'm just not sure how exactly.
PlutoNZ
Profile Joined February 2008
New Zealand410 Posts
October 14 2011 05:54 GMT
#15
On October 14 2011 14:40 Plexa wrote:
Well its hard to know what you define as medium to hard difficulty though for instance what level would you consider 1 1 2 6 24 120 X to be?

btw these are sequences not series :3

The next value is 720.

You could read this page: http://www.purplemath.com/modules/nextnumb.htm

If you want more help, give me some examples of the problems you will be doing.
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 05:55 GMT
#16
Also guys, since this is a government exam, sample questions are not given. I did it last year and remember that in general it starts really easy and gets ridiculously hard, and you start to fail at some point. Besides that there is no knowledge of it and no way to find out.
Jonoman92
Profile Blog Joined September 2006
United States9106 Posts
Last Edited: 2011-10-14 06:03:11
October 14 2011 06:01 GMT
#17
Not sure how one would study for this. But the advice already posted sounds decent.

On October 14 2011 14:40 whatthefat wrote:
I would make sure you know the most commonly used sequences. Specifically:
1) Know your squares and cubes
2) Know the Fibonacci sequence
3) Know the triangular numbers
4) Also be aware of modular arithmetic. The example you gave:
Show nested quote +
There's also trick stuff like 1,5,2,6,X with X being 3 as it's basically 1,2,X and 5,6,Y basic +1 pattern being interspliced together.
is actually an arithmetic progression in mod 7 (1, 1+4=5, 5+4=2, 2+4=6, 6+4=3).


Nevermind, just got it upon thinking what the modulus operator did back in Java.
cz
Profile Blog Joined August 2007
United States3249 Posts
October 14 2011 06:02 GMT
#18
On October 14 2011 14:54 SearingShadow wrote:
Show nested quote +
On October 14 2011 14:40 Plexa wrote:
Well its hard to know what you define as medium to hard difficulty though for instance what level would you consider 1 1 2 6 24 120 X to be?

btw these are sequences not series :3

The next value is 720.

You could read this page: http://www.purplemath.com/modules/nextnumb.htm

If you want more help, give me some examples of the problems you will be doing.


Thanks!! This is what I was looking for. I'm going to go through it tomorrow and see where I can get. After that I'll have to find some pretty hard sequences and see if I can do them.
cz
Profile Blog Joined August 2007
United States3249 Posts
Last Edited: 2011-10-14 06:04:59
October 14 2011 06:03 GMT
#19
On October 14 2011 15:01 Jonoman92 wrote:
Not sure how one would study for this. But the advice already posted sounds decent.

Show nested quote +
On October 14 2011 14:40 whatthefat wrote:
I would make sure you know the most commonly used sequences. Specifically:
1) Know your squares and cubes
2) Know the Fibonacci sequence
3) Know the triangular numbers
4) Also be aware of modular arithmetic. The example you gave:
There's also trick stuff like 1,5,2,6,X with X being 3 as it's basically 1,2,X and 5,6,Y basic +1 pattern being interspliced together.
is actually an arithmetic progression in mod 7 (1, 1+4=5, 5+4=2, 2+4=6, 6+4=3).


Hmm, could you explain that a bit more? I don't really see how from just 1,5,2,6,X it is clear that X=3 is next. Seems like there's insufficient information.


Yeah I guess it could be other stuff, but it was just as an example. I could rewrite it to 1,5,2,6,3,X and X = 7. It's just to show that sometimes there are very basic patterns (+1) but they are spliced together with another parallel sequence. There's also stuff like 1/2, 2/4, 3/8, 4/16, where it's adding +1 to the numerator and x2 for the denominator. If you were to rewrite that as a decimal it's hard/impossible to solve.
Shelke14
Profile Blog Joined April 2010
Canada6655 Posts
Last Edited: 2011-10-14 07:07:02
October 14 2011 07:06 GMT
#20
On October 14 2011 14:40 Plexa wrote:
Well its hard to know what you define as medium to hard difficulty though for instance what level would you consider 1 1 2 6 24 120 X to be?

btw these are sequences not series :3


X= 720?

OH shit, I didn't see the guy answered it a few posts above mine sorry! lol
Maenander
Profile Joined November 2002
Germany4926 Posts
Last Edited: 2011-10-14 08:12:36
October 14 2011 08:03 GMT
#21
The problem with sequences of integers is that they are ambiguous. I hate to construct a perfectly valid algorithm only to get to the "wrong" answer, because most tests allow for only one solution.
aike
Profile Blog Joined July 2010
United States1629 Posts
October 14 2011 08:25 GMT
#22
On October 14 2011 17:03 Maenander wrote:
The problem with sequences of integers is that they are ambiguous. I hate to construct a perfectly valid algorithm only to get to the "wrong" answer, because most tests allow for only one solution.


I think what they try to go for is the simplest answer. So if you are getting it wrong, you are probably thinking about it too much.

like with one of the above examples: 1,5,2,6,X is just 1+4 = 5 - 3 = 2 + 4 = 6 - 3 = 3 + 4 = 7 - 3 = 4 and so on
Wahaha
Bswhunter
Profile Blog Joined May 2010
Australia954 Posts
October 14 2011 10:03 GMT
#23
What year are you in? I am still in the Australian school system so it would be intresting to see how its changed.
Im going to guess your in year 8-9 thou
Stop browsing and do whatever it is you're supposed to do. TL will still be here when you get back
Cascade
Profile Blog Joined March 2006
Australia5405 Posts
October 14 2011 12:32 GMT
#24
For this kind of panic-studying, with the single purpose of doing well on this exam (no hidden agendas of actually learning anything...) I think the almost always best method is the exam-o-ez (transalted from the swedish word "tenta-lätt") method.

Namely: find old exams with full solutions. Study them, learn the solution algorithms, and learn (memorise almost) to reproduce the solutions from the problem only. Chances are that many of the question on this years exam are similar enough to some of the previous ones.
XXGeneration
Profile Blog Joined November 2010
United States625 Posts
October 14 2011 21:52 GMT
#25
One thing I would learn to do is finite differences; it'll really help in terms of the polynomials, but the speed may be slow.
"I was so surprised when I first played StarCraft 2. I couldn't believe that such an easy game exists... I guess the best way to attract people these days is to make things easy and simple." -Midas
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