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The Big Programming Thread - Page 671

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Thread Rules
1. This is not a "do my homework for me" thread. If you have specific questions, ask, but don't post an assignment or homework problem and expect an exact solution.
2. No recruiting for your cockamamie projects (you won't replace facebook with 3 dudes you found on the internet and $20)
3. If you can't articulate why a language is bad, don't start slinging shit about it. Just remember that nothing is worse than making CSS IE6 compatible.
4. Use [code] tags to format code blocks.
Blisse
Profile Blog Joined July 2010
Canada3710 Posts
Last Edited: 2015-10-25 03:30:25
October 24 2015 23:45 GMT
#13401
^ if you don't have problems you don't grow

On October 24 2015 17:35 WrathSCII wrote:
Hello everyone. Thank you OP for making this thread and sharing the other posts on the first post about learning C first and stuff. I'd like to participate in this thread and learn more about programming. My issue is not learning the language as syntax or how things work in the stack or windows API or other stuff, but not finding anything to practice this learning process on. My imagination is closer to -9000. So I can't really come up with some ideas to make software and practice my learning on it.

My work field as an administrator does not give me problems to be solved by using stuff like "memory optimizing" and other stuff I'd like to see like testing performance on certain programs.

I'd love if anyone can point me where I can find "ideas" on programs to develop even if they were already developed. The goal here is not commercial to sell. But a practice area, out of college homeworks and projects. I never got anything to practice my knowledge on.

Thanks.


Honestly a problem new programmers have is that they think that the idea matters. It doesn't. Every single idea you have will have been done in a form already. Just choose something and do it. Doing literally anything is better than nothing. If you don't have ideas just Google "simple programming projects" and choose one and go. Make command-line Tetris. I did that format a list of words into a maximum of X number of lines 5 pages back. Do that too. Just. Do. Something. Literally anything. It doesn't have to be pretty. It just has to do something.

You also need to problem solve more effectively. If you couldn't find any problems yourself, you need to fix that, because you can't be a good programmer if you get blocked from stuff like this, unless you meant to ask people here and you've done it yourself already..


I Bing'd "programming simple projects"

https://www.bing.com/search?q=programming simple projects&go=Submit&qs=n&form=QBRE&pq=programming simple project&sc=0-0&sp=-1&sk=&cvid=5e5f04881bf14f79b98d60945496c2af

https://www.reddit.com/r/learnprogramming/comments/2a9ygh/1000_beginner_programming_projects_xpost/
https://codeboom.wordpress.com/2012/07/30/10-mini-programming-projects/
http://www.nairaland.com/1272060/simple-programming-projects-beginners
https://blog.udemy.com/java-projects/

Same with Google

https://www.google.ca/?gfe_rd=cr&ei=mRosVrbcFMTV8QW5r7bwBA&gws_rd=ssl#q=programming simple projects

https://www.quora.com/What-are-some-great-programming-projects-for-beginners
http://inventwithpython.com/blog/2012/02/20/i-need-practice-programming-49-ideas-for-game-clones-to-code/
http://www.makeuseof.com/tag/5-project-ideas-help-learn-programming-faster/
There is no one like you in the universe.
Artesimo
Profile Joined February 2015
Germany546 Posts
Last Edited: 2015-10-26 20:47:20
October 26 2015 19:25 GMT
#13402
+ Show Spoiler +
For some reason, I struggle with this simple line of c. I am writing a UNIX shell in C at the moment and want to adress a certain file, even when I change the directory with cd/.

What I am currently using to log every input is:

FILE *filePointer = fopen("name", "ab+");


When I change directories, the next time I use the lines above, the new current directory gets picked. I dont wan't to hardcode the directory and filename by simply doing


path* = "C://...."
.
.
.
FILE *filePointer = fopen(path, "ab+");


I use this to get the current directory on start and combine it with a set filename, but fopen() no longer works then. Combining the strings works fine.

char* logfile_name = "logfile.txt";
char currentDirectory[1024];
getcwd(currentDirectory, sizeof(currentDirectory));
char* logfile = malloc(strlen(currentDirectory) +strlen("/") + strlen(logfile_name));
FILE *fp = fopen(logfile, "ab+");


Fuck it. Absolut directory it is. I won't do all this hassle for my first and only C-assignment this semester after which we immediately switch to java
spinesheath
Profile Blog Joined June 2009
Germany8679 Posts
October 26 2015 19:33 GMT
#13403
On October 27 2015 04:25 Artesimo wrote:
I use this to get the current directory on start and combine it with a set filename, but fopen() no longer works then. Combining the strings works fine.

char currentDirectory[1024];
getcwd(currentDirectory, sizeof(currentDirectory));
char* logfile = malloc(strlen(currentDirectory) +strlen("/") + strlen(logfile_name));
FILE *fp = fopen(logfile, "ab+");

I'd guess that is because you never write anything to the logfile array. Instead you just pass garbage to fopen.
If you have a good reason to disagree with the above, please tell me. Thank you.
Artesimo
Profile Joined February 2015
Germany546 Posts
Last Edited: 2015-10-26 19:39:27
October 26 2015 19:36 GMT
#13404
On October 27 2015 04:33 spinesheath wrote:
I'd guess that is because you never write anything to the logfile array. Instead you just pass garbage to fopen.

I do, I just forgot to add it, sorry about that. It is my first time with C, so my code is a mess and I oversaw it. As I said, if I check the merged string with printf() it gives me the complete path+filename, but I cant sue it on fopen();

EDIT: another fuckup on my part. It doesnt work properly. The / I added is missing, so it goes path1/path2/path3Filename instead of path1/path2/path3/Filename
AKnopf
Profile Blog Joined March 2011
Germany259 Posts
Last Edited: 2015-10-26 19:40:39
October 26 2015 19:39 GMT
#13405
On October 25 2015 03:10 Itsmedudeman wrote:
My tip would be don't be afraid to try and take on something a bit bigger than something you think you can handle. If you only do practice problems that you already know all that teaches you is memorization skills. When you work on a harder project you can learn so much more by being forced to branch out of your comfort zone and learn things you can't learn from a textbook by encountering your own unique problems and problem solving your way through them with whatever resource available.


Also, feel free to change the subject mid-way. Its your project after all.
I once wanted to write a simple game and ended up writing an extension to the object model of the language I was using - just because that one thing in the game library didn't seem to do its job in the most elegant way. I did not learn a thing about game programming but I learned a lot about the stuff my natural curiosity led me to. 100% win.
The world - its a funny place
WarSame
Profile Blog Joined February 2010
Canada1950 Posts
Last Edited: 2015-10-26 21:47:20
October 26 2015 21:46 GMT
#13406
Hey folks, I've got a question for you. I've been trying to do some challenges on /r/dailyprogrammer and got stuck on finding the distinct prime factors of an integer. Here's my attempt so far:


def findFactors(n):
factors=[]
f=2
while n!=1:
if (n%f)==0:
factors.append(f)
n/=f
else:
f+=1

return factors


However, this fails at the distinct part. I tried it with adding in things like "if not in factors" but then it would run indefinitely because it couldn't find a last factor.

For example, 492 was factored by 2 = 246, by 3=82, by 41=2, but then it's left with a 2, which is already used as a factor. I can't seem to figure out how 492 is even supposed to be factored, and I can't find any resources online that state the distinct prime factor for it, such as Wolfram.

The challenge, and some example code is here, but they seem to do the exact same thing.
Can it be I stayed away too long? Did you miss these rhymes while I was gone?
Mr. Wiggles
Profile Blog Joined August 2010
Canada5894 Posts
October 26 2015 22:19 GMT
#13407
On October 27 2015 06:46 WarSame wrote:
Hey folks, I've got a question for you. I've been trying to do some challenges on /r/dailyprogrammer and got stuck on finding the distinct prime factors of an integer. Here's my attempt so far:


def findFactors(n):
factors=[]
f=2
while n!=1:
if (n%f)==0:
factors.append(f)
n/=f
else:
f+=1

return factors


However, this fails at the distinct part. I tried it with adding in things like "if not in factors" but then it would run indefinitely because it couldn't find a last factor.

For example, 492 was factored by 2 = 246, by 3=82, by 41=2, but then it's left with a 2, which is already used as a factor. I can't seem to figure out how 492 is even supposed to be factored, and I can't find any resources online that state the distinct prime factor for it, such as Wolfram.

The challenge, and some example code is here, but they seem to do the exact same thing.

Think of a simple input, like factoring the number 4.

What should happen when a prime occurs multiple times in the factorization? Consider 2^3 = 8. It only has one distinct prime factor, 2, that is repeated 3 times. What about 2 * 2 * 3 * 3 = 36, which has distinct prime factors 2 and 3?

There is a simple addition to your program that would handle this case.
you gotta dance
WarSame
Profile Blog Joined February 2010
Canada1950 Posts
Last Edited: 2015-10-26 22:29:32
October 26 2015 22:27 GMT
#13408
Oh, I see. I misunderstood the question, I believe. By distinct primes they mean for you to only add each number to the factor list even if it happens more than once? Ex: 12 = 2*2*3, but the distinct prime factors would be 2,3, right?

EDIT: I've changed it to
def findFactors(n):
factors=[]
f=2
while n!=1:
while (n%f)==0:
if f not in factors:
factors.append(f)
n/=f
else:
f+=1

return factors
and have yet to see any problems. Thank you!
Can it be I stayed away too long? Did you miss these rhymes while I was gone?
Acrofales
Profile Joined August 2010
Spain17969 Posts
Last Edited: 2015-10-26 23:13:24
October 26 2015 23:08 GMT
#13409
On October 27 2015 07:27 WarSame wrote:
Oh, I see. I misunderstood the question, I believe. By distinct primes they mean for you to only add each number to the factor list even if it happens more than once? Ex: 12 = 2*2*3, but the distinct prime factors would be 2,3, right?

EDIT: I've changed it to
def findFactors(n):
factors=[]
f=2
while n!=1:
while (n%f)==0:
if f not in factors:
factors.append(f)
n/=f
else:
f+=1

return factors
and have yet to see any problems. Thank you!

That's python, so make it more pythonic and use a set instead of a list for unique items. If you don't like sets, you can get the same power by using a dictionary and returning the keys (secretly also a set).

Forgot to say that using a set is more legible, and allows you to remove that if statement.

Edit 2: just saw you have an indentation error around your else statement. Presumably that's just a quirk of pasting your code here? It should give a parse error.
WarSame
Profile Blog Joined February 2010
Canada1950 Posts
October 26 2015 23:20 GMT
#13410
The set suggestion is a good idea, and I'll go use that. Thanks!

The indentation error actually works fine - python allows for while/else loops. Yes, really. It also has some usability - if the while breaks out of the loop, it skips the else. If the while never runs, the else still does. If while finishes normally, the else runs afterwards. It was an error from me modifying the if though.
Can it be I stayed away too long? Did you miss these rhymes while I was gone?
Propelled
Profile Joined October 2010
Denmark184 Posts
October 27 2015 10:25 GMT
#13411
I've run into a minor problem while learning to use MongoDB. Whenever I try to query a collection for some specific fields, the order they get printed always remain the same. E.g.
db.users.find({}, {name: 1, password: 1});
returns identical to
db.users.find({}, {password: 1, name: 1});

I'm wondering if it is possible to change the order they get returned, similar to how it can be done in SQL, where
SELECT name, password FROM users
and
SELECT password, name FROM users
returns the same fields, but in different order.
I tried looking through the documentation for MongoDB, but I haven't been able to find anything.
Acrofales
Profile Joined August 2010
Spain17969 Posts
October 27 2015 11:04 GMT
#13412
I don't think you can. Mongo results are json-like objects and their field order depends on the underlying implementation (it's a form of tree structure that you shouldn't worry about). The projection thus only specifies what fields to include and not the order (which you should consider meaningless, because you cannot be sure about it and it can change arbitrarily). If you want to print them always in the same order, address that when printing. The following pseudo code illustrates it a bit better:
 print (result.name, result.password)

Manit0u
Profile Blog Joined August 2004
Poland17243 Posts
Last Edited: 2015-10-27 11:52:21
October 27 2015 11:52 GMT
#13413
Pretty much what Acrofales said. You shouldn't rely on your query to provide you with fields in certain order. You can always change it when printing data to the user. If you have to return it as raw data, without printing it (as a JSON response to be consumed by some API for example) then you should pass it through some data transformer which will ensure that your output is exactly what you want.
Time is precious. Waste it wisely.
Faust852
Profile Joined February 2012
Luxembourg4004 Posts
Last Edited: 2015-10-27 17:26:54
October 27 2015 17:25 GMT
#13414
Java noob here,
the ?: operation works only when you want to affect a value ? like
String foo = num.isOdd "yes" : "no"


I wanted to do something like :

InetAddress ia = InetAddress.getByName(textFieldIP.getText()); 
//get the IP address
ia.isReachable(3000) ? lblResult.setText("Success") : lblResult.setText("Failure");
//write either Success or Failure if the IP is reachable

And it doesn't work. When I do a dumb if/else, it works without any issue.
solidbebe
Profile Blog Joined November 2010
Netherlands4921 Posts
October 27 2015 17:37 GMT
#13415
I'm fairly sure that doesn't work because ? : just returns a value like so:

max = (a > b) ? a : b;

Might be wrong though.
That's the 2nd time in a week I've seen someone sig a quote from this GD and I have never witnessed a sig quote happen in my TL history ever before. -Najda
Ropid
Profile Joined March 2009
Germany3557 Posts
October 27 2015 17:47 GMT
#13416
I guess you would do this if you want to use ?:

lblResult.setText( ia.isReachable(3000) ? "Success" : "Failure" );
"My goal is to replace my soul with coffee and become immortal."
Faust852
Profile Joined February 2012
Luxembourg4004 Posts
Last Edited: 2015-10-27 18:11:52
October 27 2015 18:11 GMT
#13417
On October 28 2015 02:47 Ropid wrote:
I guess you would do this if you want to use ?:

lblResult.setText( ia.isReachable(3000) ? "Success" : "Failure" );


Oh yeah thank you very much ! Seems obvious now that I see it.
Manit0u
Profile Blog Joined August 2004
Poland17243 Posts
October 28 2015 02:55 GMT
#13418
I still wouldn't put a ternary as function param.


String result = ia.isReachable(3000) ? "Success" : "Failure";

lblResult.setText(result);
Time is precious. Waste it wisely.
WarSame
Profile Blog Joined February 2010
Canada1950 Posts
Last Edited: 2015-10-28 03:48:32
October 28 2015 03:37 GMT
#13419
Are we allowed to post code here just for code review/efficiency? I have some code I wrote for a /r/dailyprogrammer challenge that is taking me about a half hour to run, but someone said that they got their version to run in under a second, so I'd like to see where the improvement could be made.
EDIT: After about an hour of looking at it, I finally found the difference right after posting. It's amazing what one line can do.

The slow version:


import itertools, operator, math

def combo(s,v):#alias function
return itertools.combinations_with_replacement(s,v)

def findLims(numDig):
return 10**(numDig-1),10**(numDig)

def numDigits(n):
return int(math.log10(n))+1

def main():
numDig, numFang=map(int,raw_input().split())
#vampire can be in this range
vampBot,vampTop=findLims(numDig)
fangBot,fangTop=findLims(numDig/numFang)
print vampBot,vampTop
vampires={}#dict containing all vampires in vamprange
for fang in combo(range(fangBot,fangTop),numFang):
#combo for 10 to 99 returns 10,11,12,etc.
#multiply the combination values together
vampire=reduce(operator.mul,fang)
vampLen=numDigits(vampire)
if vampLen!=numDig:
continue
fangDig=sorted(''.join(map(str,fang)))
vampDig=sorted(str(vampire))
if vampire in range(vampBot,vampTop):
if fangDig == vampDig:
vampires[vampire]=fang
print fang
for v,f in sorted(vampires.items()):
print "{}={}".format(v,'*'.join(map(str,f)))

main()


The fast version simply removes that "if vampire in range(vampBot,vampTop)" and the program runs in half a second, or about 1/3600 the time.
Can it be I stayed away too long? Did you miss these rhymes while I was gone?
_Grazze_
Profile Blog Joined December 2006
834 Posts
October 28 2015 15:25 GMT
#13420
+ Show Spoiler +

package test;

import javax.swing.JOptionPane;


public class ChangeCalculator {




public static void main(String[] args) {




String price = JOptionPane.showInputDialog("Enter price:");
String paid = JOptionPane.showInputDialog("How much did you pay with?");

double num1 = Double.parseDouble(price);
double num2 = Double.parseDouble(paid);

double change = num2 - num1;

if(num1 > num2){
JOptionPane.showMessageDialog (null, "Invalid entry!", "Warning", JOptionPane.WARNING_MESSAGE);
System.exit(1);
}

int remainingChange = (int) change * 100;

int numberOfHundredsEuros = remainingChange / 10000;
remainingChange = remainingChange % 10000;

int numberOfFiftyEuros = remainingChange / 5000;
remainingChange = remainingChange % 5000;

int numberOfTwentyEuros = remainingChange / 2000;
remainingChange = remainingChange % 2000;

int numberOfTenEuros = remainingChange / 1000;
remainingChange = remainingChange % 1000;

int numberOfFiveEuros = remainingChange / 500;
remainingChange = remainingChange % 500;

int numberOfTwoEuros = remainingChange / 200;
remainingChange = remainingChange % 200;

int numberOfOneEuros = remainingChange / 100;
remainingChange = remainingChange % 100;

int numberOfFiftyCents = remainingChange / 50;
remainingChange = remainingChange % 50;

int numberOfTwentyCents = remainingChange / 20;
remainingChange = remainingChange % 20;

int numberOfTenCents = remainingChange / 10;
remainingChange = remainingChange % 10;

int numberOfFiveCents = remainingChange / 5;
remainingChange = remainingChange % 5;

int rest = remainingChange;

String myString =

"Your amount " + change + " consists of: \n" +
"100 Euros: " + numberOfHundredsEuros + "\n" +
"50 Euros: " + numberOfFiftyEuros + "\n" +
"20 Euros: " + numberOfTwentyEuros + "\n" +
"10 Euros: " + numberOfTenEuros + "\n" +
"5 Euros: " + numberOfFiveEuros + "\n" +
"2 Euros: " + numberOfTwoEuros + "\n" +
"1 Euros: " + numberOfOneEuros + "\n" + "\n" +
"50 Cents: " + numberOfFiftyCents + "\n" +
"20 Cents: " + numberOfTwentyCents + "\n" +
"10 Cents: " + numberOfTenCents + "\n" +
"5 Cents: " + numberOfFiveCents + "\n" +
"Remaining Cents: " + rest;




JOptionPane.showMessageDialog(null, myString);



}
}


Yo dudes! I'm trying to program a change calcuator in Java for an assignment I have in school. It works kinda okay but it wont print out cents. Any ideas?

Code in spoiler.
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