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noob phys question

Blogs > nAi.PrOtOsS
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nAi.PrOtOsS
Profile Blog Joined August 2007
Canada784 Posts
September 17 2008 02:02 GMT
#1
How do i find the slope on a linear log-log graph?

*
Caller
Profile Blog Joined September 2007
Poland8075 Posts
September 17 2008 02:10 GMT
#2
rise over the run
Watch me fail at Paradox: http://www.teamliquid.net/forum/viewmessage.php?topic_id=397564
Ilikestarcraft
Profile Blog Joined November 2004
Korea (South)17743 Posts
September 17 2008 02:21 GMT
#3
wtf ;;;
ils
"Nana is a goddess. Or at very least, Nana is my goddess." - KazeHydra
IzzyCraft
Profile Blog Joined June 2007
United States4487 Posts
Last Edited: 2008-09-17 02:22:36
September 17 2008 02:22 GMT
#4
that isnt phys lol nessarly
It's best fit line
I have ass for brains so,
even when I shit I'm droping knowledge.
Ilikestarcraft
Profile Blog Joined November 2004
Korea (South)17743 Posts
September 17 2008 02:26 GMT
#5
1+1=11?
ils
"Nana is a goddess. Or at very least, Nana is my goddess." - KazeHydra
fusionsdf
Profile Blog Joined June 2006
Canada15390 Posts
September 17 2008 02:38 GMT
#6
1+1=0
SKT_Best: "I actually chose Protoss because it was so hard for me to defeat Protoss as a Terran. When I first started Brood War, my main race was Terran."
IntoTheWow
Profile Blog Joined May 2004
is awesome32278 Posts
September 17 2008 02:39 GMT
#7
On September 17 2008 11:26 Ilikestarcraft wrote:
1+1=11?


1+1 = 1
1+1 = 10
1+1 = 2
Moderator<:3-/-<
IntoTheWow
Profile Blog Joined May 2004
is awesome32278 Posts
September 17 2008 02:41 GMT
#8
Slope?

Find the derivative of the function and evaluate in the point where you want to find the slope.
Moderator<:3-/-<
Purind
Profile Blog Joined April 2004
Canada3562 Posts
September 17 2008 02:44 GMT
#9
rise over run

I reckon the next question is gonna be "what does rise over run on a log log graph mean?"
Trucy Wright is hot
XCetron
Profile Joined November 2006
5226 Posts
September 17 2008 02:44 GMT
#10
Delta square over triforce
caelym
Profile Blog Joined June 2008
United States6429 Posts
September 17 2008 02:47 GMT
#11
u live in canada, so just look out the window
imperfect
Profile Blog Joined July 2008
Canada1652 Posts
September 17 2008 02:55 GMT
#12
I'm not sure about what I'm writing (i just learned this in physics too):

after graphing the line, just simply measure the slope with a ruler?

ie: rise over run, which would mean for example, 25mm over 50 mm or something like that in which case the slope would be 1/2.
blind bisu free and anytime fanboy.
nAi.PrOtOsS
Profile Blog Joined August 2007
Canada784 Posts
September 17 2008 03:03 GMT
#13
Ok so my teacher says that as long as the log-log graph is linear then it's correct and you can find the slope and then use that in other calculations. Is it possible tho, to have a linear log-log graph but be completely wrong? so the slope of that incorrect linear line would completely mess up all the calculations?
IntoTheWow
Profile Blog Joined May 2004
is awesome32278 Posts
September 17 2008 03:08 GMT
#14
If a function is linear (be it in all the space or just in some part) the slope is constant and that's why you can use it to calculate things. If the function has curves, it's slope changes from point to point.

As long as you stay in range (where the slope is constant, and the function is linear) your calculations will be fine.
Moderator<:3-/-<
economist_
Profile Blog Joined April 2008
Vietnam719 Posts
September 17 2008 03:30 GMT
#15
Take the derivative of the log-log functionn, if that is constant then slope is constant. If that is function instead then you cannot use for cals cause it is function.
Linear function always has the constant slope...
Economics forecast assumes everything, except responsibilities
micronesia
Profile Blog Joined July 2006
United States24776 Posts
September 17 2008 03:53 GMT
#16
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!
ModeratorThere are animal crackers for people and there are people crackers for animals.
IntoTheWow
Profile Blog Joined May 2004
is awesome32278 Posts
September 17 2008 04:07 GMT
#17
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!


Wouldn't it be "Over 3.95424251!!!"?
Moderator<:3-/-<
IzzyCraft
Profile Blog Joined June 2007
United States4487 Posts
September 17 2008 04:20 GMT
#18
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!

Doesn't matter slope is always best fit line or learn how to write algorithms.
I have ass for brains so,
even when I shit I'm droping knowledge.
micronesia
Profile Blog Joined July 2006
United States24776 Posts
September 17 2008 04:35 GMT
#19
On September 17 2008 13:20 IzzyCraft wrote:
Show nested quote +
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!

Doesn't matter slope is always best fit line or learn how to write algorithms.

Wat? I was just saying some people were assuming the question was 'how do I find slope' even though the OP obviously knows how to find the slope of a line lol
ModeratorThere are animal crackers for people and there are people crackers for animals.
Hypnosis
Profile Blog Joined October 2007
United States2061 Posts
September 17 2008 04:53 GMT
#20
mx+b
Science without religion is lame, Religion without science is blind
Purind
Profile Blog Joined April 2004
Canada3562 Posts
September 17 2008 04:53 GMT
#21
On September 17 2008 12:03 nAi.PrOtOsS wrote:
Ok so my teacher says that as long as the log-log graph is linear then it's correct and you can find the slope and then use that in other calculations. Is it possible tho, to have a linear log-log graph but be completely wrong? so the slope of that incorrect linear line would completely mess up all the calculations?


Depends on what you're graphing.

If it's supposed to be exponential, then I think it should be linear on a log log
Trucy Wright is hot
Underwhelmed
Profile Blog Joined January 2008
United States207 Posts
September 17 2008 06:30 GMT
#22
I assume you have taken data points and are plotting them on a log(x) vs log(y) graph. So basically, log(y_2) - log(y_1) / log(x_2) - log(x_1).
Ilikestarcraft
Profile Blog Joined November 2004
Korea (South)17743 Posts
Last Edited: 2008-09-17 07:13:40
September 17 2008 07:04 GMT
#23
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!

i dont know what log log is im just sortof annoyed because ops been making a lot of threads like this lately. Im not saying asking for help is bad i used to make threads like these too.
ils
"Nana is a goddess. Or at very least, Nana is my goddess." - KazeHydra
jgad
Profile Blog Joined March 2008
Canada899 Posts
September 17 2008 07:39 GMT
#24
On September 17 2008 13:20 IzzyCraft wrote:
Show nested quote +
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!

Doesn't matter slope is always best fit line or learn how to write algorithms.


That's not true. If you plot a straight line (linear function) on a log-log graph you get a straight line with a slope of 1, regardless of what the slope would be on a linear-linear graph. If you plot a quadratic equation on a log-log graph, you get a straight line with a slope of 2, not a curving line. My guess is that this exercise is about learning to interpret the shape of plots in logarithmic form and to understand the congruency between different forms of the same plot.
콩까지마
jgad
Profile Blog Joined March 2008
Canada899 Posts
September 17 2008 07:43 GMT
#25
On September 17 2008 13:53 Purind wrote:
Show nested quote +
On September 17 2008 12:03 nAi.PrOtOsS wrote:
Ok so my teacher says that as long as the log-log graph is linear then it's correct and you can find the slope and then use that in other calculations. Is it possible tho, to have a linear log-log graph but be completely wrong? so the slope of that incorrect linear line would completely mess up all the calculations?


Depends on what you're graphing.

If it's supposed to be exponential, then I think it should be linear on a log log


Nah, exponential still curves on a log-log graph. It's a straight line on a log-lin graph.
콩까지마
sigma_x
Profile Joined March 2008
Australia285 Posts
September 17 2008 07:43 GMT
#26
to find the gradient of a log log graph, put your points on log log graph paper, and find the slope. Since this is physics, (and points won't lie neatly on a linear graph) doing it any other way will not get you the answer, unless finding L1 approximations using the [dual of a] simplex is your cup of tea.

"Ok so my teacher says that as long as the log-log graph is linear then it's correct and you can find the slope and then use that in other calculations. Is it possible tho, to have a linear log-log graph but be completely wrong? so the slope of that incorrect linear line would completely mess up all the calculations?"
This will depend on what your actually trying to find. This will be fine if you the actual question features a linear component in logs. For example, y=1/2 g t^2 [which is the distance travelled by a falling object due to gravity] can be put in the form y=mx+b by taking logs of both side.

so, logy=2(logt) +log(1/2 g), which is linear on a log log graph.

Notice that in this example, the gradient tells you the power of "t", so if your gradient is roughly "2" it shouldn't interfere with your calculations too much.
Maenander
Profile Joined November 2002
Germany4926 Posts
September 17 2008 07:56 GMT
#27
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!

If the OP asks stupid questions, he gets stupid answers. That´s perfectly fine.
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
September 17 2008 08:54 GMT
#28
Would it be something like

log(y) = slope*log(x) + intercept
10^log(y) = 10^(slope*log(x) + intercept)
y = x^slope*10^intercept

y = (10^intercept)*x^slope

?
Do you really want chat rooms?
micronesia
Profile Blog Joined July 2006
United States24776 Posts
September 17 2008 10:19 GMT
#29
On September 17 2008 16:56 Maenander wrote:
Show nested quote +
On September 17 2008 12:53 micronesia wrote:
What percent of the people here responded while having no idea what log-log means?

+ Show Spoiler +
OVER 9000!

If the OP asks stupid questions, he gets stupid answers. That´s perfectly fine.

He's asked too many questions lately, and the OP was too short, and he could have been more clear, but it wasn't actually stupid imo. Not his fault people don't know what log-log is but reply anyway.
ModeratorThere are animal crackers for people and there are people crackers for animals.
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