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Latin, Math, and some probability theory.

Blogs > Recognizable
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Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
Last Edited: 2013-03-13 17:30:26
January 17 2013 14:09 GMT
#1
-

*
lcms
Profile Joined September 2011
Netherlands27 Posts
January 17 2013 14:19 GMT
#2
Concerning the chances:
There are 4*3*2*1 = 24 different arrangements of pairs of which one is the correct one, so 1/24th i'd say :-)
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
January 17 2013 14:22 GMT
#3
On January 17 2013 23:19 lcms wrote:
Concerning the chances:
There are 4*3*2*1 = 24 different arrangements of pairs of which one is the correct one, so 1/24th i'd say :-)


Ah, thanks. That makes a lot more sense than what I did.
Smancer
Profile Blog Joined December 2010
United States379 Posts
January 17 2013 14:34 GMT
#4
I have a couple of degrees in Mathematics and I have taught High school level (everything from Algebra to Calculus).

If you really understand algebra, and you still find that you are making mistakes, try improving your handwriting. When you write neater, you force yourself to slow down. This just may help to avoid 1 or two mistakes that you make.

Its out of the box advice, but I have seen it work before.
A good way to threaten somebody is to light a stick of dynamite. Then you call the guy and hold the burning fuse up to the phone. "Hear that?" you say. "That's dynamite, baby."
duckett
Profile Blog Joined June 2009
United States589 Posts
January 17 2013 14:43 GMT
#5
making computation mistakes is a good problem to have - its much harder to solve problems with building conceptual understanding. if you're making that type of mistake, the answer is to do a lot more problems of the exact type that has been giving you trouble. you'd be surprised by you fluent you'll get with the computations
funky squaredance funky squaredance funky squaredance
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
Last Edited: 2013-01-17 14:54:20
January 17 2013 14:44 GMT
#6
On January 17 2013 23:34 Smancer wrote:
I have a couple of degrees in Mathematics and I have taught High school level (everything from Algebra to Calculus).

If you really understand algebra, and you still find that you are making mistakes, try improving your handwriting. When you write neater, you force yourself to slow down. This just may help to avoid 1 or two mistakes that you make.

Its out of the box advice, but I have seen it work before.


This is something I noticed as well but I've only been trying to improve it for about a month. My handwriting is absolutely terrible. I remember messing up a test a year ago because my P looks exactly like an 8 for some reason. Teacher told me he had to fail me. It's a slow process tho, and sometimes laziness kicks in and I go back to my terrible handwriting. I don't think I really understand Algebra. I can apply all the rules. But truly understanding? I don't really. It's never explained sadly, they only show that. Yes, it really does work with numbers. For some things I have an intuitive understanding, but for others I have not. It's such a pain to improve on this. I can just remember it and solve ten problems. Or I can try to get some kind of understanding for these rules but I won't get any practice.


making computation mistakes is a good problem to have - its much harder to solve problems with building conceptual understanding.


Yes, I'm happy this is the biggest problem as well. Still, my biggest fear is that someday I can't understand it conceptually anymore because it has gotten too hard. Hope that never happens. It's intruiging to see my Chemistry class where half the people just don't understand these things conceptually and fails hard, and the other half understands everything and gets amazing grades because the tests are made a bit easier because of the other half failing hard. I wonder why they don't understand it conceptually. I have no doubts that they can, they just aren't being taught right/thinking right. I was trying to explain something to somebody sitting next to me and she never thought of trying to visualize, for example, the titration itself whilst doing problems on titration. The other thing I have noticed is that they don't really want to learn. They have this mindset that they can't ever understand, which is sad.
duckett
Profile Blog Joined June 2009
United States589 Posts
January 17 2013 14:53 GMT
#7
On January 17 2013 23:44 Recognizable wrote:
The other thing I have noticed is that they don't really want to learn. They have this mindset that they can't ever understand, which is sad.

very insightful - it's often the case that the biggest barrier to learning concepts in math and science is the perception that it is too hard or I am too dumb etc. overcome that and you're well on your way to becoming a strong mathematical thinker
funky squaredance funky squaredance funky squaredance
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
January 17 2013 14:59 GMT
#8
On January 17 2013 23:53 duckett wrote:
Show nested quote +
On January 17 2013 23:44 Recognizable wrote:
The other thing I have noticed is that they don't really want to learn. They have this mindset that they can't ever understand, which is sad.

very insightful - it's often the case that the biggest barrier to learning concepts in math and science is the perception that it is too hard or I am too dumb etc. overcome that and you're well on your way to becoming a strong mathematical thinker


This is why Math/Physics is so great. I look at the stuff I had to do two/three years ago and I'm stunned I had ever any trouble understanding any of that. The only thing I am struggling with is geometric proofs. Many people are. It's a different way of problem solving, but I'm definitely getting a lot better and it was only a year ago that I thought I can never understand this.
Smancer
Profile Blog Joined December 2010
United States379 Posts
January 17 2013 15:06 GMT
#9
On January 17 2013 23:44 Recognizable wrote:
don't think I really understand Algebra. I can apply all the rules. But truly understanding? I don't really. It's never explained sadly, they only show that. Yes, it really does work with numbers. For some things I have an intuitive understanding, but for others I have not.



Haha, there are parts of algebra that I don't really understand either. Serge Lang is my arch nemesis. He treats tensor products about as elegantly as an elephant on a balance beam.

Anyway, I am curious to see if I can help. If there are things you really never had explained and don't understand, I can try. If not good luck in school!
A good way to threaten somebody is to light a stick of dynamite. Then you call the guy and hold the burning fuse up to the phone. "Hear that?" you say. "That's dynamite, baby."
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
Last Edited: 2013-01-17 15:33:34
January 17 2013 15:14 GMT
#10
On January 18 2013 00:06 Smancer wrote:
Show nested quote +
On January 17 2013 23:44 Recognizable wrote:
don't think I really understand Algebra. I can apply all the rules. But truly understanding? I don't really. It's never explained sadly, they only show that. Yes, it really does work with numbers. For some things I have an intuitive understanding, but for others I have not.



Haha, there are parts of algebra that I don't really understand either. Serge Lang is my arch nemesis. He treats tensor products about as elegantly as an elephant on a balance beam.

Anyway, I am curious to see if I can help. If there are things you really never had explained and don't understand, I can try. If not good luck in school!


Primitives. I mean, I understand all that jazz with rectangles for primitives but. Why is:F(x)=x ln(x) - x + c -->f(x)=ln(x) --> f'(x)=1/x. The great thing is. They show you that x ln(x) - x + c really is the primitive of ln(x) because if you differentiate x ln(x) - x you get ln(x) again! Haha. I also don't really have an understanding of the primitive function. You get a function, but what does this function represent? When you put in an X, what do you get, what is F(x)? I guess it's the surface between 0 and X for the original function, but again, why does this function represent the surface?
Nehsb
Profile Joined May 2009
United States380 Posts
Last Edited: 2013-01-17 16:32:36
January 17 2013 16:21 GMT
#11
On January 18 2013 00:06 Smancer wrote:
Show nested quote +
On January 17 2013 23:44 Recognizable wrote:
don't think I really understand Algebra. I can apply all the rules. But truly understanding? I don't really. It's never explained sadly, they only show that. Yes, it really does work with numbers. For some things I have an intuitive understanding, but for others I have not.



Haha, there are parts of algebra that I don't really understand either. Serge Lang is my arch nemesis. He treats tensor products about as elegantly as an elephant on a balance beam.

Anyway, I am curious to see if I can help. If there are things you really never had explained and don't understand, I can try. If not good luck in school!


If you don't already know it, maybe you should try reading some algebraic geometry (in particular some scheme theory.) So much of algebra becomes so much clearer when worded in terms of algebraic geometry...

Tensor products of rings become fibered products of schemes, tensor product of a ring and a module becomes pullback of a sheaf, and tensor product of modules is some notion of "twisting a sheaf by another sheaf."

It's unfortunate that a lot of the algebra is clarified by scheme-theoretic algebraic geometry, but scheme-theoretic algebraic geometry requires too many prerequisites to be used to actually show the intuition behind the algebra...

On January 18 2013 00:14 Recognizable wrote:
Show nested quote +
On January 18 2013 00:06 Smancer wrote:
On January 17 2013 23:44 Recognizable wrote:
don't think I really understand Algebra. I can apply all the rules. But truly understanding? I don't really. It's never explained sadly, they only show that. Yes, it really does work with numbers. For some things I have an intuitive understanding, but for others I have not.



Haha, there are parts of algebra that I don't really understand either. Serge Lang is my arch nemesis. He treats tensor products about as elegantly as an elephant on a balance beam.

Anyway, I am curious to see if I can help. If there are things you really never had explained and don't understand, I can try. If not good luck in school!


Primitives. I mean, I understand all that jazz with rectangles for primitives but. Why is:F(x)=x ln(x) - x + c -->f(x)=ln(x) --> f'(x)=1/x. The great thing is. They show you that x ln(x) - x + c really is the primitive of ln(x) because if you differentiate x ln(x) - x you get ln(x) again! Haha. I also don't really have an understanding of the primitive function. You get a function, but what does this function represent? When you put in an X, what do you get, what is F(x)? I guess it's the surface between 0 and X for the original function, but again, why does this function represent the surface?


Hmm, so I'll try to clarify some things:

As to why this primitive represents the surface: I think the right way to do this is to start from the function that is the area of the surface, and not to start from the primitive. If you have a function f, then the Riemann integral of f is not defined as the primitive (which unfortunately some calculus textbooks do, and IMO it's a terrible way to do things if you want to really understand what's going on.) The Riemann integral of f is defined as a certain Riemann sum which represents the area under f.

However, in practice, this explicit Riemann sum is often annoying to calculate. But we have the very convenient fact that if g is the integral from 0 to x of f, then the derivative of g is f. The reason for this is that if you slightly increase x, the area should change as fast as f(x). (This should be clearer with a good diagram, but I don't have one.)

This means that you have the following computational technique to find this function g: Find some function h such that the derivative of h is f. Then, the derivative of g-h is 0, but it is a theorem in calculus (usually proven with Mean Value Theorem) that the only functions with derivative 0 are constant functions. So g must be a constant off of h, and you just need to find the constant.

So, in my opinion, it's not so much "a primitive represents the area of the surface" but "the area of the surface should be a primitive, and all primitives differ from each other by a constant."

I'm not exactly very good at explaining things, so I'm sorry if this doesn't make sense.
duckett
Profile Blog Joined June 2009
United States589 Posts
January 17 2013 16:29 GMT
#12
mm people having too much fun exploiting the degeneracy of the word algebra.
funky squaredance funky squaredance funky squaredance
King Geedorah
Profile Blog Joined October 2012
190 Posts
January 17 2013 19:07 GMT
#13
Name thief, how dare you.
Render unto Geedorah what is Geedorah's
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
Last Edited: 2013-01-17 19:11:32
January 17 2013 19:09 GMT
#14
As to why this primitive represents the surface: I think the right way to do this is to start from the function that is the area of the surface, and not to start from the primitive. If you have a function f, then the Riemann integral of f is not defined as the primitive (which unfortunately some calculus textbooks do, and IMO it's a terrible way to do things if you want to really understand what's going on.) The Riemann integral of f is defined as a certain Riemann sum which represents the area under f.

However, in practice, this explicit Riemann sum is often annoying to calculate. But we have the very convenient fact that if g is the integral from 0 to x of f, then the derivative of g is f. The reason for this is that if you slightly increase x, the area should change as fast as f(x). (This should be clearer with a good diagram, but I don't have one.)

This means that you have the following computational technique to find this function g: Find some function h such that the derivative of h is f. Then, the derivative of g-h is 0, but it is a theorem in calculus (usually proven with Mean Value Theorem) that the only functions with derivative 0 are constant functions. So g must be a constant off of h, and you just need to find the constant.

So, in my opinion, it's not so much "a primitive represents the area of the surface" but "the area of the surface should be a primitive, and all primitives differ from each other by a constant."


Took me half an hour or so. But I believe I understand ^.^ The bolded part is indeed how I used to think about integrals. Basically, x times f(x) is the the F(x) and the area changes as ''fast'' as f(x) so therefore the derative of F(x) is f(x). Right?

Name thief, how dare you.


Sir, I believe it's the other way around.
hypercube
Profile Joined April 2010
Hungary2735 Posts
January 17 2013 20:08 GMT
#15
Just slow down a little and write out more steps. You'll find that it actually saves time.

Also try to figure out what kind of mistakes are you usually making, so you'll know where you need to pay extra attention.

Most of high school math as well as a lot of university math for engineering and science comes down to a few key concepts and lots of algorithmic computation. Maybe it's necessary maybe it isn't, but it is what it is. The way to learn algorithms is through solving exercises and eliminating typical mistakes one by one.
"Sending people in rockets to other planets is a waste of money better spent on sending rockets into people on this planet."
BigFan
Profile Blog Joined December 2010
TLADT24920 Posts
January 17 2013 20:35 GMT
#16
I think more practice and writing more clearly will definitely help you. Also, step at a time
Former BW EiC"Watch Bakemonogatari or I will kill you." -Toad, April 18th, 2017
sam!zdat
Profile Blog Joined October 2010
United States5559 Posts
January 17 2013 21:00 GMT
#17
What are you reading in Latin?
shikata ga nai
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
Last Edited: 2013-01-17 21:51:17
January 17 2013 21:21 GMT
#18
On January 18 2013 06:00 sam!zdat wrote:
What are you reading in Latin?


Seneca, not very exciting. But it's pretty easy to translate compared to other things I've had or maybe I'm just getting better at translating. After a while you really get used to his style and his metaphors are nice.
De Ira, Ad Helviam Matrem, De Tranquilitate Animi, De Constantia Sapientis, Epistulae Morales and De Clementia I believe. We translate a selection of these works and we have to understand the content/philosophy. Which is where I usually get all my points from :p, However this test was only about translation. The more I learn Latin the more I appreciate it actually. I don't really understand why I've never exerted myself for this class, lotsa shitty teachers, but right now I have a very good one who is also invested in helping me improve which is great. For that matter I haven't exerted myself a lot the past 5 years. I don't say I regret it, a lot, because my grades are still good. However if I had been as motivated as I am right now I could've been way ahead at everything, but it's really hard to challenge yourself when you can get a passing grade without effort. I see it with a lot of my classmates. The Dutch education system really fails in this aspect. There are literally zero incentives whatsoever to get a grade beyond one that is passible. How do you think they 'fixed' this issue? Yes, by raising the minimum requirements. The US does this a lot better, but it fails were the Dutch system excels at and that is giving everyone equal chances and creative thought is encouraged, which asia seems to be struggling with. For my exam program for History they state explicitly that they don't want to encourage regurgitation.
sam!zdat
Profile Blog Joined October 2010
United States5559 Posts
January 18 2013 03:28 GMT
#19
On January 18 2013 06:21 Recognizable wrote:
The more I learn Latin the more I appreciate it actually.


You will find this to be a robust trend. Keep studying Latin! Beautiful language.
shikata ga nai
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
Last Edited: 2013-01-18 18:33:41
January 18 2013 18:33 GMT
#20
Got a 5.7/10 for latin, which means I improved my grade by 42 percent compared to my last translation. Happy with this, hoped for higher, but I knew that would've been unrealistic. 8.0/10 for Math. Was aiming for at least an 8.5 or higher, it is however higher than I expected because the test went so abysmal. Decent results, I'll just try to improve on the things I need to improve upon. You learn a great amount of things during tests. It is the only time you really look critically at your mistakes.
BirdKiller
Profile Joined January 2011
United States428 Posts
Last Edited: 2013-01-18 20:04:58
January 18 2013 20:01 GMT
#21
On January 19 2013 03:33 Recognizable wrote:
Got a 5.7/10 for latin, which means I improved my grade by 42 percent compared to my last translation. Happy with this, hoped for higher, but I knew that would've been unrealistic. 8.0/10 for Math. Was aiming for at least an 8.5 or higher, it is however higher than I expected because the test went so abysmal. Decent results, I'll just try to improve on the things I need to improve upon. You learn a great amount of things during tests. It is the only time you really look critically at your mistakes.


I disagree with tests being the only time where you would look critically at your mistakes. In mathematics, you need to look critically at ALL of your mistakes, whether it occurred in class, homework, or whatever else. Some mistakes you can easily dismiss as being human (ex: 2 + 3 = 6) but a lot of mistakes, from my experience in math, require more thought and correction (What made you think of the wrong answer? What was the correct answer? How/Why is that the correct answer? Why didn't I think of that correct answer? Was my thinking far off or does it just need tweaking?)

Also, you shouldn't be learning anything from taking tests. That's generally a sign that you did not either study well or came into the classroom lacking sufficient knowledge. There are some math tests written by few professors that makes students "build up" their current knowledge to create a new one, but those are rare. I would say being reminded of something that you learned but blanked out during testing is really the only thing you should learn from tests.
Recognizable
Profile Blog Joined December 2011
Netherlands1552 Posts
January 18 2013 20:52 GMT
#22
Some mistakes you can easily dismiss as being human (ex: 2 + 3 = 6) but a lot of mistakes, from my experience in math, require more thought and correction (What made you think of the wrong answer? What was the correct answer? How/Why is that the correct answer? Why didn't I think of that correct answer? Was my thinking far off or does it just need tweaking?)


I agree but the bolded part is where most of my mistakes right now are coming from. Forgetting to read the question right, forgetting to carry over pi, forgetting to multiply one variable with minus one, forgetting to show that yes the graph really does go through (0.0), misreading the question and calculating the volume when the graph circles around the x-axis instead of the y-axis. What I've learnt is that I shouldn't speed read. This is great when they give you a page of information during History and you have to only find the important things, but during math I really need to read the question carefully. For example, I tried to solve something by hand which should've been done with the calculator. I also need to pay more attention to all my algebraic steps and try to find some sort of routine that eliminates mistakes. Before the test I just never saw these mistakes as significant. Altough I make them all the freaking time, but really it costed me so much that I've realized that this is something I should focus on. Apart from that I didn't learn new material, but the questions were definitely not in proportion to the homework questions so they forced me to think a little bit deeper about the matieral.
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