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letsbefree
Canada123 Posts
I have a math problem i need to solve, although it sounds easy but i just can't get the answer, can someone help me out? Find the equation of the tangent line of y = x+3 (whole thing squared rooted) at point (6,3). Please don't use derivatives to solve it. Thank you.=)  | ||
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Nitrogen
United States5345 Posts
edit: oops i meant x values | ||
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paper
13196 Posts
1/6? i fail at math | ||
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evanthebouncy!
United States12796 Posts
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evanthebouncy!
United States12796 Posts
Read it, understand it, follow the example WITH A PICTURE LIKE YOU SHOULD DRAW A PICTURE(graph) AND SEE IF IT MAKES SENSE If that still doesn't help shoot me a pm and we'll figure something out. | ||
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inkblot
United States1250 Posts
Because (6,3) is 6 units in the x direction away from x = 0 and the slope is 1/6, the line will intersect the y axis one unit below (6,3), so it crosses at (0,2). Equation of line is y = (1/6)x + 2 | ||
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Wonders
Australia753 Posts
1. Write the general equation for a line passing through (6,3), with the gradient as an unknown. 2. Find the points of intersection of that line and the y=sqrt(x-3) graph (the x values). Just write down the equation that x has to satisfy, it'll probably be a quadratic in x. 3. Find the values of the gradient so that the determinant of the quadratic is zero (so that the line only intersects the graph at 1 point). You'll probably get a few different values, so just look at what the line looks like for each value and pick the one that looks the best. No idea why you'd do that, which would probably take a page or two of boring computations, when by taking the derivative you'd be able to do it in 2 lines though. | ||
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evanthebouncy!
United States12796 Posts
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Nytefish
United Kingdom4282 Posts
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HeavOnEarth
United States7087 Posts
are you trying to just grasp the logic behind it? if you understand it its essentially pointless to do it without the derivative i mean, all u can do is guess and check numbers with the derivative right? | ||
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HeavOnEarth
United States7087 Posts
i'm taking calc BC senior year ; so we're in the same boat http://archives.math.utk.edu/visual.calculus/2/definition.7/index.html WITH A PICTURE LIKE YOU SHOULD DRAW A PICTURE(graph) AND SEE IF IT MAKES SENSE definately, google some graph paper if u don't have any and plot it | ||
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