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Quantum Optics III: Raman Spectroscopy

Blogs > Ideal26
Post a Reply
Ideal26
Profile Blog Joined November 2013
United States185 Posts
May 11 2014 19:39 GMT
#1
Okay everyone, after our small tangent to talk about quantum mechanics, we’re back to optics! I picked a topic that is not only close to heart, but is relatively math-light so we can relax a little more than last week.

I'm going to aim for a safe middle ground on the math. Some topics need some pretty complicated math for anything to make sense, but I'll try to introduce concepts separately from derivations so those who aren't ready for all of that quantum mechanical stuff can skip the details.

Lesson 3. Raman Scattering and Raman Spectroscopy

+ Show Spoiler +

Let’s start by talking about molecules. We can think of them as being built of tiny balls attached to each other by tiny springs:


+ Show Spoiler +
[image loading]



Molecules vibrate at certain frequencies determined by their spring strength and structure.

When I talked about lasers, I told you that light interacted with atoms via absorption, stimulated emission, or spontaneous emission. Unintentionally, I totally neglected to mention scattering. Scattering is an entirely different beast, and if you’ve taken a quantum mechanics class that covers scattering, you know those problems are pretty much the worst. But we’ll make it through this lesson easily, promise.


There is elastic (also called Rayleigh) scattering, where the photon simply changes directions without losing energy, and there is inelastic scattering. Raman scattering is inelastic: the scattered photons have different energies than the incident photons.


So a photon acts like wave, yes? And you probably know that the energy of a photon, E, is related to its frequency, f, by the simple relationship:

E=hf (1)

Where h is Planck’s constant (=6.626E-34 J*s). I don’t like these variables so we’re going to divide h by 2π and multiply f by 2π to get angular frequency and write:

E=ħω (2)

So much better.


Here comes some math... after the mixed response from last week's blog, I'm going to spoiler the math and you can read the derivation if you want (it's just simple algebra this week, so try!) or you can just take the final result at face value.

+ Show Spoiler +

Let’s consider a molecule in an electric field. The presence of an E field induces a polarization in the molecule:

+ Show Spoiler +
[image loading]
(Polarization is basically just the separation of charge here)


We call the polarization μ, where

μ=αE (3)

Here α is the polarizability, which is unique to the molecule. Let’s say that the electric field, E, is given by:

E= E0*cos(ω0*t) (4)

where E0 is the amplitude and ω0 is the angular frequency of the field. Remember we just said that a molecule oscillates with its own particular frequency? We’ll call it ωvib for vibrational frequency.


Now, if we look at the picture of the polarized atom, it’s not hard to believe that the polarizability depends on the stretching of the “springs” in the molecule. As the molecule vibrates, the spacing between the positive and negative charges will oscillate a tiny bit and this will change how polarized the molecule is. α is probably some really complicated function of positions of the atoms, but we can usually safely assume that it doesn't change too much as the molecule vibrates. Under this assumption, we can expand it in a Taylor series (take my word for it if you aren't familiar with this) as:

α=α0+(∂α/∂r)*dr (5)

r is just a variable that denotes the relative separation of the atoms. Since the molecule is vibrating like a spring r is something like:

r=r0*sin(ωvib*t) (6)

So we can find dr by taking the derivative of (6) and can combine Eqs (3)-(5) to get something like:

μ=(α0+C*cos(ωvib*t))*E0*cos(ω0*t) (7)

I just absorbed all of the constant numbers into the symbol C because we don’t care about that number.


Then with the help of trig, we can simplify this to:

μ=C1*cos(ωvib*t)+C2*{cos((ω0-ωvib)*t)+cos((ω0+ωvib)*t)} (8)

with more C's we don't care much about...


So we see that there are 3 cosine terms with 3 different frequencies. ω0 is just the frequency of the electric field; this corresponds to Rayleigh scattering. The photon just bounces back with the same energy it started with.

There are also 2 shifted frequencies, these correspond to Raman scattering. The blue shifted term (ω0+ωvib) is called anti-Stokes scattering and the red shifted (ω0-ωvib) is called Stokes scattering.


You can also think of this in terms of the Doppler Effect, the thing that causes the frequency of sound to change as something is traveling toward and away from you. The molecule oscillates toward and away from your light source, causing the shifts in the observed frequencies.


So that’s what Raman scattering is. The scattered light can be detected using a CCD hooked up to a spectrometer, and we’ll get something like this:


+ Show Spoiler +
[image loading]



Pretty complicated, huh? People who want a Ph.D. in molecular dynamics or quantum chemistry can calculate spectra like this by having a very good understanding of the molecular structure. I am not one of these people, so don’t ask how, haha. Theory combined with experiments performed over the course of several decades has allowed us to build a pretty decent database of what each of these peaks is for.


Raman spectra are essentially molecular signatures. Every molecule vibrates in a very unique way, and by looking at the Raman spectrum we can say exactly what molecule we’re looking at. Raman spectroscopy is a method that compliments techniques such as mass spectroscopy, NMR, fluorescence spectroscopy, etc. The advantage of Raman is its sensitivity, robustness, and the fact that it is non-invasive and non-destructive. We use low enough powers that we can look at sensitive living cells without compromising their health. You can’t do NMR or MS on a biological cell and keep everything intact. You could do fluorescence, but then you have to add dyes to the cell that can affect its behavior or even kill it.


There are lots and lots of variations of Raman spectroscopy, each have their own advantage. The stuff explained above is spontaneous Raman scattering. We shine light on a sample and some (actually, very few) molecules will Raman scatter light back at us.

My favorite variation is CARS (coherent anti-Stokes Raman scattering). We use 3 femtosecond pulsed lasers. 2 of them “prepare” the sample. The wavelengths are chosen carefully so that they get all of the molecules in a sample to vibrate together, then the 3rd pulse “probes” the sample to see what’s going on, and the signal we receive comes from manyyy of the molecules. This signal is many orders of magnitude larger than that from spontaneous Raman,


+ Show Spoiler +
[image loading]
CARS beams. Subscripts on the left are for pump (p) and stokes (s) which get the molecules vibrating together. Probe (pr) looks at the signal. On the right we get a new signal, CARS.



Even better is something called FAST-CARS. It’s extremely tricky to do experimentally, but the basic idea is this:

CARS uses 2 laser pulses to prepare the sample. This is pretty good, but there are usually a lot of vibrational modes in big molecules, and CARS will only excite a few of them. FAST CARS (femtosecond adaptive spectroscopic techniques via CARS) uses laser pulses to “sing a melody” to the molecules. If the musical notes are resonant with the vibrational “notes” of the molecule, they will sing back in unison. This creates a very big signal that is easy to detect in fractions of a microsecond. This is what our lab used to detect anthrax: click!.


Raman can be used in microscopy as well; we scan the lasers across a sample and collect a spectrum for every pixel and can create images like this:

+ Show Spoiler +
[image loading]
A) optical microscope image of cells fixed on a slide. B) Raman image. C) Spectrum at a particular pixel.
The Raman image is based on the strength of the peak around 2900, so the colors represent how intense that peak is at each point.

(heyy, I actually took this image my first day back in the lab! We just got the microscope working and I tested it by imaging a cell!)



The applications of Raman spectroscopy are limitless. Every day we’re developing better methods for enhancing the Raman signal and making cheaper and smaller systems so you can do Raman anywhere and everywhere. We have a handheld Raman spectrometer that my boss likes taking to his ranch to shine at crops to evaluate plant health. Biomedical researchers use Raman in endoscope form to look for cancer. It’s a beautifully powerful technique that will only improve with time.


Thanks for reading! Again, I always love feedback and questions. I had a very busy week so I didn't re-read this post as much as I would have liked to make sure everything was transparent, so please let me know if something doesn't make sense.


*****
Mothra
Profile Blog Joined November 2009
United States1448 Posts
May 11 2014 21:36 GMT
#2
This is really cool.. it's like a view of a different world. Just amazing the stuff we are capable of understanding now. Can't say I could follow all of it exactly, but there was enough to get a general picture and feel wonderment.
sorrowptoss
Profile Blog Joined June 2011
Canada1431 Posts
May 12 2014 00:56 GMT
#3
I took a Waves and Optics course at college, and it sucked. I essentially needed to identify different types of problems and memorize the steps to solve them. The theory behind it was poorly explained and passed as unimportant or impractical (of which I am totally in disagreement). This blog not only enlightens me on what I missed and what I could have learned through the lens of a charismatic and caring teacher, but also revives my interest in Physics.

Looking forward to your next entry
flamewheel
Profile Blog Joined December 2009
FREEAGLELAND26781 Posts
May 12 2014 14:11 GMT
#4
Your blogs are awesome ~
Writerdamn, i was two days from retirement
neptunusfisk
Profile Blog Joined July 2012
2286 Posts
May 12 2014 17:31 GMT
#5
Do you have experience with second harmonic generation in RKTP or similar?
maru G5L pls
Ideal26
Profile Blog Joined November 2013
United States185 Posts
May 13 2014 00:07 GMT
#6
On May 13 2014 02:31 neptunusfisk wrote:
Do you have experience with second harmonic generation in RKTP or similar?


No direct experience, but I'm familiar with the basic ideas of SHG.


You guys are the best, I'm glad you're enjoying optics! Reading such nice comments definitely makes me want to keep up with this blog. <3
imBLIND
Profile Blog Joined December 2006
United States2626 Posts
May 13 2014 01:40 GMT
#7
Why couldn't my professor explain raman spectrography like that...
im deaf
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