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-_-
United States7081 Posts
Problem: Use the definition of continuity and the properties of limits to show that the function is continuos at the given number a. f(x)= x^2 + Sqr root of(7-x), a = 4 The definition on cont. is just f(a) is defined, Lim f(x) as x approaches a exists, and lim F(x) as x approaches a = f(a). By the way, the teacher's at some seminar until friday (due date). | ||
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Ender
United States294 Posts
Then just do lim as x approaches 4 of f(x) by plugging 4 in again and getting the same value. | ||
Hot_Bid
Braavos36374 Posts
someone close the thread already ps. any person with a brain can figure out this stupid homework with ten minutes on google | ||
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-_-
United States7081 Posts
On September 29 2005 06:44 Hot_Bid wrote: putting "do my homework!" as if you're being honest doesn't change the fact that you're a lazy shmuck who wants others to do his homework for him someone close the thread already I've seen a bunch of HW threads. It's not spam or anything, I don't know if it should be closed. Yeah, I am a lazy shmuck... aren't we all? | ||
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-_-
United States7081 Posts
On September 29 2005 06:43 Ender wrote: To check f(a) is defined just plug in 4 into the equation and you get 16+sqrt(3). Then just do lim as x approaches 4 of f(x) by plugging 4 in again and getting the same value. I understand the first part, but not the second. Explain if you would. | ||
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Hot_Bid
Braavos36374 Posts
On September 29 2005 06:45 -_- wrote: I've seen a bunch of HW threads. It's not spam or anything, I don't know if it should be closed. Yeah, I am a lazy shmuck... aren't we all? oh in that case, by all means someone help the guy out. | ||
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Ender
United States294 Posts
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-_-
United States7081 Posts
On September 29 2005 06:48 Ender wrote: I only help people out because "easy" and "hard" have relative meaning. If I had a problem with something I would turn to someone who knows what they're doing even though they would consider it so easy they could google it in 10 minutes. But yea, I recommend at least trying to google it before asking. I googled it. Couldn't find it. And I don't get your answer. I'm trying, at least I'm pretty sure, to get lim f(x) as x approaches a to = 4 because I'm trying to get it to = f(4). | ||
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CruiseR
Poland4014 Posts
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-_-
United States7081 Posts
And ender... I think you did help me. f(4) doesn't mean 4 it means what you get when you plug in 4 DOH! CLOSE! (unless a math genius mod sees ender is wrong) | ||
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garandou
Germany518 Posts
1. Plug in ( a + h ) and let h converge towards 0. You obtain the limit of f(x), x->a from the right side of a. 2. Plug in ( a - h ) and let h converge towards 0. You obtain the limit of f(x), x->a from the left side of a. 3. Plug in a. 4. If all three limits exist and all three limits are the same, the function is continuous at a. | ||
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Suicide
United States475 Posts
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