EPTOn September 02 2008 03:15 travis wrote:
lol I am trying to figure out what this is about but I am failing miserably.
In layman's terms, this has to do with the strength of radioactive waves being exerted by an atom, given the nature of the orbits of it's electrons?
or am I way off?
lol I am trying to figure out what this is about but I am failing miserably.
In layman's terms, this has to do with the strength of radioactive waves being exerted by an atom, given the nature of the orbits of it's electrons?
or am I way off?
If you take two atoms and make a molecule out of them their total energy is lowered but since the energy of the "universe" must remain constant the excess energy has to go somewhere. Normally a third particle would crash into the forming molecule and absorb this energy as kinetic energy, that is heat.
However in interstellar space there aren't a whole lot of particles flying about so the probability for a 3 body reaction is generally negible.
In this case the excess energy is emitted as a "light particle", a photon. The simplest way to think of a wave function would be as a replacement to the classical trajectory.
When you want to modell two colliding particles you need some way to describe their movements so to speak, when you do the problem quantum mechanically you use wave functions to do that.
Hm and I am not looking for a "solution" so to speak, more like the correct theoretical approach to take when you want to take a momentum normalized wave function and turn it into an energy normalized one. (I don't know where to start)
But anyway my handler mailed me 1 hour or so ago and wrote that he had found the solution in an old article he had lying about.
If you take the momentum normalized function and multiply it with a factor SQRT(2M/pi*SQRT(2M*E)) you get an energy normalized function. (I might remember it slightly wrong will check tomorrow obv)
yay I guess -_-
I don't understand half of this crap as good as i ought to :/
