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Active: 2312 users

Help my friend since I suck at calc

Blogs > Raithed
Post a Reply
1 2 Next All
Raithed
Profile Blog Joined May 2007
China7078 Posts
April 02 2008 01:44 GMT
#1
This is my takehome test that is due tomorrow. Unfortunately, I do not know how to do any of these... Explanations on how to integrals would be greatly appreciated. I am working on these on my own, and would like ideas, or someone to talk to on AIM or something to discuss how to do these.


[image loading]


fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
April 02 2008 02:05 GMT
#2
[image loading]
Do you really want chat rooms?
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
April 02 2008 02:17 GMT
#3
[image loading]
Do you really want chat rooms?
Raithed
Profile Blog Joined May 2007
China7078 Posts
April 02 2008 02:20 GMT
#4
ROFL. Those are EPIC.
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
April 02 2008 02:22 GMT
#5
That last one is exclusive content btw (made it myself).
Do you really want chat rooms?
doob10163
Profile Joined April 2008
6 Posts
April 02 2008 02:28 GMT
#6
Thanks guys. This is the friend that Raithed posted for


I have 1, 2, 3, 4, 6, 10, and 14 done

Not quite sure how to go about the rest of these. Any ideas?
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
Last Edited: 2008-04-02 02:42:08
April 02 2008 02:40 GMT
#7
The flowchart should help with some of them. Remember, sin^2 = 1 - cos^2 and cos^2 = 1 - sin^2. That means if a power is odd you can

cos^3 = cos cos^2 = cos (1 - sin^2)

then u = sin, du = 1/cos dx.

For the rational ones do partial fractions.

edit: also, you can use http://integrals.wolfram.com/index.jsp to check your work
Do you really want chat rooms?
doob10163
Profile Joined April 2008
6 Posts
April 02 2008 02:50 GMT
#8
My trig is terrible - for example, I would have no idea how to get about #9.

i did 4 times the integral (sec^2 x) ^2

which then became sex^2 x (tan ^2x + 1)

is this the right approach to be taking? If so , what is the proper next step?
paper
Profile Blog Joined September 2004
13196 Posts
April 02 2008 02:53 GMT
#9
damn i wish i had that shit fight/flight posted when i took calc :{
Hates Fun🤔
Saracen
Profile Blog Joined December 2007
United States5139 Posts
April 02 2008 03:10 GMT
#10
you can do most of these by parts or trig identities

for 9. "which became sex^2x" ahah i see what you did there ^_^
sec^2(x)tan^2(x) function to a power times its derivative
and S sec^2(x) dx = tanx

well at least i'm pretty sure how it is
i forgot all this shitty trig identity integration stuff
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
Last Edited: 2008-04-02 03:12:53
April 02 2008 03:12 GMT
#11
so then you have u = tan, then the derivative of u, du, becomes dx = 1/sec^2 du.

then its the integral of u^2 + 1 = 1/3 u^3 + u

or 1/3 (tanx)^3 + tanx

giving 4/3 (tanx)^3 + 4tanx
Do you really want chat rooms?
Saracen
Profile Blog Joined December 2007
United States5139 Posts
April 02 2008 03:16 GMT
#12
you don't need to use u-substitution on that one
right?
doob10163
Profile Joined April 2008
6 Posts
April 02 2008 03:24 GMT
#13
Thanks, fight_or_flight. Do you have any idea on how to go about #5? (Do you have AIM, MSN, or YIM and don't mind me messaging you for help?)
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
Last Edited: 2008-04-02 03:36:01
April 02 2008 03:35 GMT
#14
actually, I should be doing other things besides this, and I have to go home soon. Anyway, I haven't taken calc in a long time so these problems are hard for me too, lol.

Basically I've just been working off my own flowchart to be honest.
Do you really want chat rooms?
doob10163
Profile Joined April 2008
6 Posts
April 02 2008 03:35 GMT
#15
Thanks anyways
doob10163
Profile Joined April 2008
6 Posts
April 02 2008 03:55 GMT
#16
Any ideas on how to do the 2nd integral of 3, 5, 11, 12, 13, 15, 16, 17, 18, and 19?

The second integral of #3 being what happens after you split the fraction and are left with 18x over the denominator
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
Last Edited: 2008-04-02 03:58:37
April 02 2008 03:58 GMT
#17
u = 1+3x^2, du = 6xdx?
Do you really want chat rooms?
Saracen
Profile Blog Joined December 2007
United States5139 Posts
April 02 2008 04:20 GMT
#18
On April 02 2008 12:55 doob10163 wrote:
Any ideas on how to do the 2nd integral of 3, 5, 11, 12, 13, 15, 16, 17, 18, and 19?

The second integral of #3 being what happens after you split the fraction and are left with 18x over the denominator

separate it into 2 fractions
1/(1+3x^2) and -6x/(1+3x^2) after you take out the 3
1st one is arctan
2nd one is function to a power times its derivative
Saracen
Profile Blog Joined December 2007
United States5139 Posts
April 02 2008 04:25 GMT
#19
number 5:
u-sub
u=lnx
du=dx/x
x=e^u
then use parts (tabular method)
Saracen
Profile Blog Joined December 2007
United States5139 Posts
April 02 2008 04:30 GMT
#20
11 is just trig sub...
it's really straightforward...idk why it's hard?
sec(theta) = sqrt(4y^2+1), dy=(sec^2(theta))d(theta)/2
1 2 Next All
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