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Happy 410th Birthday, Fermat! - Page 2

Blogs > EsX_Raptor
Post a Reply
Prev 1 2 3 Next All
intotheheart
Profile Blog Joined January 2011
Canada33091 Posts
August 17 2011 15:21 GMT
#21
Best blog ever. Just sayin'.
kiss kiss fall in love
EsX_Raptor
Profile Blog Joined February 2008
United States2802 Posts
Last Edited: 2011-08-17 15:40:14
August 17 2011 15:35 GMT
#22
Let's do the good-old MU Puzzle:

Assume that we have the following string:

MI

and that we can perform operations on it based strictly off the following rules:

I. Add a U to the end of any string ending in I. For example: MI to MIU.
II. Double any string after the M (that is, change Mx, to Mxx). For example: MIU to MIUIU.
III. Replace any III with a U. For example: MUIIIU to MUUU.
IV. Remove any UU. For example: MUUU to MU.

Is it possible to obtain MU?

If you find an answer to this, please post it in spoilers. I'm still working on it!

Edit: New page: More decoration:

[image loading]
SecondChance
Profile Joined December 2010
Australia603 Posts
August 17 2011 15:37 GMT
#23
All those who didn't go so well in highshcool and have no fucking idea what is going on in this thread yet wished they understood say "I".



I understand to an extent, but it looks like this:

<|understood|-----lolwut---------------------------------------------------------------------------------------------------------|>
I see the want to in your eyes.
ComaDose
Profile Blog Joined December 2009
Canada10357 Posts
August 17 2011 15:51 GMT
#24
On August 18 2011 00:37 SecondChance wrote:
+ Show Spoiler +

All those who didn't go so well in highshcool and have no fucking idea what is going on in this thread yet wished they understood say "I".



I understand to an extent, but it looks like this:

<|understood|-----lolwut---------------------------------------------------------------------------------------------------------|>


You wont learn this in any high-school I've heard of.
I spoiled myself with a solution to the MI string from google lol
.
I want more decoration!

[image loading][image loading][image loading]
BW pros training sc2 is like kiss making a dub step album.
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
Last Edited: 2011-08-17 17:04:17
August 17 2011 16:57 GMT
#25
On August 18 2011 00:35 EsX_Raptor wrote:
Let's do the good-old MU Puzzle:

Assume that we have the following string:

MI

and that we can perform operations on it based strictly off the following rules:

I. Add a U to the end of any string ending in I. For example: MI to MIU.
II. Double any string after the M (that is, change Mx, to Mxx). For example: MIU to MIUIU.
III. Replace any III with a U. For example: MUIIIU to MUUU.
IV. Remove any UU. For example: MUUU to MU.

Is it possible to obtain MU?

If you find an answer to this, please post it in spoilers. I'm still working on it!

Edit: New page: More decoration:

[image loading]


+ Show Spoiler [solution] +

We approach this algebraically.

Suppose we have n Is, and we want to reduce them to a single U. We approach this instead as k+3 I's, since the first 3 I's we can reduce to a U. The question is then, given what k can we completely erase the string. The only way we can remove strings is to remove UU. UU is produced by k=6.

Thus, in order for the string subsequent to M to be reducible to U, it must consist of 3+6n I's, for some n.

At the same time, we can only generate powers of 2 for the number of I's. Thus 3+6n = 2^m for n,m, which is so say we want an m such that 2^m - 3 ≅ 0 mod 6.

2^1 ≅ 1 mod 6
2^2 ≅ 4 mod 6
2^3 ≅ 2 mod 6
2^4 ≅ 4 mod 6
etc we have hit a cycle

Therefore it is impossible to produce MU.

Other cases ignored because it is clearly impossible to reduce them.

edit - Aw fuck it according to wiki I could have just used invariants LOL so much simpler fml.
EsX_Raptor
Profile Blog Joined February 2008
United States2802 Posts
August 17 2011 17:05 GMT
#26
On August 18 2011 01:57 EtherealDeath wrote:
Show nested quote +
On August 18 2011 00:35 EsX_Raptor wrote:
Let's do the good-old MU Puzzle:

Assume that we have the following string:

MI

and that we can perform operations on it based strictly off the following rules:

I. Add a U to the end of any string ending in I. For example: MI to MIU.
II. Double any string after the M (that is, change Mx, to Mxx). For example: MIU to MIUIU.
III. Replace any III with a U. For example: MUIIIU to MUUU.
IV. Remove any UU. For example: MUUU to MU.

Is it possible to obtain MU?

If you find an answer to this, please post it in spoilers. I'm still working on it!

Edit: New page: More decoration:

[image loading]


+ Show Spoiler [solution] +

We approach this algebraically.

Suppose we have n Is, and we want to reduce them to a single U. We approach this instead as k+3 I's, since the first 3 I's we can reduce to a U. The question is then, given what k can we completely erase the string. The only way we can remove strings is to remove UU. UU is produced by k=6.

Thus, in order for the string subsequent to M to be reducible to U, it must consist of 3+6n I's, for some n.

At the same time, we can only generate powers of 2 for the number of I's. Thus 3+6n = 2^m for n,m, which is so say we want an m such that 2^m - 3 ≅ 0 mod 6.

2^1 ≅ 1 mod 6
2^2 ≅ 4 mod 6
2^3 ≅ 2 mod 6
2^4 ≅ 4 mod 6
etc we have hit a cycle

Therefore it is impossible to produce MU.

Other cases ignored because it is clearly impossible to reduce them.

That's what I thought. Whoever made that puzzle made me spend quite some time trying to solve the unsolvable. lol

By the way, it's your turn to ask us a question!
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
August 17 2011 17:14 GMT
#27
On August 18 2011 02:05 EsX_Raptor wrote:
Show nested quote +
On August 18 2011 01:57 EtherealDeath wrote:
On August 18 2011 00:35 EsX_Raptor wrote:
Let's do the good-old MU Puzzle:

Assume that we have the following string:

MI

and that we can perform operations on it based strictly off the following rules:

I. Add a U to the end of any string ending in I. For example: MI to MIU.
II. Double any string after the M (that is, change Mx, to Mxx). For example: MIU to MIUIU.
III. Replace any III with a U. For example: MUIIIU to MUUU.
IV. Remove any UU. For example: MUUU to MU.

Is it possible to obtain MU?

If you find an answer to this, please post it in spoilers. I'm still working on it!

Edit: New page: More decoration:

[image loading]


+ Show Spoiler [solution] +

We approach this algebraically.

Suppose we have n Is, and we want to reduce them to a single U. We approach this instead as k+3 I's, since the first 3 I's we can reduce to a U. The question is then, given what k can we completely erase the string. The only way we can remove strings is to remove UU. UU is produced by k=6.

Thus, in order for the string subsequent to M to be reducible to U, it must consist of 3+6n I's, for some n.

At the same time, we can only generate powers of 2 for the number of I's. Thus 3+6n = 2^m for n,m, which is so say we want an m such that 2^m - 3 ≅ 0 mod 6.

2^1 ≅ 1 mod 6
2^2 ≅ 4 mod 6
2^3 ≅ 2 mod 6
2^4 ≅ 4 mod 6
etc we have hit a cycle

Therefore it is impossible to produce MU.

Other cases ignored because it is clearly impossible to reduce them.

That's what I thought. Whoever made that puzzle made me spend quite some time trying to solve the unsolvable. lol

By the way, it's your turn to ask us a question!


Hmm...
Explain why the following scenario is true.

Suppose we have two entangled particles, let's say their state is a|1>|0>+b|0>|1> to be simple, where the values of a and b are not particularly important save that their squares sum to 1, but let's use one of the Bell States, that is a=b=1/sqrt(2). Now we measure one of the particles to determine it's actual state. We know that instantaneously, the state of the other particle is set. However, it is impossible to determine any classical information from this instantaneous effect - i.e., cannot gain any physical information. Why? Or rather, what information do you think you could gain that you didn't have before?
TL AntiHack
Profile Joined May 2011
39 Posts
August 17 2011 17:17 GMT
#28
5/5, you sir deserve applause. Thank you for making my day better.

On August 18 2011 00:21 IntoTheheart wrote:
Best blog ever. Just sayin'.
Currently not active
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
August 17 2011 17:18 GMT
#29
On August 18 2011 02:17 TL AntiHack wrote:
5/5, you sir deserve applause. Thank you for making my day better.

Show nested quote +
On August 18 2011 00:21 IntoTheheart wrote:
Best blog ever. Just sayin'.


hax.
Pengtoss
Profile Blog Joined April 2011
207 Posts
August 17 2011 17:30 GMT
#30
I am stupid
Aletheia27
Profile Blog Joined July 2010
United States267 Posts
Last Edited: 2011-08-17 17:45:06
August 17 2011 17:44 GMT
#31
On August 17 2011 23:49 Iranon wrote:
Show nested quote +
On August 17 2011 23:38 EsX_Raptor wrote:
It is also believed that a proof to the Riemann hypothesis would compromise internet security.

Iranon, you forgot to ask your question!


Oh, right! And it sure would -- for number theoretic reasons. It would allow for a fast factoring algorithm, which compromises RSA.

I'll keep on the topic of fun math that a lot of people know about but relatively few actually follow.

Can you turn a sphere inside out without poking holes in it or making any sharp creases? The sphere's surface can pass through itself, and you can stretch and rotate parts of it as much as you like, but you can't break it and glue it back together. If you know what the terms mean, I'm asking for a diffeomorphism between two spheres that reverses the orientation.


I believe you can although it hinges on the axiom of choice...

EDIT: I don't remember exactly why though... Guess I wasn't meant to be a math major
I am that I am
Primadog
Profile Blog Joined April 2010
United States4411 Posts
August 17 2011 17:50 GMT
#32
Nothing new to add, but here's my favorite geek song:
Thank God and gunrun.
Ruyguy
Profile Blog Joined January 2011
Canada988 Posts
August 17 2011 18:02 GMT
#33
this blog makes me feel so stupid haha.
Kukaracha
Profile Blog Joined February 2011
France1954 Posts
August 17 2011 18:43 GMT
#34
I remember being 15 and stupid and not giving a fuck about math classes. I would litterally do nothing because I had refused to buy a scientific calculator that could support functions. To my defense, our techer was a clown, the year before that we had a great one and I had some of the best grades in the class.

But then I grew up and found out that I missing out a whole beautiful world... I don't know if I'll ever dedicate myself to it but I'd like to give a try oince more, by myself this time.
Le long pour l'un pour l'autre est court (le mot-à-mot du mot "amour").
ComaDose
Profile Blog Joined December 2009
Canada10357 Posts
August 17 2011 19:06 GMT
#35
EtherealDeath's question was too hard!
I only took first year chemistry and promptly forgot everything involved.
I only mention chemistry becuase i only vaguely recognize the syntax involved in "a|1>|0>+b|0>|1>" as from that class
moar math and physics!

I propose a new question: "whoes 410th birthday is it and what is he famous for?"
should be easy enough.
BW pros training sc2 is like kiss making a dub step album.
Aletheia27
Profile Blog Joined July 2010
United States267 Posts
August 17 2011 19:13 GMT
#36
On August 18 2011 04:06 ComaDose wrote:
EtherealDeath's question was too hard!
I only took first year chemistry and promptly forgot everything involved.
I only mention chemistry becuase i only vaguely recognize the syntax involved in "a|1>|0>+b|0>|1>" as from that class
moar math and physics!

I propose a new question: "whoes 410th birthday is it and what is he famous for?"
should be easy enough.


It's a quantum physics problem actually.... but i don't want to answer this cause I don't havea good question
I am that I am
EsX_Raptor
Profile Blog Joined February 2008
United States2802 Posts
August 17 2011 19:22 GMT
#37
I, too, was perplexed by EtherealDeath's problem. However, I would gladly work it through if he were to give us a few hints as to how to approach it (I know next to nil about quantum physics).

By the way, I have been practicing writing trivial proofs and decided to give proving the MU puzzle a try:

[image loading]

I most likely (and as per-usual) left out something critical.
ComaDose
Profile Blog Joined December 2009
Canada10357 Posts
Last Edited: 2011-08-17 19:41:54
August 17 2011 19:23 GMT
#38
On August 18 2011 04:13 Aletheia27 wrote:
Show nested quote +
On August 18 2011 04:06 ComaDose wrote:
EtherealDeath's question was too hard!
I only took first year chemistry and promptly forgot everything involved.
I only mention chemistry becuase i only vaguely recognize the syntax involved in "a|1>|0>+b|0>|1>" as from that class
moar math and physics!

I propose a new question: "whoes 410th birthday is it and what is he famous for?"
should be easy enough.


It's a quantum physics problem actually.... but i don't want to answer this cause I don't havea good question

You should answer and give a lame question then.... now I'm googling cause I feel ignorant.
Its pretty much your calling to continue this thread.

EDIT: Your proof is true but a little.... shallow, like i mean just missing some whys and therefore... pretty much exactly like a professional would do it good job ;p

randall from xkcd helped me understand it better ;p linky

EDIT: can your question be rewritten as this?
+ Show Spoiler +

Suppose we have two entangled particles. Now we measure one of the particles to determine it's actual state. We know that instantaneously, the state of the other particle is set. However, it is impossible to determine any classical information from this instantaneous effect - i.e., cannot gain any physical information. Why? Or rather, what information do you think you could gain that you didn't have before?

i.e. is the answer your looking for true for all entangled particles?
BW pros training sc2 is like kiss making a dub step album.
EsX_Raptor
Profile Blog Joined February 2008
United States2802 Posts
August 17 2011 19:44 GMT
#39
Thanks for the link!

From now on, I will try a mathematical approach to every puzzle I encounter to save myself the potential time-loss of trying one with no solution. ;p

[image loading]
M.C. Escher

And someone still needs to answer ComaDose's question!

On August 18 2011 04:06 ComaDose wrote:
I propose a new question: "whoes 410th birthday is it and what is he famous for?"

EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
August 17 2011 22:49 GMT
#40
Well let's reword it.

You know that if one measures Particle A to be in state 1, then B is in 0. If A is measured to be in state 2, then B is in 1, and conversely if you measure B, then A is immediately set if it has not already been set by measurement.

Some have thought this could be used for FTL (faster than light) communication, since the "information transfer" is instantaneous.

However, this is not the case.

In short, what does measuring your particle tell you that you didn't already know?
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