EPTCode A - Code S (Visualization) - Page 2
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Dimagus
United States1004 Posts
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syllogism
Finland5948 Posts
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Cheebah
210 Posts
On December 14 2010 04:45 TheBanana wrote: Does that mean that "uncoded" foreigners will be limited to 4 places or am I being unfairly pessimistic? You're being pessimistic ^^ Quoted from the previous thread about GSL in 2011 : 4 spots of Code A are guaranteed for top foreign players who has won recent big tourneys or shown considerable performances in non-Korean competitions. | ||
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stangstang
Canada281 Posts
standard group play for code S + 2 code A winners. shuffling around from code A and code S depends on how well you perform. | ||
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FlamingTurd
United States1059 Posts
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Moody
United States750 Posts
I guess it doesn't really matter how they determine who goes where, as long as it objective and explained before hand. Players don't have to know "What do I have to do to make it to Code S." They just have to continue playing their games and always trying to win. | ||
Empyrean
17067 Posts
On December 14 2010 04:47 butter wrote: It's actually from the TL thread. But I think they are not as clear as mine  (based on the visual style of the OSL FAQ): ![[image loading]](http://i.imgur.com/Dp2vFl.png) ![[image loading]](http://i.imgur.com/xXcH0.jpg) Oh, this DOES make it much more clear. Thanks for that. | ||
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GeorgeForeman
United States1746 Posts
32 PLAYERS START IN CODE A: -Divided into 8 groups of 4 players, simple bracket format. -Players who lose first match are done and qualify for nothing next season (16 total players) -For each group, winners of first match play. Loser remains Code A next season but is done for this season; winner has two chances to qualify for Code S (described later) 32 PLAYERS START IN CODE S: -Divided into 8 pools of 4 players; round robin play determines placement in pool -Bottom two finishers from each pool face elimination from Code S -3rd place finisher plays a Code A winner (from last bullet point in Code A discussion above); winner is Code S next year, loser plays a 4th place finisher from Code S pool. Winner from this match is also Code S next year, loser is Code A -Top 2 from each Code S pool advance to round of 16 16 PLAYERS QUALIFY FOR CODE S ROUND OF 16: -Players are re-seeded into 4 pools of 4, round-robin play determines placement -Bottom two finishers are eliminated from this season's GSL and remain Code S for next season -Top 2 of these pools qualify for Round of 8 -Round of 8 is seeded normally like a single elimination bracket (like current seasons) -Winner of this bracket is GSL champion UP TO 16 NEW PLAYERS CAN QUALIFY FOR CODE A NEXT SEASON: -16 players were eliminated from Code A (described above) -open off-line qualifiers will determine which players qualify to take these vacated spots -At least 4 foreign players must be in each season's GSL between Code S and Code A, so if fewer than 4 are qualified, as many as are necessary will be placed into Code A (it's not entirely clear how this works, but my opinion is that it won't matter, since enough foreigners will qualify each season through regular means.) So yeah, it's a bit more complex than your standard single- or double-elimination bracket, but if you're at all familiar with tournament structures, it's not that far out there. Overall, it seems like a really good system. The Code A brackets are a bit brutal (Single elimination? Yuck.) But if you're good enough to make Code S, you have to lose a whole lot to get booted out. We should see a lot of really good games coming out of this format, though if they want to do one a month, I don't see how Tastosis can possibly cast them all. | ||
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mordk
Chile8385 Posts
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happyness
United States2400 Posts
![[image loading]](http://imgur.com/oLgYJ.png) ![[image loading]](http://imgur.com/n0IGL.png) So it really isn't that complicated. Other than the above, the lower 16 in Code A will compete for 12 spots in offline preliminaries, with 4 spots reserved for the top foreigners. | ||
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mAgixWTF
Germany103 Posts
On December 14 2010 06:02 GeorgeForeman wrote: -At least 4 foreign players must be in each season's GSL between Code S and Code A, so if fewer than 4 are qualified, as many as are necessary will be placed into Code A (it's not entirely clear how this works, but my opinion is that it won't matter, since enough foreigners will qualify each season through regular means.) and i thought 4 spots for Code A would always be given to foreigners, no matter how many foreigners already got Code A, and no matter how many qualify for Code A in the qualifiers. could you do me the favour and tell me where you got your information regarding this matter? Or can somebody vouch for his version?  edit: typo | ||
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Batch
Sweden692 Posts
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kOre
Canada3642 Posts
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Liquid`Nazgul
22427 Posts
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GeorgeForeman
United States1746 Posts
On December 14 2010 08:31 mAgixWTF wrote: and i thought 4 spots for Code A would always be given to foreigners, no matter how many foreigners already got Code A, and no matter how many qualify for Code A in the qualifiers. could you do me the favour and tell me where you got your information regarding this matter? Or can somebody vouch for his version? edit: typo You actually may be correct. I just assumed they wouldn't do that if there were already foreigners in. But I really have no idea. | ||
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LiOn
Austria239 Posts
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Befree
695 Posts
Basically S class has a 32 player tournament. The 16 losers in the first round have to play the 8 winners of the A class tournament to retain their spot in S class. The rest is just details. I'm curious as to how the coverage of this will work, though? It'd be really awesome if they'd cast all of this. Tasteless did seem to act like they were going to have a huge amount of starcraft, so hopefully they will. | ||
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stangstang
Canada281 Posts
On December 14 2010 09:34 GeorgeForeman wrote: You actually may be correct. I just assumed they wouldn't do that if there were already foreigners in. But I really have no idea. I read that it was top 4 from foreign tournaments. so players like Jinro, IdrA, Ret wouldn't count to the 4 since their A/S class achievement came from previous GSL's and not foreign tournaments. | ||
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Jaksiel
United States4130 Posts
Dan Patrick: With the first nine months of the Baseketball postseason out of the way, the playoff picture is starting to emerge. Kenny Mayne: So, with last night's victory over Boston, next week the Milwaukee Beers must beat Indianapolis in order to advance to Charlotte. That's in an effort to reduce their magic number to three. Dan Patrick: Right, and then the Beers can advance to the National Eastern Division North to play Tampa. Kenny Mayne: So, if the Beers beat Detroit and Denver beats Atlanta in the American Southwestern Division East Northern, then Milwaukee goes to the Denslow Cup, unless Baltimore can upset Buffalo and Charlotte ties Toronto, then Oakland would play LA and Pittsburgh in a blind choice round robin. And if no clear winner emerges from all of this, a two-man sack race will be held on consecutive Sundays until a champion can be crowned. | ||
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Grumbels
Netherlands7032 Posts
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![[image loading]](http://i.imgur.com/Ev5Jc.jpg)
