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can someone solve this math riddle for me - Page 2

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zizou21
Profile Joined September 2006
United States3683 Posts
July 22 2007 15:11 GMT
#21
ok so the problem lies in the 27+2 when it should be 27-2 altho im still kind of confused to how this works

so 27-2 why substract 2 to the amount they paid? is the 2$ the bellboy jacked INCLUDED in the 9$ they paid? yes i know im an idiot
its me, tasteless,s roomate LOL!
CustomXSpunjah
Profile Blog Joined June 2007
United States1093 Posts
July 22 2007 15:17 GMT
#22
On July 22 2007 14:18 MyLostTemple wrote:
i suck at math : [


doesnt have much to do with math, more of your ability to problem solve
beware, the rise of the Protoss is upon us!
zizou21
Profile Joined September 2006
United States3683 Posts
July 22 2007 15:22 GMT
#23
btw does anyone any other sweet ass riddles like this (not necessarily math) cuz at dinner i like to pop these up, but the other nyte i popped this one up but couldnt give them the answer LOL
its me, tasteless,s roomate LOL!
WhatisProtoss
Profile Blog Joined February 2004
Korea (South)2325 Posts
July 22 2007 15:24 GMT
#24
On July 23 2007 00:11 zizou21 wrote:
ok so the problem lies in the 27+2 when it should be 27-2 altho im still kind of confused to how this works

so 27-2 why substract 2 to the amount they paid? is the 2$ the bellboy jacked INCLUDED in the 9$ they paid? yes i know im an idiot

I cannot believe this question got to the second page.

You need to ask yourself questions. For example:

HOW MUCH DID THE GUYS PAY?
$9x3 = $27

HOW MUCH DID THE HOTEL KEEP?
$25

Okay... so, bellboy keeps $2 (the amount the guys are ripped off). Right? No questions now.

Just like OldBoy tells us, ask the wrong questions and you'll get the wrong answer.
WhatisProtoss
Profile Blog Joined February 2004
Korea (South)2325 Posts
July 22 2007 15:25 GMT
#25
On July 23 2007 00:22 zizou21 wrote:
btw does anyone any other sweet ass riddles like this (not necessarily math) cuz at dinner i like to pop these up, but the other nyte i popped this one up but couldnt give them the answer LOL

Use google search?
zizou21
Profile Joined September 2006
United States3683 Posts
Last Edited: 2007-07-22 15:31:22
July 22 2007 15:28 GMT
#26
On July 23 2007 00:24 WhatisProtoss wrote:
Show nested quote +
On July 23 2007 00:11 zizou21 wrote:
ok so the problem lies in the 27+2 when it should be 27-2 altho im still kind of confused to how this works

so 27-2 why substract 2 to the amount they paid? is the 2$ the bellboy jacked INCLUDED in the 9$ they paid? yes i know im an idiot

I cannot believe this question got to the second page.

You need to ask yourself questions. For example:

HOW MUCH DID THE GUYS PAY?
$9x3 = $27

HOW MUCH DID THE HOTEL KEEP?
$25

Okay... so, bellboy keeps $2 (the amount the guys are ripped off). Right? No questions now.

Just like OldBoy tells us, ask the wrong questions and you'll get the wrong answer.


ok word
its me, tasteless,s roomate LOL!
rgfdxm
Profile Joined December 2006
United States239 Posts
Last Edited: 2007-07-22 15:37:29
July 22 2007 15:35 GMT
#27
OK so they each payed 10$ at first but got 1$ back each ($9 x 3 = $27). the bellboy pocketed 2$


This tells you all the information you need.

The total amount of money that left the guys' pockets by the end is $27 (they paid $30 and got $3 back, so now they are out $27 total)

Where did that $27 they spent go? $25 went to pay for their hotel room, and $2 went into the bellboy's pocket.

Think about what you're doing from here. The $2 the bellboy has are part of the $27. Adding another $2 to the $27 makes no sense. That money is already accounted for. The "missing" three dollars to get from 27 to 30 that you're looking for is the three extra the guys paid and then got returned to them.


Bonus explanation with more equations (because equations are cool). All positive numbers are sources of money, all negative numbers are drains:

GOOD:
+$30 (TOTAL MONEY PAID) - $3 (refund) - $2 (bellboy) - $25 (cost of room) = 0 (all accounted for)

What the problem has you do is subtract their refund from what they paid first, and then add the amount the bellboy took to come up with a meaningless number of 29:

BAD:
+$30 (total money) - $3 (refund) + $2 (wtf are you doing the bellboy took money away he didn't add it) = $29

So we can see that $29 comes out of nowhere and makes no sense, unless the bellboy put in $2 of his own money.
Lycaeus
Profile Blog Joined February 2006
United States1420 Posts
July 22 2007 16:14 GMT
#28
sorry to be rude but this was a riddle?
larrysbird
Profile Joined May 2006
375 Posts
July 22 2007 16:39 GMT
#29
its more of a trick than a riddle ; ). its more like counting your fingers backward from 10-1 folding each after each count. you stop counting a 6 then when you say 6+4(four fingers up) =10 + 1(1 folded finger left) = 11.
Is there a cure among us from this processed sanity - c soul
Alventenie
Profile Joined July 2007
United States2147 Posts
July 22 2007 16:49 GMT
#30
almost as good as how much change can you have without being able to break a dollar =)
5HITCOMBO
Profile Joined March 2006
Japan2239 Posts
July 22 2007 17:54 GMT
#31
$1.19?
I live in perpetual fear of terrorists and studio gangsters
knyttym
Profile Blog Joined December 2006
United States5797 Posts
July 22 2007 18:13 GMT
#32
On July 23 2007 00:22 zizou21 wrote:
btw does anyone any other sweet ass riddles like this (not necessarily math) cuz at dinner i like to pop these up, but the other nyte i popped this one up but couldnt give them the answer LOL


monty hall problem. I remember when someone looked it up and posted it here when the map came out.
Cascade
Profile Blog Joined March 2006
Australia5405 Posts
July 22 2007 18:23 GMT
#33
A nice cute "riddle" showing that statistics and probabilities can be confusing as well. It is based on an old swedish TV-show (bingolotto):

You get to choose one of three boxes. One of them will give you a nice prize (car or something) the other two will give you nothing.
You first choose one. The game leader then opens one of the OTHER two boxes (the one you chose is not opened) which turns out to be empty.
You are now presented with the choice to either stick with the one you picked in the first step, or to switch box to the other not opened one.
Should you?
Jumbalumba
Profile Joined February 2007
Australia118 Posts
July 22 2007 18:31 GMT
#34
On July 23 2007 03:23 Cascade wrote:
A nice cute "riddle" showing that statistics and probabilities can be confusing as well. It is based on an old swedish TV-show (bingolotto):

You get to choose one of three boxes. One of them will give you a nice prize (car or something) the other two will give you nothing.
You first choose one. The game leader then opens one of the OTHER two boxes (the one you chose is not opened) which turns out to be empty.
You are now presented with the choice to either stick with the one you picked in the first step, or to switch box to the other not opened one.
Should you?


Haha yeah. That one is good. One should always switch because the probability of winning is greater when switching.
0x64
Profile Blog Joined September 2002
Finland4609 Posts
July 22 2007 18:52 GMT
#35
Simple, They payed 27.
25 to the hotel, and 2 to the guy
they gave 30 and got back 3.
Its all in the wording
Dump of assembler code from 0xffffffec to 0x64: End of assembler dump.
Asta
Profile Joined October 2002
Germany3491 Posts
July 22 2007 20:38 GMT
#36
On July 22 2007 14:03 zizou21 wrote:
my bad i should have named this thread "help me figure out this way to show how easily it is to confuse peopel and to get them to believe bullshit"



you see, there never was a riddle. as ppl pointed out, the calculation is 30 - 3 - 2 = 25 which is obviously correct. in your text it says 27 + 2 = 29 (!= 30) which is an equation that has _nothing_ to do with the whole situation. but some people (including you) never even start to think what the real equation looks like so they don't see the mistake in the text. they simply believe the bs that is fed to them. they even find it amusing or interesting or whatever.

learn to use your head to reflect upon the stuff you read. it might not always be true and sometimes it might even be easy to see that it isn't. for example in this case i'm sure, if it wasn't for that misleading sentence in the text, you would have seen that there is no riddle at all and you would have calculated it right yourself (30 - 2 - 3 = 25). it's not like the math behind it was difficult. not even for someone who sucks at math.
mdominik86
Profile Joined November 2006
Canada142 Posts
July 22 2007 22:44 GMT
#37
he got $5 from the homel clerk, kept $2 and gave $1 to each of the other guys. would it make more sence if he kep $3 and gave each of them $1 each because 3 + 1 + 1 = 5.
evanthebouncy!
Profile Blog Joined June 2006
United States12796 Posts
July 22 2007 23:25 GMT
#38
You are paying 25 for a hotel not 30.
You falsely assumed that you are still paying for 30 dollars, and added 2 to 27 to make 29 and become confused.
You should subtract 2 from 27 to make 25, which is the true price of the hotel.
Life is run, it is dance, it is fast, passionate and BAM!, you dance and sing and booze while you can for now is the time and time is mine. Smile and laugh when still can for now is the time and soon you die!
niteReloaded
Profile Blog Joined February 2007
Croatia5282 Posts
July 22 2007 23:28 GMT
#39
On July 23 2007 03:31 Jumbalumba wrote:
Show nested quote +
On July 23 2007 03:23 Cascade wrote:
A nice cute "riddle" showing that statistics and probabilities can be confusing as well. It is based on an old swedish TV-show (bingolotto):

You get to choose one of three boxes. One of them will give you a nice prize (car or something) the other two will give you nothing.
You first choose one. The game leader then opens one of the OTHER two boxes (the one you chose is not opened) which turns out to be empty.
You are now presented with the choice to either stick with the one you picked in the first step, or to switch box to the other not opened one.
Should you?


Haha yeah. That one is good. One should always switch because the probability of winning is greater when switching.

explain this please?
evanthebouncy!
Profile Blog Joined June 2006
United States12796 Posts
Last Edited: 2007-07-23 01:11:18
July 22 2007 23:32 GMT
#40
On July 23 2007 03:31 Jumbalumba wrote:
Show nested quote +
On July 23 2007 03:23 Cascade wrote:
A nice cute "riddle" showing that statistics and probabilities can be confusing as well. It is based on an old swedish TV-show (bingolotto):

You get to choose one of three boxes. One of them will give you a nice prize (car or something) the other two will give you nothing.
You first choose one. The game leader then opens one of the OTHER two boxes (the one you chose is not opened) which turns out to be empty.
You are now presented with the choice to either stick with the one you picked in the first step, or to switch box to the other not opened one.
Should you?


Haha yeah. That one is good. One should always switch because the probability of winning is greater when switching.


Ninja edit!


Nope! :p You got tricked.

The probability is exactly the same. The host always knows which box is empty, because if he opens the one with the prizes the show is over.

Now, imagine you have 3 boxes
[x] [1] [2], may the "x" be the prize, and 1, 2 be the empty boxes.

There are some possibilities we can discuss:

You chose box [x], the host open empty box 1 or 2.
You are left with 2 boxes, one with prize, one with no prize, the chances are 1/2

You choose box [1], the host open empty box 2.
You are left with 2 boxes, one with prize, one with no prize, the chances are 1/2

You choose box [2], the host open empty box 1.
You are left with 2 boxes, one with prize, one with no prize, the chances are 1/2


There is a similar trick where people try to guess the bean under the 3 cups and the host always flip over an empty cup. It does not change the outcome of switching or not switching the cups.
Life is run, it is dance, it is fast, passionate and BAM!, you dance and sing and booze while you can for now is the time and time is mine. Smile and laugh when still can for now is the time and soon you die!
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