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Significant numbers question.

Forum Index > General Forum
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1 2 Next All
Sfydjklm
Profile Blog Joined April 2005
United States9218 Posts
September 15 2005 08:44 GMT
#1
In a calculation involving multiplication, division, trigonometric functions, etc., the number of significant digits in an answer should equal the least number of significant digits in any one of the numbers being multiplied, divided etc.
i dont really get it.
Say i need to divide 10.27 by 10.2, the answer should feature 3 significant numbers?
doesnt really make sense, since one of my measurments is only correct to the tenth, how can the answer have 2 digits after decimal?-.-a
twitter.com/therealdhalism | "Trying out Z = lots of losses vs inferior players until you figure out how to do it well (if it even works)."- Liquid'Tyler
ColdSoup
Profile Joined February 2005
United States447 Posts
September 15 2005 08:46 GMT
#2
and this folks is why i hate math
Sfydjklm
Profile Blog Joined April 2005
United States9218 Posts
September 15 2005 08:47 GMT
#3
Its chemistry actually~~
twitter.com/therealdhalism | "Trying out Z = lots of losses vs inferior players until you figure out how to do it well (if it even works)."- Liquid'Tyler
SChasu
Profile Joined October 2003
United States1505 Posts
Last Edited: 2005-09-15 12:13:03
September 15 2005 08:47 GMT
#4
edit: im retarded. (to think im in physics)
<--terrible explainer...
totalbiscuit is awful at casting.
Sfydjklm
Profile Blog Joined April 2005
United States9218 Posts
September 15 2005 08:52 GMT
#5
On September 15 2005 17:47 SS-guy wrote:
if you mean it has like .004 or w/e there are still 3 significant digits. its not significant by a place. its significant by how many numbers there are.

my question is why there should be 2 places after the decimal in the answer, when my worst measurement's accuracy is only 1 digit.
twitter.com/therealdhalism | "Trying out Z = lots of losses vs inferior players until you figure out how to do it well (if it even works)."- Liquid'Tyler
AK-Nemesis
Profile Joined December 2002
2005 Posts
September 15 2005 08:56 GMT
#6
10.27 * 10.2

10.27 has 4 sig fig
10.2 has 3...

you use the least, which is 3 sig fig.. so your answer is only up to the tenth... what is so hard about this? if you don't get it.. i suggest you drop this course, whatever comes after this is a lot more harder than sig fig
Nemesis has left the building~
Sfydjklm
Profile Blog Joined April 2005
United States9218 Posts
Last Edited: 2005-09-15 09:01:02
September 15 2005 08:58 GMT
#7
On September 15 2005 17:56 AK-Nemesis wrote:
10.27 * 10.2

10.27 has 4 sig fig
10.2 has 3...

you use the least, which is 3 sig fig.. so your answer is only up to the tenth... what is so hard about this? if you don't get it.. i suggest you drop this course, whatever comes after this is a lot more harder than sig fig

how is it up to 10th if there is 3 sig figures? its gonna be 1.01

I am not asking what the answer is
I am asking why its not treated like addition, for example, where the places after decimal are counted.

p.s.: Its division not multiplication joo
twitter.com/therealdhalism | "Trying out Z = lots of losses vs inferior players until you figure out how to do it well (if it even works)."- Liquid'Tyler
AK-Nemesis
Profile Joined December 2002
2005 Posts
September 15 2005 09:14 GMT
#8
On September 15 2005 17:58 Sfydjklm wrote:
Show nested quote +
On September 15 2005 17:56 AK-Nemesis wrote:
10.27 * 10.2

10.27 has 4 sig fig
10.2 has 3...

you use the least, which is 3 sig fig.. so your answer is only up to the tenth... what is so hard about this? if you don't get it.. i suggest you drop this course, whatever comes after this is a lot more harder than sig fig

how is it up to 10th if there is 3 sig figures? its gonna be 1.01

I am not asking what the answer is
I am asking why its not treated like addition, for example, where the places after decimal are counted.

p.s.: Its division not multiplication joo


my mistake about saying the tenth thing, once again i posted watching reading the entire post, sorry

but still, the sig fig is just done that way, and it has a good reason for it altho i don't remember it exactly and don't want to bother finding out
Nemesis has left the building~
teh leet newb
Profile Blog Joined January 2005
United States1999 Posts
September 15 2005 09:33 GMT
#9
On September 15 2005 17:47 SS-guy wrote:
if you mean it has like .004 or w/e there are still 3 significant digits. its not significant by a place. its significant by how many numbers there are.


That is incorrect. Placeholder digits do not count towards sig figs. Final zeros, however, do. Ex: 0.00009000 has 4 sig figs (9000).

To the OP: Yeah, as AK-Nemesis said, multiplication/division isn't treated like addition/subtraction because well, that's just the way it is. I'm only in 10th grade chem, so I haven't learned why yet -_-;
"The best argument against democracy is a five-minute conversation with the average voter." - Winston Churchill
Chibi[OWNS]
Profile Joined May 2003
United Kingdom10597 Posts
September 15 2005 09:35 GMT
#10
--- Nuked ---
Ender
Profile Blog Joined October 2003
United States294 Posts
September 15 2005 09:46 GMT
#11
Look, just think about it this way: when you're doing a problem, you're answer can't be any more accurate the least bit of information you have. So if you have two pieces of information, like 1.23 or 2.4 in the beginning, you're answer can't be any more exact than the least accurate information you have, in this case 2.4 because it has the least amount of significant digits. Sig fig are just a way to quantify the accuracy of data. A lot of teachers dont even care about sig fig, since ideally you're supposed to round every number you get in every step of a problem. But since most chemistry and physics teachers just want their students to learn chemistry or physics, they dont care much. Still, it's not too hard to use it.
The beatings will continue until the morale improves.
Sfydjklm
Profile Blog Joined April 2005
United States9218 Posts
September 15 2005 09:49 GMT
#12
Is it really so hard to comprehend what i write?=/
twitter.com/therealdhalism | "Trying out Z = lots of losses vs inferior players until you figure out how to do it well (if it even works)."- Liquid'Tyler
Chill
Profile Blog Joined January 2005
Calgary25979 Posts
September 15 2005 09:50 GMT
#13
It makes sense. Your answer should have 3 significant digits. The fact that your equipment was only accurate to the tenths no longer matters when you apply some form of manipulation to the data. If you rounded the data properly beforehand it should all come out in the wash.
Moderator
Chibi[OWNS]
Profile Joined May 2003
United Kingdom10597 Posts
September 15 2005 09:52 GMT
#14
--- Nuked ---
ArseniC-2
Profile Joined August 2005
United States131 Posts
September 15 2005 09:59 GMT
#15
On September 15 2005 18:33 teh leet newb wrote:
Show nested quote +
On September 15 2005 17:47 SS-guy wrote:
if you mean it has like .004 or w/e there are still 3 significant digits. its not significant by a place. its significant by how many numbers there are.


That is incorrect. Placeholder digits do not count towards sig figs. Final zeros, however, do. Ex: 0.00009000 has 4 sig figs (9000).


Yep, SS-guy was wrong.

On September 15 2005 18:46 Ender wrote:
Look, just think about it this way: when you're doing a problem, you're answer can't be any more accurate the least bit of information you have. So if you have two pieces of information, like 1.23 or 2.4 in the beginning, you're answer can't be any more exact than the least accurate information you have, in this case 2.4 because it has the least amount of significant digits. Sig fig are just a way to quantify the accuracy of data. A lot of teachers dont even care about sig fig, since ideally you're supposed to round every number you get in every step of a problem. But since most chemistry and physics teachers just want their students to learn chemistry or physics, they dont care much. Still, it's not too hard to use it.


He is right too. My H chem teacher was a nutcase, and we had to do everything with sig. figs, no matter how minor, and if he messed up sig figs even slightly, we lost at least 1/2 credit for the entire problem.

HeadBangaa
Profile Blog Joined July 2004
United States6512 Posts
Last Edited: 2005-09-15 10:11:34
September 15 2005 10:11 GMT
#16
On September 15 2005 17:56 AK-Nemesis wrote:
10.27 * 10.2

10.27 has 4 sig fig
10.2 has 3...

you use the least, which is 3 sig fig.. so your answer is only up to the tenth... what is so hard about this? if you don't get it.. i suggest you drop this course, whatever comes after this is a lot more harder than sig fig
Haha, you tried to be condescending but made an ass out of yourself :p
People who fail to distinguish Socratic Method from malicious trolling are sadly stupid and not worth a response.
1INK
Profile Joined November 2004
United States630 Posts
September 15 2005 10:45 GMT
#17
i always thought these were intuitive o.O
Bill307
Profile Blog Joined October 2002
Canada9103 Posts
Last Edited: 2005-09-15 10:49:48
September 15 2005 10:47 GMT
#18
Divide 10.2 (3 digits of accuracy) by 1.00 x 10^1 (also 3 digits of accuracy).

10.2
---------------- = 1.02
1.00 x 10^1

The answer is 1.02. Do you see why it is accurate to 2 decimal places even though the original (10.2) is accurate to 1 decimal?

In general, the accuracy of a number does NOT depend on the # of decimal places! Maybe you just see it that way because almost every example you've encountered in real life so far has been like that. But in reality, the accuracy of a number depends on the # of significant digits, NOT JUST THE DECIMALS!

Example: "6,500 people have been confirmed dead." How many significant digits does this have? Probably just two: 6 and 5. This means that there were between 6,450 and 6,549 deaths, because all of these numbers round to 6,500. In contrast, if all four digits were significant, then there were EXACTLY 6,500 deaths.

Now let's make a trivial change to this figure. We can also say that 6.5 thousand deaths have been confirmed. Or, we can say that 0.0065 million deaths have been confirmed.

6,500 has 0 decimal digits
6.5 has 1 decimal digit
0.0065 has 4 decimal digits
But they ALL have TWO significant digits. They are all accurate to 2 digits. This is an example of why the # of significant digits is NOT the # of decimal digits.
Syst[eM]
Profile Joined August 2005
335 Posts
September 15 2005 10:55 GMT
#19
Bill307, thank you, I now understand ^^
Luhh
Profile Joined October 2003
Sweden2974 Posts
September 15 2005 10:57 GMT
#20
On September 15 2005 17:44 Sfydjklm wrote:
In a calculation involving multiplication, division, trigonometric functions, etc., the number of significant digits in an answer should equal the least number of significant digits in any one of the numbers being multiplied, divided etc.
i dont really get it.
Say i need to divide 10.27 by 10.2, the answer should feature 3 significant numbers?
doesnt really make sense, since one of my measurments is only correct to the tenth, how can the answer have 2 digits after decimal?-.-a

Highest range compared to lowest range by numbers given in the example?

10.274/10.15=1.012.. 1.01
10.265/10.24=1.002.. 1.00

1.01=/=1.00

Cute. Though this was an extreme example...
I wouldn´t call him stupid, but let´s just say he´s unlucky when thinking...
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