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I'm finding the measure of the angle is equal to 0 degrees according to my angle chasing method. Bear with me, I'm a bit sleepy.
First I just split the triangle into 5 smaller triangles. It is not certain whether any of the triangles are similar. Then I start filling in angles and variables coming out to five variables and four equations.
I could use substitution and stuff but that stuff takes time, so I put my four equations into a 4*6 matrix and use elementary row operation calculators to get my answer in a final form.
A B C D E constant
1 0 0 -1 -1 0
0 1 0 1 0 0
0 0 1 -2 -1 0
0 0 0 0 0 1
Depending on how you assign your variables, your rref will look slightly different.
Which means that my fourth and fifth variables are parameters and could therefore be anything. The second row of the rref is that 1B + 1D = 0
=> B = 0 and D = 0 since there are no such things as negative angles. It just so happens that B for me is equal to the angle DEB.
Now A and C depend on the other parameter E and they are all the same. However when I plug in a random value (10degrees) for that parameter, I get a big scalene triangle. edit: nevermind that
I'm just gonna say this is unsolvable.ed
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my friends wasted their time graphing this in various cases, and found that the angle is definitely *not* fixed.
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Please post a legit problem jeez, wasting people's time..
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this is quite possibly one of the best trolls i have ever seen
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On March 17 2010 13:32 Caller wrote:
this is quite possibly one of the best trolls i have ever seen
this
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Yeah I think Caller is right... we just got owned.
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You're never going to solve it. There must be a missing part, like what is the angle of DEB when the area of the triangle is largest or some other addition to the problem. I actually tried to solve a similar problem way back when I took calculus involving circles(because two radius are equal in length). I spend 4 months trying to get an answer until I asked my professor and I was told it was not solvable -_-.
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What grade level are you OP?
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It looks like we all got math trolled
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Someone post this to /sci/ on 4chan... 
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Damn. I went through all the trouble of graphing it only to find it out that the angle isn't the same various triangles. What a waste of time.
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On March 17 2010 13:26 Chairman Ray wrote:
It actually is unsolvable. Try plugging in any value in the range (0,110) and it will be correct.
Assuming A is a number, the lowest possible value is 35.00000000000000000000....01
So we have 35 < x <= 110.
In other words.... yeah it's obvious that there is no unique solution. But at least we can establish some reasonable bounds.
Check the boundary conditions:
A = .000000000000001 (or just 0 and make it a rectangle) Your answer is 35.
A = 60. Your answer is 110.
Any bigger than that and you don't have a triangle, any smaller, well, the initial conditions are not achievable.
Please... nobody else post responses and close this topic.
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Canada2175 Posts
Edit: i'm making fun of people without reading their whole posts. I fail.
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@ ^
God damn it.
35 < x <= 110
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On March 17 2010 14:04 Saturnize wrote:
Angle DEB is 50
You're wrong. It's 51.
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On March 17 2010 14:05 love1another wrote:You're wrong. It's 51.
Personally, I got 42.
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Naw. Sorry I just checked it's 38... Please read thread before posting.
Edit: Shit it IS 42. Douglas Adams is rolling over in his grave.
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I think you're math teacher after 6 months came to the conclusion that it is unsolvable.
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EPT
