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[H] Understading Newton's Laws

Blogs > il0seonpurpose
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il0seonpurpose
Profile Blog Joined January 2007
Korea (South)5638 Posts
December 10 2008 03:22 GMT
#1
I guess to most people on teamliquid, this is really basic physics, I'm taking it in high school because its required and its basically just advanced. But I don't get the third law, where for every action there is an equal and opposite reaction. The problem I have understanding is that we learned the second law of F=ma and other forces, learning about free body diagrams; how Fa (applied) and Ff(friction) are opposites and they don't always equal each other out. This paper I'm reading off of says "Both forces are exactly the same size. They are equal in magnitude."

Also, there's this little project where we get pictures and identify the laws being portrayed. I have a picture of a basketball player shooting, it's the second law but I don't know how to explain it well. I also have a picture of a baseball player and I have the same problem.

Thanks

micronesia
Profile Blog Joined July 2006
United States24779 Posts
Last Edited: 2008-12-10 03:40:54
December 10 2008 03:39 GMT
#2
Newton's Third Law: For every action there is an equal and opposite reaction.

What does this mean?

For every force, there is an equal and opposite reaction force. It's best to see this with examples, I think.

Example 1:

You push on a wall with your hands. You apply a 100 Newton force. What happens? You fall backwards. Why? Because the reaction force (the wall pushing back on you) was 100 N which accelerated you backwards.

Example 2:

The earth pulls you down with a force of gravity equal to 9.8 times your mass in kilograms. According to Newton's Third law, this means you pull the Earth back up with the same force. Is this true? Well, yes it is. Even though your gravity field is much weaker, the earth has such a huge mass that it experiences a force towards you equal to your weight. However, the Earth is so massive that it shrugs off the ~500 Newton force and doesn't move.

edit: for the basketball player, I guess you should consider that while your hand is pushing the ball, you are applying a force, so the ball accelerates (up until the moment the ball isn't in contact with the hand anymore)
ModeratorThere are animal crackers for people and there are people crackers for animals.
Nitrogen
Profile Blog Joined February 2008
United States5345 Posts
December 10 2008 03:40 GMT
#3
On December 10 2008 12:22 il0seonpurpose wrote:
I guess to most people on teamliquid, this is really basic physics, I'm taking it in high school because its required and its basically just advanced. But I don't get the third law, where for every action there is an equal and opposite reaction. The problem I have understanding is that we learned the second law of F=ma and other forces, learning about free body diagrams; how Fa (applied) and Ff(friction) are opposites and they don't always equal each other out. This paper I'm reading off of says "Both forces are exactly the same size. They are equal in magnitude."

Also, there's this little project where we get pictures and identify the laws being portrayed. I have a picture of a basketball player shooting, it's the second law but I don't know how to explain it well. I also have a picture of a baseball player and I have the same problem.

Thanks


i think the paper means before the object is put into motion, if you push on an object the static friction will be equal to the force applied until you go over the coefficient of static friction multiplied by the normal force.

and the basketball one is probably just how when he throws the basketball he receives the same force as the basketball, but his mass is greater so he gets less of an acceleration. hope that helps
UNFUCK YOURSELF
Abydos1
Profile Blog Joined October 2008
United States832 Posts
Last Edited: 2008-12-10 03:51:08
December 10 2008 03:42 GMT
#4
Friction and force applied are not an action/reaction pair. If you use that as an example, say a car wheel's friction on the ground, the action/reaction pair is the force of friction on the car tire and the force of friction on the road(earth). Think of a spaceship, the spaceship burns fuel to propel itself forward, the fuel is expelled backwards with the same force in the opposite direction.

Edit: as nitrogen pointed out if an object is stationary force applied equals the force from friction since the object isn't moving; otherwise the difference causes an acceleration on the object.

Hope that helps...
"...perhaps the greatest joy possible in Starcraft, being accused of being a maphacker" - Day[9]
OneOther
Profile Blog Joined August 2004
United States10774 Posts
December 10 2008 03:43 GMT
#5
...This is AP Physics?
micronesia pretty much covered the third law. As for the picture of a basketball player shooting, is it referring to the ball or the player? Either way there are a lot of things you could talk about. You apply a force to the ball, so it starts moving. You can also talk about the player jumping vs F=mg. There are tons of other stuff as well
micronesia
Profile Blog Joined July 2006
United States24779 Posts
December 10 2008 03:45 GMT
#6
On December 10 2008 12:42 Abydos1 wrote:
Friction and force applied are not an action/reaction pair. If you use that as an example, say a car wheel's friction on the ground, the action/reaction pair is the force of friction on the car wheel and the force of friction on the road(earth). Think of a spaceship, the spaceship burns fuel to propel itself forward, the fuel is expelled backwards with the same force in the opposite direction.

Edit: as nitrogen pointed out if an object is stationary force applied equals the force from friction since the object isn't moving; otherwise the difference causes an acceleration on the object.

Hope that helps...

100% accurate but you might want to say tire instead of wheel :p
ModeratorThere are animal crackers for people and there are people crackers for animals.
Abydos1
Profile Blog Joined October 2008
United States832 Posts
December 10 2008 03:51 GMT
#7
On December 10 2008 12:45 micronesia wrote:
Show nested quote +
On December 10 2008 12:42 Abydos1 wrote:
Friction and force applied are not an action/reaction pair. If you use that as an example, say a car wheel's friction on the ground, the action/reaction pair is the force of friction on the car wheel and the force of friction on the road(earth). Think of a spaceship, the spaceship burns fuel to propel itself forward, the fuel is expelled backwards with the same force in the opposite direction.

Edit: as nitrogen pointed out if an object is stationary force applied equals the force from friction since the object isn't moving; otherwise the difference causes an acceleration on the object.

Hope that helps...

100% accurate but you might want to say tire instead of wheel :p


Fine fine, changed it to tire to avoid ambiguity
"...perhaps the greatest joy possible in Starcraft, being accused of being a maphacker" - Day[9]
Kentor *
Profile Blog Joined December 2007
United States5784 Posts
December 10 2008 04:13 GMT
#8
An action/reaction pair always act on two different objects.
HeavOnEarth
Profile Blog Joined March 2008
United States7087 Posts
December 10 2008 04:19 GMT
#9
http://letmegooglethatforyou.com/?q=Newton's Third Law
;p
"come korea next time... FXO house... 10 korean, 10 korean"
eth0x
Profile Blog Joined August 2008
Canada208 Posts
December 10 2008 04:28 GMT
#10
For every action there is an equal and opposite reaction. What this means is that if you have an Fa of 10N on a car, to the left, that car will have a 10N push on you, to the right. Its really quite simple once you get used to forces.

Forces always act in pairs by the way.
Because he is Mantoss, the incarnation of masculinity and awesomeness.
HeavOnEarth
Profile Blog Joined March 2008
United States7087 Posts
December 10 2008 04:31 GMT
#11
Hope you have your trig down btw, inclined planes and co-ordinate changes are simple after u get them but hard to understand wtf is going at first xD
For freebody diagrams just label everything, draw a picture , then calculate your forces
Some general equations are Fn*u(coeffcient of friction) = Ff(Force of friction, acts against Applied force or Fa) And Applied force - force of Friction = MA.
Sometimes you aren't given Fn, and you have to know for Newton's third law, (MG) force due to gravity = Fn, for example if you are 100 Kg standing still, Fn = 100Kg*9.81m/s^2 = Newton (kg*m/s^2); because you push on the floor with that, it pushes back Fn= perpendicular force acting against an object w/ wall, etc.
For example if you push horizontally with a force of 150N against 10Kg box and it slides across a surface with a coefficient of friction of .5, what's the acceleration?
Fn= Mg ( g = 9.81 gravity )
Fn*.5 = Ff
150N - Ff = MA
MA/ 10Kg = A
+ Show Spoiler +

you should get about 10m/s for acclerationi think xd
"come korea next time... FXO house... 10 korean, 10 korean"
thoraxe
Profile Blog Joined March 2007
United States1449 Posts
December 10 2008 04:34 GMT
#12
Its pretty weird how a wall can push back at you.
Obama singing "Kick Ass" Song: http://www.youtube.com/watch?v=yghFBt-fXmw&feature=player_embedde
Abydos1
Profile Blog Joined October 2008
United States832 Posts
December 10 2008 04:37 GMT
#13
On December 10 2008 13:34 thoraxe wrote:
Its pretty weird how a wall can push back at you.


Why do you think it hurts when you punch one?
"...perhaps the greatest joy possible in Starcraft, being accused of being a maphacker" - Day[9]
Faronel
Profile Blog Joined July 2008
United States658 Posts
December 10 2008 05:06 GMT
#14
I imagine micronesia as some sort of cape wearing hero in a physics classroom. Once the Teamliquid Forum Physics Thread Detector goes off, he immediately comes and resolves the topic.
C'est la vie...
il0seonpurpose
Profile Blog Joined January 2007
Korea (South)5638 Posts
December 10 2008 05:14 GMT
#15
On December 10 2008 14:06 Faronel wrote:
I imagine micronesia as some sort of cape wearing hero in a physics classroom. Once the Teamliquid Forum Physics Thread Detector goes off, he immediately comes and resolves the topic.


LOL


Ok thanks guys, I think I got it
Tynuji
Profile Blog Joined June 2007
127 Posts
Last Edited: 2008-12-10 06:15:46
December 10 2008 06:13 GMT
#16
I just did my physics exam (we got raped so bad) and had one of the Newton's Third Law questions. Remember that objects being connected to each other (if by an unstretchable string with mass or if one slides into the other), you have to solve the question by treating it as a system (I lost 20% because I did them seperately =[) where you add the masses to determine acceleration. It took my a fuckton of time to understand that (to bad I thought the string makes it into a trick question).

Also, from what I've seen, a mastery of equation manipulation will really help you in short answer questions. Meaning, manipulating the equations before substituting numbers in. You also cannot push a rope.

OmgIRok
Profile Blog Joined June 2008
Taiwan2699 Posts
Last Edited: 2008-12-10 06:31:02
December 10 2008 06:21 GMT
#17
Well, if you've seen baseball, and you've seen players at the bat swing, there's your action reaction.

EX: A-Rod is up to bat, the pitcher throws a fastball and A-Rod swings. His lower body will turn the opposite direction of the upper body swing, because of Newton's 3rd Law (Action and Reaction)

Let's say that he wasn't standing on the dirt (where there is friction, so the body turning the opposite direction is very minor), and he was standing on a rotating plate (like the ones when you go out to eat at a restaurant, you can spin around to pass food from one person to the next). There is less friction on the plate, so as A-Rod swings, his upper body turns counter-clock wise (he's a right handed person).
[image loading]
(ignore the sissy pose)
Back to the body turning counter-clock wise. Now in order for his body to swing with that force and turn that direction, he is pushing his feet into the ground at an opposite direction as the swing. Now let's imagine that instead of standing in an area with high friction, he his now standing, ready to bat on the plate. As he try to apply force in his feet for the out-of-the-park Grand Slam, it would cause the plate to spin, taking his feet along with it, causing his feet to go in the opposite direction of A-Rod's swinging direction.

[image loading]

Here we see Ted Williams swinging. He is a left-handed batter so we'll have to look at it from a left handed players POV. He swings clockwise, but take a look at the right foot, it is pushing in the counter-clockwise direction.

Hope this helps with your Baseball picture understanding. =]
I learned all this in 5th grade I can't believe I haven't forgotten.
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Tynuji
Profile Blog Joined June 2007
127 Posts
Last Edited: 2008-12-10 06:52:57
December 10 2008 06:49 GMT
#18
A very good example would be walking. When you walk, you are actually applying a force behind you towards the ground and as a result, the ground pushes back on you which propells you forward. This is because of the differences in your mass and the Earth (and friction of course, because that's the force pushing you forward! The force opposite of your applied!)

Another good example of Newton's third law is being hit by a car. This really expresses the point that the force acts on DIFFERENT objects. That is, you have two equal but opposite forces, a lot of people (beginners) may say, doesn't that mean the net force is zero? That's incorrect because the action/reaction pair apply to different objects. So when a man is hit by a car, the reason he goes flying while the car barely moves is because of combining Newton's second law with that law.

You learned F = ma. Since you know that the force they experience will have equal magnitudes but opposite directions. So you have an average joe that I'll weigh as about 75kg. A car we'll make 1000kg. So if the car hits the man with a let's say 1000 N force, the man will also apply a force back with 1000 N. However, the acceleration of both objects will be different when you solve for acceleration for both objects because of the differences in their masses.

So for the guy, he would be accelerating at F/m = a. 1000N/75kg = 13.333 m/s^2 (remember Newtons is kg*m/s^2 I think). The car however would be accelerating 1000N/1000kg = 1 m/s^2.

You may also need to learn some acceleration constraints. Such as when an object on a frictionless surface is has a rope on a massless pulley with another block hanging from the edge. I never took high school physics but the university course (which first year is apparently review, damn you philosophy) makes use of a buttload of word problem analysis. So just knowing the concepts aren't enough, but applying them to solve problems is very important.
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