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Quick help with Math - Page 2

Blogs > rushz0rz
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rushz0rz
Profile Blog Joined February 2006
Canada5300 Posts
Last Edited: 2010-11-28 08:42:01
September 17 2008 06:35 GMT
#21
IntoTheRainBOw fan~
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
September 17 2008 06:36 GMT
#22
On September 17 2008 15:31 HeavOnEarth wrote:
Show nested quote +
On September 17 2008 15:27 EtherealDeath wrote:
Oh don't spoil the answer of 1728/(3sqrt(3)) HeavOnEarth ;-(

Of course my mental math is extremely inconsistent at this time of morning....

oh i just do uh whatever that property of multiplication is called where instead of 144 x 12,
you do ( 144 x 2 )+( 144x 10)= ~, 144 x 2 , 288 ,easy in head, 144 x 10, 1440, easy in head, so add them


... 1440
...+ 288 = 1728, carry the one :p



Oh I just multiply it out cause it takes less than a second, at which point time is irrelevant.

And it's not 1728, not the answer to the question anyways :-P
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
September 17 2008 06:37 GMT
#23
hmm get on IRC and msg me (EtherealDeath or EtherealFlash, something like that i forget which)
SayaSP
Profile Blog Joined February 2007
Laos5494 Posts
September 17 2008 06:38 GMT
#24
Isn't the formula for finding the diagonal like sqrt(3)*side
[iHs]SSP | I-NO-KI BOM-BA-YE | のヮの http://tinyurl.com/MLIStheCV , MLIS.
HeavOnEarth
Profile Blog Joined March 2008
United States7087 Posts
September 17 2008 06:38 GMT
#25
what we're not going to give him the answer are we :O
"come korea next time... FXO house... 10 korean, 10 korean"
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
September 17 2008 06:39 GMT
#26
On September 17 2008 15:38 SayaSP wrote:
Isn't the formula for finding the diagonal like sqrt(3)*side


That would be correct. But gotta let him find out why :-P
HeavOnEarth
Profile Blog Joined March 2008
United States7087 Posts
Last Edited: 2008-09-17 06:55:56
September 17 2008 06:41 GMT
#27
[image loading]
"come korea next time... FXO house... 10 korean, 10 korean"
ketomai
Profile Joined June 2007
United States2789 Posts
September 17 2008 06:45 GMT
#28
I thought it was rt 2 * side o.O;

My advice, draw a picture.
geometryb
Profile Blog Joined November 2005
United States1249 Posts
September 17 2008 07:13 GMT
#29
lol
Nytefish
Profile Blog Joined December 2007
United Kingdom4282 Posts
Last Edited: 2008-09-17 10:56:32
September 17 2008 10:55 GMT
#30
You guys are pretty mean, it doesn't help to say "duuuh it's obvious" If you don't want to help then don't post. If you're just here to show off your (relatively) amazing Maths skills then go work in a nursery.

For question one it's just trial and error. Starting with the 2nd statement and finding an 'x' that agrees with the first statement (and your common sense).

[image loading]


Using this picture and the fact that the longer diagonal is the diameter of the sphere, you can label a side (of the cube) 'x' and use some basic Pythagorus to find the longer diagonal in terms of x.
No I'm never serious.
sigma_x
Profile Joined March 2008
Australia285 Posts
September 17 2008 14:01 GMT
#31
Question 1 is not trial and error. He was born in the year (x^2-x), so if he's over 100 years old today, you need to solve 2008-(x^2-x)>100, so that the answer will then be 1982-(x^2-x). This yields more than one solution, and in fact yields infinitely many if you consider that age does not have to be an integer.
Nytefish
Profile Blog Joined December 2007
United Kingdom4282 Posts
September 17 2008 14:38 GMT
#32
Well there is a proper approach, but simply trying values of x^2 is easier and faster.
I think assuming age is an integer is adequate, no need to be so "correct".
No I'm never serious.
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