x = 6.0
y = 12.0
L1 = 12"
L2 = 10"
R = sqrtof(10^2+12^2) = 15.62
theta = tan^-1(y/x) = tan^-1(12/6) = 63.43º
How do I find theta1, and theta2?
Sorry for the yellow:
![[image loading]](http://i25.tinypic.com/m7scz.jpg)





Blogs > Raithed |
Raithed
China7078 Posts
x = 6.0 y = 12.0 L1 = 12" L2 = 10" R = sqrtof(10^2+12^2) = 15.62 theta = tan^-1(y/x) = tan^-1(12/6) = 63.43º How do I find theta1, and theta2? Sorry for the yellow: ![]() ![]() ![]() ![]() ![]() ![]() | ||
hellhawk123
United States84 Posts
| ||
Raithed
China7078 Posts
| ||
Lemonwalrus
United States5465 Posts
Edit: oh, nvmd, I think. Edit2: oh, nvmd the nvmd. | ||
fight_or_flight
United States3988 Posts
On January 31 2008 11:31 Raithed wrote: No, R = sqrtof(10^2+12^2) = 15.62. Not x, y, but a, b. I don't remember those laws. :[ how is R equal to that? you can only use pythagorean theorem for a right-triangle. I'm kind of confused on the question, you should word it better. edit: lol at the theta | ||
Raithed
China7078 Posts
| ||
hellhawk123
United States84 Posts
also law of cosines is given triangle w/ lengths a b c and respective angles alpha beta gamma, c^2=a^2+b^2-2abcos(gamma) (pythag theorem is when gamma=pi/2) | ||
fight_or_flight
United States3988 Posts
On January 31 2008 11:36 hellhawk123 wrote: sorry but how are you getting R? I assumed x=x component of R and y=y component of R? also law of cosines is given triangle w/ lengths a b c and respective angles alpha beta gamma, c^2=a^2+b^2-2abcos(gamma) Correct. If R is given by the (x,y) components, then it should be easy to plug in a, b, c and solve for gamma. | ||
Raithed
China7078 Posts
So basically it is: 13.42^2 = 10^2 + 12^2 - 2(10)(12)cos(gamma) 180 = 100+144 - 240cos(gamma) 180 = 244 - 240cos(gamma) Oh fuck I fail at Algebra, I know the gamma has to be alone, so move the (244 - 240cos) to the other side? | ||
hellhawk123
United States84 Posts
| ||
Raithed
China7078 Posts
Thanks hellhawk, so that would be theta1? | ||
hellhawk123
United States84 Posts
| ||
Raithed
China7078 Posts
| ||
hellhawk123
United States84 Posts
| ||
Kwidowmaker
Canada978 Posts
| ||
Raithed
China7078 Posts
| ||
Kwidowmaker
Canada978 Posts
I'm of the understanding that L1 is only the black and not the yellow line. | ||
Raithed
China7078 Posts
| ||
BluzMan
Russian Federation4235 Posts
| ||
Slayer91
Ireland23335 Posts
theta1 is theta minus the angel opposite l2. Finding those angles is a matter of plugging in the cosine rule, right? | ||
| ||
![]() StarCraft 2 StarCraft: Brood War Dota 2 League of Legends Counter-Strike Super Smash Bros Heroes of the Storm Other Games Organizations
StarCraft 2 • Berry_CruncH381 StarCraft: Brood War• AfreecaTV YouTube • intothetv ![]() • Kozan • IndyKCrew ![]() • LaughNgamezSOOP • Migwel ![]() • sooper7s Dota 2 League of Legends |
Wardi Open
Replay Cast
WardiTV European League
ShoWTimE vs sebesdes
Percival vs NightPhoenix
Shameless vs Nicoract
Krystianer vs Scarlett
ByuN vs uThermal
Harstem vs HeRoMaRinE
PiGosaur Monday
uThermal 2v2 Circuit
Replay Cast
The PondCast
Replay Cast
Epic.LAN
CranKy Ducklings
[ Show More ] Epic.LAN
BSL20 Non-Korean Champi…
Bonyth vs Sziky
Dewalt vs Hawk
Hawk vs QiaoGege
Sziky vs Dewalt
Mihu vs Bonyth
Zhanhun vs QiaoGege
QiaoGege vs Fengzi
Sparkling Tuna Cup
Online Event
BSL20 Non-Korean Champi…
Bonyth vs Zhanhun
Dewalt vs Mihu
Hawk vs Sziky
Sziky vs QiaoGege
Mihu vs Hawk
Zhanhun vs Dewalt
Fengzi vs Bonyth
|
|