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Pretty Urgent Help - Calc Midterm in 10 Hrs!

Forum Index > Closed
Post a Reply
exalted
Profile Blog Joined March 2004
United States3612 Posts
November 07 2006 23:33 GMT
#1
Dear TL,

I\'ve been working for the past few hours on these problems and would like some guidance from the math wizards here: Any help as soon as possible would be greatly appreciated - I\'m pretty confident I can at least get a 50 now that I just figured out the basics of delta epsilon proofs!

Question 1:
Find y\' if x^y = y^x

This seems to be a really confusing question because under this situation, x = y. So how can we find y\' if y^y = y^y? It seems the key is with using logarithms, but I am a complete newbie with that. Any alternative methods or a solution would be greatly appreciated.

Question 2:
Show that e = lim as x-> 0+ (1+x)^(1/x)

No idea how to start this one.

Question 3:
State the definitions of
a) lim x-> infinity f(x) = L
b) lim x-> 1 f(x) = infinity

It seems like the only thing I can do is translate it into simple english, by writing... the limit of f(x) as x approaches infinity is L, but this seems too \"simple\". If anyone could confirm that this indeed is the definition I could feel at much more ease.

Question 4:
Show that d/dx ln(x) = 1/x (Assume that de^x/dx = e^x)

I don\'t know this one either.

Any help would be really really sweet. I know there\'s a crusade against HW threads, but this is the last thread I should have to make about this garbage for a while. And I\'ll work on improving my TvP guide for those interested (FA\'s guide is sick good although I don\'t play PvZ)

exalted
too easy
vGl-CoW
Profile Blog Joined December 2002
Belgium8305 Posts
November 07 2006 23:39 GMT
#2
[image loading]
Moderatorfollow me on twitter if u think ur so tough @BooyaCow
Hot_Bid
Profile Blog Joined October 2003
Braavos36402 Posts
November 07 2006 23:40 GMT
#3
have you considered looking on google or reading your book? this isnt exactly the most complex shit
@Hot_Bid on Twitter - ESPORTS life since 2010 - http://i.imgur.com/U2psw.png
Hot_Bid
Profile Blog Joined October 2003
Braavos36402 Posts
November 07 2006 23:42 GMT
#4
oh also,

When Reyes 'roid rages all over one of Saracen's dorky Christian Speed Metal friends, and then lies that he did it because the kid called him a "wetback," the inner circle and the outer circle separate like oil and water -- or cool and dork -- until Saracen sacks up and confesses to Coach Taylor that Reyes was crying racist.

In Depressing Love Triangle Land, Street convinces Riggs to break him out of the rehab facility for a joy ride and they happen to run into Lyla on their way out. And just when you think it couldn't get more awkward than Lyla snuggling with her paralyzed boyfriend while her able-bodied pity fuck watches their two-wheeled dance of desire, it...doesn't. It actually all goes surprisingly well, the three of them really sharing and caring around a campfire. Pretty well, that is, until Street pauses while wheeling himself back to his room and catches a glimpse of Riggs and Lyla hugging goodbye down in the parking lot.

Speaking of suspicious goodbyes. After getting away with being the one who really started Reyes off in the beginning with a racist comment, Voodoo gets cleared by the Sports Judge in another back room deal presided over by Buddy. But when he's put on defense by a still-smarting Coach Taylor, Voodoo brats off about it, and we close the episode with the news -- delivered in a rather untrustworthy manner by Buddy -- that Voodoo's gone back to Louisiana and told a reporter all about the recruiting violations so the Arnett Mead win is in jeopardy. Just like it was at the end of the last episode. What's the Spanish word for "progress"?
@Hot_Bid on Twitter - ESPORTS life since 2010 - http://i.imgur.com/U2psw.png
exalted
Profile Blog Joined March 2004
United States3612 Posts
November 07 2006 23:42 GMT
#5
COME ONNNNNNNNNNNN
too easy
useLess
Profile Blog Joined January 2004
United States4781 Posts
November 07 2006 23:42 GMT
#6
Derivatives? Limits? These look like theyre problems straight out of the book.
Moonlight Shadow
exalted
Profile Blog Joined March 2004
United States3612 Posts
November 07 2006 23:43 GMT
#7
You know that when YOU do it, Hot_Bid, the rest of TL will bandwagon on because you're their Liquiscoop hero. So let me make this Clear that its a plea for help. -_-
too easy
Purind
Profile Blog Joined April 2004
Canada3562 Posts
November 07 2006 23:47 GMT
#8
I believe 3 is horizontal and vertical asymptotic behaviour (dunno how you would define it explicitly)

4) you write y = ln x -> e^y=x, then go chain rule and isolate y'

2) it's something you can find in a textbook. There's no way a calc textbook won't have it, and the book will be easier to read than tl net text (seriously, it took me about 30 seconds to realize what x^y = y^x meant)

1) log both sides and chain rule or something

My math is terribly noob, so I don't feel like going through the problems
Trucy Wright is hot
Hot_Bid
Profile Blog Joined October 2003
Braavos36402 Posts
Last Edited: 2006-11-07 23:49:43
November 07 2006 23:49 GMT
#9
exalted, i am sorry. but principles make no exceptions, crusades stop for no man. progress will have sacrifices, and this thread will be a test of will.

edit: and also, it seems as though you'll get your help anyway
@Hot_Bid on Twitter - ESPORTS life since 2010 - http://i.imgur.com/U2psw.png
Chill
Profile Blog Joined January 2005
Calgary26003 Posts
November 07 2006 23:54 GMT
#10
Question 1
ln(x^y) = ln(y^x)
y*(lnx) = x*(lny)
y = x * lny/lnx
y' = (1*lny/lnx) + (1/y)/(1/x)
y' = lny/lnx + x/y

I'm not sure if this is right... =x let's just say it's been awhile

Question 2
This is neither a question nore worded properly. I can't see what you're getting at. Should that e equals a limit (what?) as x goes to some random formula. Gotcha... x isn't even in the formula with e, e is a number. It goes to e and x goes to anything.

Question 3

Not sure what they're looking for. Part a) has a horizontal asymtote (is that the right word?) at L. Part b) has a vertical asymtote at 1.

Question 4

y = ln(x)
Therefore, x =e^y
Differentiate: dx/dx = e^y * dy/dx
1 = e^y * dy/dx
1 / e^y = dy/dx
By our difinition, e^y = x
1/x = dy/dx
Moderator
exalted
Profile Blog Joined March 2004
United States3612 Posts
November 08 2006 00:02 GMT
#11
Ok i'm reading this in detail now... thank you, and hot_bid, make a card for me, ok?
too easy
Twisted
Profile Blog Joined September 2002
Netherlands13554 Posts
November 08 2006 00:04 GMT
#12
If you make one more homework topic I'm going to ban you.
Moderator
Klogon
Profile Blog Joined November 2002
MURICA15980 Posts
November 08 2006 03:22 GMT
#13
Uhhh just go down the hall and ask someone. You're in college -- use the resources.
Please log in or register to reply.
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