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Probulous
Australia3894 Posts
Because I don't have enough headaches. I am going to need some serious guidance though. There are so many possibilities that this will be a lesson in WIFOM. Would it be correct to ignore who mafia choose for their list? I mean you cannot infer whether they chose all town to ensure a town kill, or put one of their own in to gain some credit. Holy shit end game is going to be epic on this one... Probulous ->  | ||
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Australia3894 Posts
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Australia3894 Posts
Mason - Such a friendly person you are! After the drafting phase you can choose, either I will randomly select one Pro-town person and you will both be able to communicate with each other for the rest of the game, or you can pick one person and you will both be able to communicate with each other for the rest of the game. Maybe I am reading too much into things, but since you can only actually be a mason after the drafting phase this seems redundant. That's not a problem unless I am completely misunderstanding how this works. Can you decide to Mason someone at any time during the game but from then on you cannot change your mind? | ||
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Australia3894 Posts
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Australia3894 Posts
Don't feel pressured to jump out just because others want to play. You legitimately signed up for the game and if you want to play you should not be pushed out by those that missed the deadline. | ||
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Probulous
Australia3894 Posts
Surely it works in a filter situation where people are grouped on how their first number clashes? Ie all those with 7 as their first number are put together. For example if you had [7][1] [7][1] [7][4] The order would be [7][4] [7][1] [7][1] Because their second number clashed. That seems most logical to me. | ||
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Probulous
Australia3894 Posts
On May 10 2012 09:34 wherebugsgo wrote: again, then everyone would pick 1 as the second number. Then all that matters is first number uniqueness. e: think about it this way. one guy picks 2/2. Everyone else picks X/1. The one person with a unique X appears first, 2/2 appears second. Is that fair? Why would you pick 1 as your second number when it is likely to clash and put you at the bottom of whatever group you end up in? In the example above picking 1 made you come last. In your example the [2],[2] would be first. Remember you evaluate the first number first. Your example: [1,1] [1,2] [2,2] [5,1] [1,4] [1,1] This would be ordered into groups based on the first number. So you would have [1,1],[1,2],[1,4],[1,1] [2,2] [5,1] as the groups The order when then be [2,2] [5,1] [1,2] [1,4] [1,1] [1,1] Why is that not fair? | ||
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