|
I'm probably just being stupid, but for some reason this seems difficult to me. I'm posting it in a few places on the internet in case someone can help me out. Thanks in advance!
Let M be a connected, compact, smooth manifold without boundary. Let V denote the (real) vector space of all smooth functions from M into the real line. Call a subspace H of V invariant if whenever h is in H and g is a diffeomorphism of M then h composed with g is in H. Prove that the only invariant subspaces are {0}, V, and the set of constant functions on M.
![0 stars based on 0 ratings](/images/blogs/graystarSmall.gif) ![0 stars based on 0 ratings](/images/blogs/graystarSmall.gif) ![0 stars based on 0 ratings](/images/blogs/graystarSmall.gif) ![0 stars based on 0 ratings](/images/blogs/graystarSmall.gif)
|
Lol this is beyond me, maybe next year xD
and to ur quote: Algebraic Geometry or Starcraft?
Algebraic Geometry any day.
|
Spenguin
Australia3316 Posts
It makes my problem seem Butt Secks Man like.
|
This is due on Monday if anyone can help by then. Nobody on AoPS can solve it quickly so I feel it must be difficult.
|
well, I cant rember the specifics but, first u have to show that it is one-to-one mapping. Meaning u need all dimensions to plot the whole R-axis then. Then u show that the only spaces that maps one-to-one on those requierments are {0} and V. The specifics Im not sure about, but I think this is the way to go. /Jacob
|
|
|
|