Nightmare Math Problem.

On August 21 2011 11:04 Probe1 wrote:
It'd help if you quit smoking cigars when you're trying to solve complex formulas.

On August 21 2011 11:07 Sgany wrote:


Fixed :D Thanks for that sir

On August 21 2011 11:11 cz wrote:


Thanks for what?

On August 21 2011 11:11 Lixler wrote:
I too have devoted much thought to this most interesting of problems. Basically, we assume a constant loading rate and assume that this rate is lower than the playing rate, which is always 1 second/1second. In order to pause the least, we need our loaded amount to reach the total at exactly the same moment our watched amount reaches the total. So we need to pre-load Total - Loading rate*playtime. But playtime = total, so we can simplify to total*(1-loading rate). For a video of, say, 10 seconds and a loading rate of .5 seconds/second, we get that we need to load 5 seconds in advance. During those 5 seconds, we will load 2.5 seconds, putting us at 7.5 seconds. During those 2.5 seconds, we will load 1.25 seconds, putting us at 8.75 seconds. And we will asymptotically approach having watched the video, exactly as Zeno would have predicted.

On August 21 2011 11:19 Hypertension wrote:
How long it takes to buffer 1 second = B
Length of video in seconds = V
Waiting time = B*V-V

On August 21 2011 11:22 Sgany wrote:


That is simple to work out, what I want to know is the time it takes for the video WHILE buffering to reach a point where it is not completely buffered, but I can play it without it having to buffer at all.

On August 21 2011 11:24 Severedevil wrote:
Okay. You know how long the video is supposed to last; we'll call that the 'video time' and denote it by v. You don't know how long the video will take to buffer; we'll call that the 'buffer time', b.)

Now, how long do you have to pause your video and let it pre-buffer? The answer is however long it takes to buffer the full video, minus the amount of time it takes to play the full video, or b - v. If you want that as a percentage of the total buffer time, it's (b - v) / b, which is equal to 1 - (v / b).

You've already found v / b; it's the ratio you calculated. So just subtract it from 1, and you're done. (Multiply by a 100 if you want a percentage.)

So, for 10v:12b, you get 1 - (10/12) = ~17%.

Also, I'm stealing this as a highly relatable algebra problem for students.

On August 21 2011 11:24 Severedevil wrote:
Okay. You know how long the video is supposed to last; we'll call that the 'video time' and denote it by v. You don't know how long the video will take to buffer; we'll call that the 'buffer time', b.)

Now, how long do you have to pause your video and let it pre-buffer? The answer is however long it takes to buffer the full video, minus the amount of time it takes to play the full video, or b - v. If you want that as a percentage of the total buffer time, it's (b - v) / b, which is equal to 1 - (v / b).

You've already found v / b; it's the ratio you calculated. So just subtract it from 1, and you're done. (Multiply by a 100 if you want a percentage.)

So, for 10v:12b, you get 1 - (10/12) = ~17%. (This is the 'critical mass' point. You can start playing the video, and it will finish buffering right before you finish watching it. Assuming the video buffers at a constant rate, which may not be true.)

Also, I'm stealing this as a highly relatable algebra problem for students.

On August 21 2011 12:08 itachisan wrote:
nerds

User was warned for this post

On August 21 2011 14:41 SarR wrote:

Paraphrase:-
"Watching all these people talk about stuff that I cant understand makes me feel like a dumbass and left out because it reminds me that I'm intellectually inadequate which renders me unable to participate in intelligent discussions. In order to salvage some pride, I'm going to attempt to make them feel like they are the losers by labeling them using a word which traditionally carries such connotations thereby making me feel superior by virtue of being intellectually inadequate. In other words I get to be "cool" by not knowing shit"

On August 22 2011 00:52 itachisan wrote:


^ nerd.