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calculus change of rates

Blogs > Raithed
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Raithed
Profile Blog Joined May 2007
China7078 Posts
Last Edited: 2008-06-01 23:45:23
June 01 2008 23:27 GMT
#1
If a rocket is rising vertically at 880 ft/sec when it is 4,000 ft up, how fast is the camera - to - rocket distance changing at that instant?

how do i start this off? i drew this, but im not sure if its correctly drawn:

[image loading]


i just wanted to start it off, i mean it would equal to 4,000 right?

----

Suppose a liquid is to be cleared of sediments by pouring it through a cone - shaped filter. Assume the height of the cone is 16 in. and the radius at the base of the cone is 4 in. If the liquid is flowing out of the cone at a constant rate of 2 cubic inches per minute, how fast is the depth of the liquid decreasing when the level is 8 in. deep?

just from reading that, i think it would be best to get the cone formula? cone: A = (PIr^2h) / 3 after this, what would be the next step? thanks guys.

paper
Profile Blog Joined September 2004
13196 Posts
June 01 2008 23:35 GMT
#2
don't you need to know how far you are from the base of the launching rocket?
Hates Fun🤔
Raithed
Profile Blog Joined May 2007
China7078 Posts
June 01 2008 23:45 GMT
#3
updated, sorry paper.
micronesia
Profile Blog Joined July 2006
United States24651 Posts
June 01 2008 23:46 GMT
#4
I don't mind people occasionally getting help, but why are you using tl as your primary source for learning everything that is math? It is getting to be too much :-/
ModeratorThere are animal crackers for people and there are people crackers for animals.
Raithed
Profile Blog Joined May 2007
China7078 Posts
June 01 2008 23:51 GMT
#5
because you guys help me more than the internet does first time, its my primary source and basically my #1 place to go first. sometimes the sites i go to via google gives example that arent related or hard to understand.
jtan
Profile Blog Joined April 2003
Sweden5891 Posts
June 01 2008 23:53 GMT
#6
If he wants help and people wants helping it's not a problem imo

+ it's his blog
Enter a Uh
paper
Profile Blog Joined September 2004
13196 Posts
Last Edited: 2008-06-01 23:54:59
June 01 2008 23:54 GMT
#7
well, don't you have a book that teaches you this shit? o__O
when i took calc, everything was in the book lol

for #1, i'm guessing the answer is 700ft/s?
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fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
June 01 2008 23:54 GMT
#8
I'd help him except I spent all my free time watching the TSL and don't have anymore....LOL.
Do you really want chat rooms?
micronesia
Profile Blog Joined July 2006
United States24651 Posts
Last Edited: 2008-06-01 23:58:56
June 01 2008 23:55 GMT
#9
The distance between the camera and the rocket:

r = sqrt(y^2+3000^2)

differentiate:

dr/dt = .5 (y^2+3000^2)^(-.5) * 2y dy/dt

Plug in 880 for dy/dt and 4000 for y? I haven't plugged it in yet.

Edit: would give you 704 ft/s
ModeratorThere are animal crackers for people and there are people crackers for animals.
ydg
Profile Blog Joined March 2008
United States690 Posts
June 01 2008 23:59 GMT
#10
i love related rates. they're so fun. you just need to find a relationship and then take the derivative and plug in a number.
"If a rocket is rising vertically at 880 ft/sec when it is 4,000 ft up, how fast is the camera - to - rocket distance changing at that instant?"
so using your triangle, d^2=h^2+90,000 (pythagorean theorem)
you want to find dd/dt when h=4,000, and you're given dh/dt to be 880.
derive and plug in h=4,000, and then solve for dd/dt

"
Suppose a liquid is to be cleared of sediments by pouring it through a cone - shaped filter. Assume the height of the cone is 16 in. and the radius at the base of the cone is 4 in. If the liquid is flowing out of the cone at a constant rate of 2 cubic inches per minute, how fast is the depth of the liquid decreasing when the level is 8 in. deep?
"
again, use the formula for the volume of the cone. derive it. plug in what you know and find dh/dt, where h is the height of the cone. you're given dv/dt and you want to find dh/dt when h=8
also note, you can find the radius when h=8 by using similar triangles
The only courage that matters is the kind that gets you from one moment to the next.
jtan
Profile Blog Joined April 2003
Sweden5891 Posts
Last Edited: 2008-06-02 00:02:14
June 02 2008 00:01 GMT
#11
I got 2*4*88=704 on paper not sure it's right though, I did it pretty fast

edit: yup, seems right. Did it just like micronesia
Enter a Uh
Purind
Profile Blog Joined April 2004
Canada3562 Posts
June 02 2008 00:08 GMT
#12
Use pythagorean theorem
x^2 + y^2 = d^2

Differentiate implicitly wrt t to get something like
x dx/dt + y dy/dt = d dd/dt
dy/dt = given, d = can figure out easily, dx/dt = 0, dd/dt = answer
Trucy Wright is hot
micronesia
Profile Blog Joined July 2006
United States24651 Posts
June 02 2008 00:10 GMT
#13
On June 02 2008 09:08 Purind wrote:
Use pythagorean theorem
x^2 + y^2 = d^2

Differentiate implicitly wrt t to get something like
x dx/dt + y dy/dt = d dd/dt
dy/dt = given, d = can figure out easily, dx/dt = 0, dd/dt = answer

your alphabetical collision is XD
ModeratorThere are animal crackers for people and there are people crackers for animals.
Purind
Profile Blog Joined April 2004
Canada3562 Posts
June 02 2008 00:12 GMT
#14
Use the volume of a cone formula.
V = something.
it will be in terms of r and h. You can find a relation between r and h. It'll be like... h = 4r or something like that (draw one view of the cone so that it looks like a triangle, you should be able to figure out what the equation is from that). Plug that relationship into the volume equation so that the only unknown is h.

Differentiate wrt t to get
dV/dt = something dh/dt
dh/dt should be your answer
Trucy Wright is hot
Purind
Profile Blog Joined April 2004
Canada3562 Posts
June 02 2008 00:15 GMT
#15
On June 02 2008 09:10 micronesia wrote:
Show nested quote +
On June 02 2008 09:08 Purind wrote:
Use pythagorean theorem
x^2 + y^2 = d^2

Differentiate implicitly wrt t to get something like
x dx/dt + y dy/dt = d dd/dt
dy/dt = given, d = can figure out easily, dx/dt = 0, dd/dt = answer

your alphabetical collision is XD


Shut up, I don't read or think!!
Trucy Wright is hot
Raithed
Profile Blog Joined May 2007
China7078 Posts
June 02 2008 00:30 GMT
#16
On June 02 2008 08:55 micronesia wrote:
The distance between the camera and the rocket:

r = sqrt(y^2+3000^2)

differentiate:

dr/dt = .5 (y^2+3000^2)^(-.5) * 2y dy/dt

Plug in 880 for dy/dt and 4000 for y? I haven't plugged it in yet.

Edit: would give you 704 ft/s

i get the dr/dt part, but getting the r = sqrt(y^2+3000^2) part i got lost, why y^2 which i dont know, i know its the pythagorean formula, but that confused me, to get "r" dont i need 2 numbers? i guess its calculus and you dont huh?

i have a question guys when solving these kinds of stuff, im still looking at it, which one am i solving for; meaning, which side? its asking how fast the camera is, so we're solving for the hypotenuse right? thanks again. and ydg can you explain the second one like write it out?

so..

A = (PIr^2h) / 3
derive this? PI = 0 r^2 would be 2r and h would be dy/dx? the 3 going on top would be 3^-1, am i on the right track?
micronesia
Profile Blog Joined July 2006
United States24651 Posts
Last Edited: 2008-06-02 00:38:29
June 02 2008 00:37 GMT
#17
On June 02 2008 09:30 Raithed wrote:
Show nested quote +
On June 02 2008 08:55 micronesia wrote:
The distance between the camera and the rocket:

r = sqrt(y^2+3000^2)

differentiate:

dr/dt = .5 (y^2+3000^2)^(-.5) * 2y dy/dt

Plug in 880 for dy/dt and 4000 for y? I haven't plugged it in yet.

Edit: would give you 704 ft/s

i get the dr/dt part, but getting the r = sqrt(y^2+3000^2) part i got lost, why y^2 which i dont know, i know its the pythagorean formula, but that confused me, to get "r" dont i need 2 numbers? i guess its calculus and you dont huh?

I'm not sure if I understand your question. I kept 3000 as a number because it is always 3000. I kept y as a variable because, even though we know the value at some point in time, we need to keep it as a variable in order to determine the overall relationship between y and r, and dy and dr. Once we have that relationship, then we can plug in the actual value of 4000.
ModeratorThere are animal crackers for people and there are people crackers for animals.
ydg
Profile Blog Joined March 2008
United States690 Posts
June 02 2008 00:38 GMT
#18
for the first one, r is the hypotenuse and y is the height and 3000 is the given distance between the launch and the rocket.

okay second one..
[image loading]

[image loading]

[image loading]

derive, plug in, solve
The only courage that matters is the kind that gets you from one moment to the next.
Raithed
Profile Blog Joined May 2007
China7078 Posts
June 02 2008 00:44 GMT
#19
ydg, does the 16/4 always have to be h/r? and which do i derive for? the V = 1/3PI(h/4)^2 or h = PI(h^3/48)? im guessing the latter?
ydg
Profile Blog Joined March 2008
United States690 Posts
June 02 2008 00:46 GMT
#20
similar triangles, so the height/base of one triangle is equal to the height/base of another
and uh, lol, it's just two equations that are equal to each other, v=that, which =the last thing. derive the v=pi h^3/48
The only courage that matters is the kind that gets you from one moment to the next.
Raithed
Profile Blog Joined May 2007
China7078 Posts
June 02 2008 00:54 GMT
#21
okay not to sound even more stupid;

V = PI * ( h^3 / 48 )

the next step is product rule or quotient in the parenthesis?
ydg
Profile Blog Joined March 2008
United States690 Posts
June 02 2008 01:11 GMT
#22
neither, since pi and 48 are constants and not variables
The only courage that matters is the kind that gets you from one moment to the next.
paper
Profile Blog Joined September 2004
13196 Posts
June 02 2008 02:16 GMT
#23
raithed what year are you?
Hates Fun🤔
jtan
Profile Blog Joined April 2003
Sweden5891 Posts
June 02 2008 03:46 GMT
#24
You can't just "derive" a formula generally

you derive by a variable

like if you have your V = PI * ( h^3 / 48 ) you could calculate dV/dt which would yield a formula for how much the vulume changes over time, in this case V would be a constant function.

If you are looking for dV/dh == how much the volume changes when h changes you can in this case just use the standard rule and get (PI/48) *(3*h^2). Pi and 48 are constant and doesn't affect the differentiation.
Enter a Uh
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