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EsX_Raptor
United States2801 Posts
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fight_or_flight
United States3988 Posts
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drift0ut
United Kingdom691 Posts
On May 11 2008 09:54 fight_or_flight wrote: Its got to be zero....the largest term, the first one, goes to zero. The rest are smaller. that's not sufficient, the sum of 1/n, n>m has the leading term tending to zero but the sum does not for any m. but yeah i'd guess zero also... | ||
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Pistasj
Norway272 Posts
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B1nary
Canada1267 Posts
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nemY
United States3119 Posts
(nsfw) + Show Spoiler + ![[image loading]](http://poderresponsabilidad.files.wordpress.com/2007/07/megan-fox-7.jpg) | ||
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EtherealDeath
United States8366 Posts
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fight_or_flight
United States3988 Posts
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fight_or_flight
United States3988 Posts
On May 11 2008 09:59 drift0ut wrote: that's not sufficient, the sum of 1/n, n>m has the leading term tending to zero but the sum does not for any m. but yeah i'd guess zero also... You are right...what was I thinking.. | ||
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._.
1133 Posts
On May 11 2008 10:10 fight_or_flight wrote: http://www.texify.com HOLY SHIT! Now I don't have to send mspaint equations to my teacher for my math project! THX. | ||
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EtherealDeath
United States8366 Posts
On May 11 2008 10:14 ._. wrote: HOLY SHIT! Now I don't have to send mspaint equations to my teacher for my math project! THX. Lol and then I forget how to type Tex cause i used it only once a year ago for finals. Anyways, harmonicize the problem :-P | ||
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CDRdude
United States5625 Posts
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imDerek
United States1944 Posts
so the answer is 2(rt(2)-1) edit: write as lim (1/n)[1/rt(1+ 1/n) + 1/rt(1 + 2/n) + ... + 1/rt(1 + n/n)] then its pretty obvious it's just the definition of the integral | ||
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Zortch
Canada635 Posts
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thoraxe
United States1449 Posts
Holy crap!! That looks like Jessica Chobot from ign.com Is it her? | ||
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fight_or_flight
United States3988 Posts
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EsX_Raptor
United States2801 Posts
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junny
United States174 Posts
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micronesia
United States24709 Posts
BTW putting the word 'math' or something similar in the title would have been preferable. | ||
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nemY
United States3119 Posts
On May 11 2008 10:44 thoraxe wrote: Holy crap!! That looks like Jessica Chobot from ign.com Is it her? Like Ghoflz said, it's Megan Fox. That being said, I had never heard of Jessica Chobot, but after a quick google of her I was able to find some sexy pics of her. + Show Spoiler + ![[image loading]](http://img.qj.net/uploads/articles_module/72560/jesspsp_qjpreviewth.jpg) OMGZ! SHE HAS MADE THE PSP USEFUL! sorry to derail this blog  | ||
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