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Blogs > EsX_Raptor
Post a Reply
EsX_Raptor
Profile Blog Joined February 2008
United States2802 Posts
May 11 2008 00:52 GMT
#1
[image loading]


*
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
May 11 2008 00:54 GMT
#2
Its got to be zero....the largest term, the first one, goes to zero. The rest are smaller.
Do you really want chat rooms?
drift0ut
Profile Blog Joined June 2004
United Kingdom691 Posts
May 11 2008 00:59 GMT
#3
On May 11 2008 09:54 fight_or_flight wrote:
Its got to be zero....the largest term, the first one, goes to zero. The rest are smaller.

that's not sufficient, the sum of 1/n, n>m has the leading term tending to zero but the sum does not for any m. but yeah i'd guess zero also...
Pistasj
Profile Blog Joined November 2005
Norway272 Posts
May 11 2008 00:59 GMT
#4
Lim Yoh Hwan?
B1nary
Profile Blog Joined January 2008
Canada1267 Posts
Last Edited: 2008-05-11 01:01:28
May 11 2008 01:00 GMT
#5
It's definitely not 0. The smallest term is the last one. There are n terms. Multiply the last term by n to get the lower bound.
nemY
Profile Blog Joined July 2006
United States3119 Posts
May 11 2008 01:05 GMT
#6
I'LL SAVE YOU!

(nsfw)
+ Show Spoiler +
[image loading]
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
May 11 2008 01:07 GMT
#7
someone tell me how to type LaTeX in TL and i will dump in a readable solution >.>
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
Last Edited: 2008-05-11 01:11:04
May 11 2008 01:10 GMT
#8
http://www.texify.com
Do you really want chat rooms?
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
May 11 2008 01:11 GMT
#9
On May 11 2008 09:59 drift0ut wrote:
Show nested quote +
On May 11 2008 09:54 fight_or_flight wrote:
Its got to be zero....the largest term, the first one, goes to zero. The rest are smaller.

that's not sufficient, the sum of 1/n, n>m has the leading term tending to zero but the sum does not for any m. but yeah i'd guess zero also...

You are right...what was I thinking..
Do you really want chat rooms?
._.
Profile Blog Joined November 2007
1133 Posts
May 11 2008 01:14 GMT
#10
On May 11 2008 10:10 fight_or_flight wrote:
http://www.texify.com

HOLY SHIT!

Now I don't have to send mspaint equations to my teacher for my math project! THX.
:D
EtherealDeath
Profile Blog Joined July 2007
United States8366 Posts
May 11 2008 01:15 GMT
#11
On May 11 2008 10:14 ._. wrote:
Show nested quote +
On May 11 2008 10:10 fight_or_flight wrote:
http://www.texify.com

HOLY SHIT!

Now I don't have to send mspaint equations to my teacher for my math project! THX.



Lol and then I forget how to type Tex cause i used it only once a year ago for finals. Anyways, harmonicize the problem :-P
CDRdude
Profile Blog Joined May 2007
United States5625 Posts
May 11 2008 01:30 GMT
#12
It looks to me like you can say that each term in that series is smaller than each term in the harmonic series, which diverges. So, you know it's smaller than a diverging series, which upon further reflection doesn't really help at all. Damn.
Force staff is the best item in the game.
imDerek
Profile Blog Joined August 2007
United States1944 Posts
Last Edited: 2008-05-11 01:40:22
May 11 2008 01:32 GMT
#13
its a riemann sum of integral of x^(-1/2) from 1 to 2

so the answer is 2(rt(2)-1)

edit: write as lim (1/n)[1/rt(1+ 1/n) + 1/rt(1 + 2/n) + ... + 1/rt(1 + n/n)] then its pretty obvious it's just the definition of the integral
Least favorite progamers: Leta, Zero, Mind, Shine, free, really <-- newly added
Zortch
Profile Blog Joined January 2008
Canada635 Posts
May 11 2008 01:43 GMT
#14
very nice
Respect is everything. ~ARchon
thoraxe
Profile Blog Joined March 2007
United States1449 Posts
May 11 2008 01:44 GMT
#15
On May 11 2008 10:05 nemY wrote:
I'LL SAVE YOU!

(nsfw)
+ Show Spoiler +
[image loading]

Holy crap!! That looks like Jessica Chobot from ign.com
Is it her?
Obama singing "Kick Ass" Song: http://www.youtube.com/watch?v=yghFBt-fXmw&feature=player_embedde
fight_or_flight
Profile Blog Joined June 2007
United States3988 Posts
May 11 2008 01:51 GMT
#16
right, 2(rt(2)-1)/n which is 0
Do you really want chat rooms?
EsX_Raptor
Profile Blog Joined February 2008
United States2802 Posts
May 11 2008 02:15 GMT
#17
imDerek you pwn dude!!! ^^
junny
Profile Joined October 2007
United States174 Posts
May 11 2008 02:21 GMT
#18
im willing to bet thats megan fox!
micronesia
Profile Blog Joined July 2006
United States24768 Posts
May 11 2008 04:11 GMT
#19
I like math but this isn't really my type of problem :p

BTW putting the word 'math' or something similar in the title would have been preferable.
ModeratorThere are animal crackers for people and there are people crackers for animals.
nemY
Profile Blog Joined July 2006
United States3119 Posts
May 11 2008 08:50 GMT
#20
On May 11 2008 10:44 thoraxe wrote:
Show nested quote +
On May 11 2008 10:05 nemY wrote:
I'LL SAVE YOU!

(nsfw)
+ Show Spoiler +
[image loading]

Holy crap!! That looks like Jessica Chobot from ign.com
Is it her?


Like Ghoflz said, it's Megan Fox. That being said, I had never heard of Jessica Chobot, but after a quick google of her I was able to find some sexy pics of her.

+ Show Spoiler +
[image loading]

OMGZ! SHE HAS MADE THE PSP USEFUL!


sorry to derail this blog
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