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decafchicken
United States20068 Posts
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CDRdude
United States5625 Posts
+ Show Spoiler + --The buoyant force due to water is 4 (the difference between 30 N in air, and the 26 in water) --The buoyant force is the mass of displaced fluid. F(b) = mass_fluid = density * volume Because of units, the water density is 1000 (units should be kg per cubic meter) F(b) = 1000 * V(object) = 4 V(object) = 4/1000 = .004 (this seems legit, because it's in cubic meters) You also know the buoyant force due to the mystery fluid: 6 F(b2) = x * V(object) = 6 where x is your density, and you calculated V in the previous step. x = 6 / .004 = 1500 (remember, the units are in kg per cubic meter, so this seems to make sense) As a check, you can look and see that the fluid is 50% more dense than water, and yes, the buoyant force is 50% stronger than in water. I hope this helps. | ||
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decafchicken
United States20068 Posts
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CDRdude
United States5625 Posts
F = F(gravity) - F(buoyancy) I was just looking at the buoyant force, which I'm quite sure is just the mass of displaced fluid. | ||
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decafchicken
United States20068 Posts
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SpiritoftheTunA
United States20903 Posts
cause the scale shows the normal force, and the net force will always be zero | ||
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CDRdude
United States5625 Posts
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