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thought this was gonna be about something else
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Why does it feel like this is a blog about penises.
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^ agreeing with above replies.
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Croatia9558 Posts
On July 14 2011 02:09 Serejai wrote:
Why does it feel like this is a blog about penises.
Because that's the TL's resident penis guy.
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I haven't had physics, so here are my guesses.
1: 1/4 F?????
2: No idea what STP is
3: Doesn't that depend on air composition/temp and the amount of force? Or is that taken care of by STP?
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On July 14 2011 02:23 jorge_the_awesome wrote:
I haven't had physics, so here are my guesses.
1: 1/4 F?????
2: No idea what STP is
3: Doesn't that depend on air composition/temp and the amount of force? Or is that taken care of by STP?
STP is "standard temperature and pressure". Isn't this just basic high school physics homework?
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On July 14 2011 02:15 2Pacalypse- wrote:Show nested quote +On July 14 2011 02:09 Serejai wrote:
Why does it feel like this is a blog about penises. Because that's the TL's resident penis guy.
Funny, My quote is also from this thread ^^
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Not homework, just erecting a series of math/compsci blogs that get harder over time. That is, if you guys don't pull out.
But try to solve them. That will improve your shots at getting hotter jobs that don't blow so bad.
Edit: Posted the answer to the first problem.
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omg i tried to do it and got he should have to push harder which i assume is wrong...
im just going to write thick and long.
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ˇwhers the force come from, please explain. pressures must be equal? Why not forces? How does it come.
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On July 14 2011 03:07 EsX_Raptor wrote:
Not homework, just erecting a series of math/compsci blogs that get harder over time. That is, if you guys don't pull out.
But try to solve them. That will improve your shots at getting hotter jobs that don't blow so bad.
Edit: Posted the answer to the first problem.
I see what you did there.
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Roffles
Pitcairn19291 Posts
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i almost choked on laughter at that subtle paragraph
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.......................
You have got to be joking, but amusing nonetheless.
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+ Show Spoiler [Answer] +The guy has more surface area with which to apply the same force. He wins.
What about long and thick?
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This is so sexual and hilarious. Keep it up.
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On July 14 2011 03:07 EsX_Raptor wrote:
Not homework, just erecting a series of math/compsci blogs that get harder over time. That is, if you guys don't pull out.
But try to solve them. That will improve your shots at getting hotter jobs that don't blow so bad.
Edit: Posted the answer to the first problem.
The reply made this thread amazing. lol thank you EsX_Rator, I learned something today. :D
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On July 14 2011 04:31 TheGiz wrote:+ Show Spoiler [Answer] +The guy has more surface area with which to apply the same force. He wins. What about long and thick?
+ Show Spoiler +actually, the guy has to apply more force, as evidenced by the answer OP posted lol
pressure = force per unit area, so to have equal amount of pressure applied, the guy has to apply four times the force the girl does...
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I think this is secretly an ethics question disguised as a math question.
Syringes, a little girl, penises, applying force...
I am going to answer: immoral.
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On July 14 2011 05:52 Z3kk wrote:+ Show Spoiler +actually, the guy has to apply more force, as evidenced by the answer OP posted lol
pressure = force per unit area, so to have equal amount of pressure applied, the guy has to apply four times the force the girl does...
+ Show Spoiler +Actually having a penis instantly makes everything you do 4 times more efficient so he only needs to be as strong as the girl.
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You got this all wrong. But I can see where your calculations began derailing; there are 3 main factors:
• The female shouldn’t be a ‘little girl’; this starts implying that even though she can create F (force) as great or greater than the male, she still seems weaker.
This is a matter of perception and reader- delusion. I suggest you edit the subject from ‘little girl’ to ‘lady’.
If you want a visual aid to get my point:
+ Show Spoiler +
• The second factor is that you’re trying to make this equation gravity-neutral, even though we are great fans of Affirmative Action and thus should help the so-called ‘weaker-sex’ by enabling her with the powers of gravity; reversing the image to this point:
+ Show Spoiler +
• To further balance the scales, we should give the lady more surface area to apply pressure to, while we give the guy some solid ground from where he can push the syringe. This would lead in the lady getting the new syringe ‘A’ and the guy syringe ‘B’ and apply pressure like this:
+ Show Spoiler +
Now we can truly look at the equation, now that reader-delusions are removed and we’ve taken Affirmative Action.
While the lady has a better grip on the syringes on the 3 main attachmentpoints (FA), allowing her to make most of her multitasking abilities (MA), the guy has a more focused linear pressurepoint (FB), enabling him to use the fullest of his one-track mindedness (OTM).
This gives us the following equation:
Assume both syringes can hold the same volume V, the uncompressible liquid between them is also V, and the radius of syringe B is equal to twice the radius of syringe A.
FB*1 OTM = FA*3MA
Now, knowing that using the MA on 3 different routes will definetely open up 1 unit of MA to think of STP (Standard Temperature and Pressure); creating the following disturbance in the equation:
FB*1 OTM > FA*3MA-1MA(STP); ending the equation with this:
+ Show Spoiler +
In conclusion, as the formula proves; the guy will win this using these variables and the lady will end up being overpowered, by his build-up pressure.
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Okay, even though this is obviously a joke thread, here are my answers.
1. Let's say that the radius of the girl's syringe is R, and the radius of the guy's syringe is 2R. The surface area of their respective syringes are then piR^2 and pi(2R)^2 or pi4R^2. If the force applied by the girl is Fa and the force applied by the guy is Fb, and the pressures applied by both must be equal, then you can set them equal to each other through Fa/(piR^2) = Fb/(pi4R^2) and get 4Fa = Fb.
2. Following the ideal gas law, PV=nRT, we can see that all the variables (volume, number of moles, temperature) excluding pressure are the same for both of them. Therefore, we can omit them and judging by the answer in question 1, we can conclude that the result will be the same; the guy must apply 4x the pressure to equalize it with air at standard temperature and pressure.
3. Now, because they are applying enough pressure to make sure that they both have the same volume, we can choose one of the sides and calculate, using Boyle's Law (P1V1 = P2V2). Pressure we have already determined to be Fa/(piR^2) for the girl, and the new volume will be V2. The original volume is V, and the original pressure we can assume to be 1 atmosphere. Therefore, we have (1)(V) = [Fa/(piR^2)][V2]. We are solving for V2, so we simplify to get V(piR^2)/Fa = V2.
To make that seem a bit easier to relate to , let's assign some values. Say the volume of the air is 1 liter (that's a big syringe), the radius of the "syringe" is 1/4 of a meter, and the force applied is 1 N. Then, we have (1 liter)(1 atmosphere)(pi/16 square meters)/1N = V2. This simplifies to (1 liter)(1 atm)(0.2 pascals^-1) = V2. Skipping some retarded conversions, we arrive at V2 ~= 0.000002 liters or 0.002 mL (which is a rather small syringe).
+ Show Spoiler +Yes, I know OP probably wanted to make penis jokes. The joke is on him; the last figure is the volume of his penis!
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On July 14 2011 06:03 Gnial wrote:
I think this is secretly an ethics question disguised as a math question.
Syringes, a little girl, penises, applying force...
I am going to answer: immoral.
Lmao. I think you might be right!
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You best start believing in troll threads...
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EPT![[image loading]](http://i51.tinypic.com/10hqc6t.jpg)
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![[image loading]](http://i.imgur.com/w61lT.jpg)
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