EPT![[image loading]](http://img41.imageshack.us/img41/561/73229849.jpg)
![[image loading]](http://img42.imageshack.us/img42/8192/60009274.jpg)
![[image loading]](http://img42.imageshack.us/img42/9409/asdfasfa.jpg)
Math mistakes
| Blogs > blabber |
|
blabber
United States4448 Posts
| ||
|
nemY
United States3119 Posts
| ||
|
Kyuukyuu
Canada6263 Posts
the six one is still pretty awesome though | ||
|
il0seonpurpose
Korea (South)5638 Posts
| ||
|
naonao
United States847 Posts
| ||
|
29 fps
United States5724 Posts
| ||
n.DieJokes
United States3443 Posts
| ||
|
Avidkeystamper
United States8552 Posts
+ Show Spoiler + I'm a nitpick | ||
|
conCentrate9
United States438 Posts
| ||
|
AlwaysGG
Taiwan952 Posts
| ||
|
ninjafetus
United States231 Posts
Show why the vertex of f = ax^2 + bx + c must occur at x = -b / (2a) The idea was for them to remember that a vertex was a critical point, so they would take a derivative, set it equal to zero, and solve. Instead they wrote the quadratic formula x = (-b ± sqrt(b^2 - 4ac) ) / (2a) "expanded" as x = (-b + sqrt(b^2 - 4ac) - sqrt(b^2 - 4ac) ) / (2a) canceled the sqrt terms, and ended with x = - b / (2a). ..... .................. I almost gave them credit for such brilliant incompetence. | ||
|
evanthebouncy!
United States12796 Posts
| ||
|
Railz
United States1449 Posts
![[image loading]](http://www.midcoast.com/~mlc/ice/girls-evil.jpg) | ||
|
HeavOnEarth
United States7087 Posts
but noo. -pout- | ||
|
Divinek
Canada4045 Posts
| ||
MasterOfChaos
Germany2896 Posts
On May 18 2009 15:37 ninjafetus wrote: Instead they wrote the quadratic formula x = (-b ± sqrt(b^2 - 4ac) ) / (2a) "expanded" as x = (-b + sqrt(b^2 - 4ac) - sqrt(b^2 - 4ac) ) / (2a) canceled the sqrt terms, and ended with x = - b / (2a). I almost gave them credit for such brilliant incompetence. Why incompetence? It is a viable way to arrive at the solution if you recall that the vertex is in the middle of the arms. That is similar to how I arrived at that formula several years before learning what a derivative is. | ||
|
klizzer
517 Posts
![[image loading]](http://roberdo.com/wp-content/uploads/2006/02/maths-problem.jpg) Also, the expanding thing above isn't necessarily wrong, it just lacks one step of counting the average, as MoC said. | ||
|
ninjafetus
United States231 Posts
On May 18 2009 19:37 MasterOfChaos wrote: Why incompetence? It is a viable way to arrive at the solution if you recall that the vertex is in the middle of the arms. That is similar to how I arrived at that formula several years before learning what a derivative is. It's incompetence because A ± B = A + B - B = A doesn't make sense. You're implying that B =0, always. Yeah, there's other ways to get it (factor to vertex form), and, if we ignore the middle step, what they did will work in the specific case that the discriminant is zero, but other than that, it's just wrong. The reason I expected them to use the derivative is because 1) it was a calculus class, and 2) I had shown them the exact steps I was expecting before. If they did a legitimate factoring, I gave them full credit, of course. If they had averaged the two roots, I would have given them credit. That's not what they were thinking, I promise. | ||
|
Musoeun
United States4324 Posts
| ||
|
clazziquai
6685 Posts
They still do!  Thanks for sharing (again) ^_^ | ||
|
Nytefish
United Kingdom4282 Posts
On May 18 2009 21:56 klizzer wrote: The reason I always use pencil T_T | ||
|
HeavOnEarth
United States7087 Posts
it does look like an ink blot though; not scribbling. | ||
| ||
