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On January 08 2009 14:30 Peter[Deuce] wrote:
Ah I get the first, still wondering what I subtract to get the second.
Suppose:
55% of adults like coffee.
25% of adults like tea.
45% of adults like cola.
and
15% drink both coffee and tea
5% drink all beverages
25% drink both coffee and cola
5% drink only tea
ok so you have that right
First thing I like to do is put the a+b+c one in, the five percent, then you can throw in the coffee and tea's 10 percent to get 15, and then the coffee and cola's 20 to get 25. then you put 5% in tea, which you dont even need to be supplied with, and fill in the rest based on the 'suppose' just by subtracting what you have from what you need. and then subtract everything in there from 100 to get the 20.
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Divinek's has P(Coffee and cola)=20% when it's 25%
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On January 08 2009 14:30 Divinek wrote:Show nested quote +On January 08 2009 14:27 Resonance wrote:
No answer? Man that's a bad teaching method how are you supposed to know if what you are doing is right?
Anyway here is my logic for both of your questions:
For the first one it's pretty simple, just find the only Cola drinkers %.
For the second, what I did was get all the percentages (after broken down, 15+25+5+15+5+10+0=75)
Then just go 100% - 75 = 25...rofl yeah ok so I made that mistake there I'm really fucking tired haha
So answers are 15% and 25% When you get to 3rd/4th year math courses atleast none of the books have answers, at all. It's suprising how many people got this wrong. Pictures really do help, always, always, always.
Lol I'm suprised it wrong too, I did this stuff last year and I remember it was so easy, but I have forgotten so much.
Ah well I'm not in math right now so I guess I have an excuse.
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On January 08 2009 14:33 Peter[Deuce] wrote:
Divinek's has P(Coffee and cola)=20% when it's 25%
no see his P(coffee and cola) is split among the 5 all3 + the 20 coffee/cola/NOTtea which checks out
P(coffee, cola, not tea) != P (coffee, cola)
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I don't know. I figured that P(Cola and Tea)=0% because 5%(tea only)+15%(Coffee and tea)+5%(All)=25% already.
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On January 08 2009 14:34 SpiritoftheTunA wrote:Show nested quote +On January 08 2009 14:33 Peter[Deuce] wrote:
Divinek's has P(Coffee and cola)=20% when it's 25% no see his P(coffee and cola) is split among the 5 all3 + the 20 coffee/cola/NOTtea which checks out P(coffee, cola, not tea) != P (coffee, cola)
Ah!
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On January 08 2009 14:35 Peter[Deuce] wrote:
I don't know. I figured that P(Cola and Tea)=0% because 5%(tea only)+15%(Coffee and tea)+5%(All)=25% already.
yeah i did something similar the first time, not realizing the mistake in thinking i just pointed out
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Thanks guys. First time in statistics where I was confused =O
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a) 15
b) 20
2nd year math major approved 
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On January 08 2009 14:40 zeks wrote:a) 15 b) 20 2nd year math major approved
but did you like my drawing
And no worries for the help, if you need anymore in the future feel free to pm me if you like.
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On January 08 2009 14:13 Fontong wrote:^^Avidkeystamper has a clever solution, I've actually never seen this type of problem in my life despite having just taken multivariable calc(lol...). I really wouldn't know how to do it without thinking a lot. Show nested quote +On January 08 2009 14:06 YianKutKu wrote:
I remember doing these problems in my pre-calc class. Forgot now.
edit: use a tree diagram You are a hunters player, yes? I think I've seen you around bnet.
Yup. Haven't been playing a lot of 3v3's though lately.
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EPT
