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Physics Help! Two questions - Page 2

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viceroy Romania227 Posts September 09 2008 03:20 GMT #21 So is it 60 ? or not ?

viceroy Romania227 Posts September 09 2008 03:34 GMT #22 ok, if I look of the print screen you gave us then the ratio is actually 100. and that would make the uncertainty 6 not 60... I think your friend is messing with you bro

clazziquai 6685 Posts September 09 2008 03:36 GMT #23 Yes, it's 6 thanks a lot for the help. Fuck my friedn then LOL

viceroy Romania227 Posts September 09 2008 03:37 GMT #24 and 100 would be incorrect since is 3 sig figs so you would have to write 1.0 x 10^2 for two sig figs only

viceroy Romania227 Posts September 09 2008 03:40 GMT #25 glad I could help clazziquai To calculate uncertainty you calculate first the percent errors as: (error/value) * 100 so if you have 3 numbers you would have to add 3 of these percent errors. then you find the final value for example in your case the percent error was 6.1% and the final value was 100 so would be 100(the value) * 6 (the percent error) / 100 => the uncertainty

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