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Math Problem T_T

Blogs > decafchicken
Post a Reply
decafchicken
Profile Blog Joined January 2005
United States20159 Posts
October 11 2007 00:41 GMT
#1
Yea so i have this math(pre-calc) problem on my test that's been bothering me to no end that i got wrong and literally nobody in the class that i know has the answer. The answer is somewhat simple (1-3 sentences tops), but i cant find it anywhere in my textbooks. ITW and Margarita tried to help me but i dont think we ever got it? Google has failed me, merely telling me that the statement is true, not how to prove it. Anyways here it is:

Prove that the product of two odd functions is an even function.

**
how reasonable is it to eat off wood instead of your tummy?
BuGzlToOnl
Profile Blog Joined November 2006
United States5918 Posts
October 11 2007 00:49 GMT
#2
hmm, I'm doing this right now, I should definetly know this. T__T
If you want to make God laugh, tell Him your plans.
Kau *
Profile Joined March 2007
Canada3500 Posts
Last Edited: 2007-10-11 00:54:59
October 11 2007 00:53 GMT
#3
Would it be right to say that since an even function satisfies f(x) = f(-x) and an odd function satisfies -f(x) = f(-x) that two odd functions f(x) and g(x) multiplied together would satisfy (two odd functions)(-f(x))(-g(x)) = f(-x)g(-x) = f(x)g(x) (an even function).
Moderator
azndsh
Profile Blog Joined August 2006
United States4447 Posts
October 11 2007 00:54 GMT
#4
definition of odd function f(x) = -f(-x)
definition of even function: f(x) = f(-x)

Let your two odd functions be f(x) and g(x). From the definition, we know that f(x) = -f(-x) and g(x) = -g(-x). Then multiply and tada! f(x)g(x) = f(-x)g(-x), so the product is obviously even by definition.
azndsh
Profile Blog Joined August 2006
United States4447 Posts
October 11 2007 00:55 GMT
#5
>_> too slow
Kau *
Profile Joined March 2007
Canada3500 Posts
October 11 2007 00:59 GMT
#6
Only by one minute, if you count my edits you were first ^^
Moderator
BuGzlToOnl
Profile Blog Joined November 2006
United States5918 Posts
October 11 2007 01:08 GMT
#7
That sounds about right!

+ Show Spoiler +
T________________T
If you want to make God laugh, tell Him your plans.
decafchicken
Profile Blog Joined January 2005
United States20159 Posts
October 11 2007 01:13 GMT
#8
<3 kau + azndash

kau are you holykau from scgd?
how reasonable is it to eat off wood instead of your tummy?
Jonoman92
Profile Blog Joined September 2006
United States9109 Posts
October 11 2007 01:50 GMT
#9
Could is be as simple as the concept that any 2 negatives multiplied together will produce a positive answer? Just a guess.... I'm in pre-calc but we don't do proofs we only do those in geometry.
Kau *
Profile Joined March 2007
Canada3500 Posts
Last Edited: 2007-10-11 06:42:36
October 11 2007 02:07 GMT
#10
On October 11 2007 10:13 decafchicken wrote:
kau are you holykau from scgd?


Yessir I am
Moderator
Dark.Carnival
Profile Blog Joined November 2006
United States5095 Posts
October 11 2007 03:01 GMT
#11
i never finished pre-calc, i got mono for the entire second semester of school and by the time i was better enough to start trying to pass my classes(at home) my teacher decided not to help so i had to drop the class -.-
@QxGDarkCell ._.
Aphelion
Profile Blog Joined December 2005
United States2720 Posts
October 11 2007 03:35 GMT
#12
On October 11 2007 10:50 Jonoman92 wrote:
Could is be as simple as the concept that any 2 negatives multiplied together will produce a positive answer? Just a guess.... I'm in pre-calc but we don't do proofs we only do those in geometry.


Exactly it.

let f(x), g(x) = odd functions

so f(-x) = -f(x), g(-x) = -g(x)

g(-x)f(-x) = (-g(x))(-f(x)) = g(x)f(x)

so g(x)f(x) = g(-x)f(-x)

By definition, g(x)f(x) is an even function
But Garimto was always more than just a Protoss...
oneofthem
Profile Blog Joined November 2005
Cayman Islands24199 Posts
October 11 2007 03:43 GMT
#13
was in week 3 hw for my real analysis thing. pah.
We have fed the heart on fantasies, the heart's grown brutal from the fare, more substance in our enmities than in our love
azndsh
Profile Blog Joined August 2006
United States4447 Posts
October 11 2007 04:26 GMT
#14
On October 11 2007 12:43 oneofthem wrote:
was in week 3 hw for my real analysis thing. pah.


wtf ...

week 3 we were on topology

man i hated that class
YoUr_KiLLeR
Profile Blog Joined September 2004
United States3420 Posts
October 11 2007 05:33 GMT
#15
i think you could also say that odd functions have an odd degree and even functions have an even degree, so the product of two odd functions will have a degree of (degree of 1st function + degree of 2nd function), and the sum of 2 odd numbers is even, so the product of the two odd functions gets you a function with an even number degree.

of course you'd have to be a lot more formal than that, i just didnt want to type everything out but i think you get the idea.
what the fuck do you have to say for yourself now you protoss jackass can you retaliate in any way
azndsh
Profile Blog Joined August 2006
United States4447 Posts
Last Edited: 2007-10-11 05:59:44
October 11 2007 05:58 GMT
#16
On October 11 2007 14:33 YoUr_KiLLeR wrote:
i think you could also say that odd functions have an odd degree and even functions have an even degree, so the product of two odd functions will have a degree of (degree of 1st function + degree of 2nd function), and the sum of 2 odd numbers is even, so the product of the two odd functions gets you a function with an even number degree.

of course you'd have to be a lot more formal than that, i just didnt want to type everything out but i think you get the idea.


that's assuming you have a polynomial function, which isn't necessarily the case -- i.e. sin(x), cos(x) are odd, even respectively (although the terms odd/even function did come from the fact that polynomial functions of odd/even degrees demonstrated those properties)
IntoTheWow
Profile Blog Joined May 2004
is awesome32278 Posts
October 11 2007 06:02 GMT
#17
Margarita solved it in irc -_- but you went away.
Moderator<:3-/-<
YoUr_KiLLeR
Profile Blog Joined September 2004
United States3420 Posts
October 12 2007 00:56 GMT
#18
On October 11 2007 14:58 azndsh wrote:
Show nested quote +
On October 11 2007 14:33 YoUr_KiLLeR wrote:
i think you could also say that odd functions have an odd degree and even functions have an even degree, so the product of two odd functions will have a degree of (degree of 1st function + degree of 2nd function), and the sum of 2 odd numbers is even, so the product of the two odd functions gets you a function with an even number degree.

of course you'd have to be a lot more formal than that, i just didnt want to type everything out but i think you get the idea.


that's assuming you have a polynomial function, which isn't necessarily the case -- i.e. sin(x), cos(x) are odd, even respectively (although the terms odd/even function did come from the fact that polynomial functions of odd/even degrees demonstrated those properties)

oh yea that completely went over my head.
what the fuck do you have to say for yourself now you protoss jackass can you retaliate in any way
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