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Numy
South Africa35471 Posts
On October 10 2014 21:54 TheYango wrote: 2*5*4/2 = 20 3*6*7/2 = 63 5*8*2/4 = 20 4*8*9/4 = 72? I thought possibly that but where on earth does the /2 and /4 come from and how do we know the last one is /4 instead of /2. Arg I hate this kind of pattern shit, don't really understand the purpose of it. edit: Actually now that i look at it I think it's /2 as the last one. | ||
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mordek
United States12705 Posts
@numy kinda why I thought it may be something stupid like 63 (20,63,20, 63 etc.) and that was all there was too the pattern. | ||
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jcarlsoniv
United States27922 Posts
On October 10 2014 22:01 Numy wrote: I thought possibly that but where on earth does the /2 and /4 come from and how do we know the last one is /4 instead of /2. Arg I hate this kind of pattern shit, don't really understand the purpose of it. Well, you derive the relationship from the first one, confirm it with the second one, use that thought process for the third to get the /4, and then apply it to the 4th for the answer. | ||
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Numy
South Africa35471 Posts
On October 10 2014 22:03 jcarlsoniv wrote: Well, you derive the relationship from the first one, confirm it with the second one, use that thought process for the third to get the /4, and then apply it to the 4th for the answer. I get what you saying but the problem is we don't know the logic for the /2 so not really deriving it for the 3rd one. Just kind of throwing a number out there and making it work. Actually looking at it again I think it's /2 because you have 4/2 then 6/3 so with the 3rd one you got 8/2 for /4 and the last one would then be 8/4 for /2. Every other division gives you not a whole number that's why I discarded it. So A is 4*8*9/2 = 144. Ok that seems large. Whatever screw this. | ||
TheYango
United States47024 Posts
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jcarlsoniv
United States27922 Posts
edit - inb4 the answer is 36 | ||
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Dandel Ion
Austria17960 Posts
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Tooplark
United States3977 Posts
http://www.futilitycloset.com/2014/04/30/nobs-number-puzzle/ | ||
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impirion
124 Posts
Also, that's really cool, wonder how long it took to come up with that series if it wasn't done by computer. | ||
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jcarlsoniv
United States27922 Posts
+ Show Spoiler + ![[image loading]](http://imgs.xkcd.com/comics/the_sake_of_argument.png) | ||
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Tooplark
United States3977 Posts
On October 10 2014 21:07 justiceknight wrote: ![[image loading]](http://i.imgur.com/miOFPkx.jpg) some1 solve this problem for me Here's the best I can come up with: Sides are A B C. Product of A with gcd(B,C)^2, then B with gcd(A,C)^2, and so on rotating around. This rule works for all 3, but I feel like it shouldn't be the solution. This gives: 5 * gcd(2,4)^2 = 5*2^2 = 20 7 * gcd(6,3)^2 = 7*3^2 = 63 5 * gcd(8,2)^2 = 5*2^2 = 20 8 * gcd(4,9)^2 = 8*1^2 = 8 or if we use a different rule and only take the gcd of the sides with a common factor, we get 144. Either way the answer seems like it should be 144 or 36. | ||
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GhandiEAGLE
United States20754 Posts
American education And other funny things~ | ||
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jcarlsoniv
United States27922 Posts
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Sufficiency
Canada23833 Posts
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Tooplark
United States3977 Posts
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Sufficiency
Canada23833 Posts
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Alaric
France45622 Posts
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Tooplark
United States3977 Posts
On October 10 2014 23:33 Alaric wrote: Maybe the point is that there are a bunch of possible solutions and the goal is to see you apply reasoning to find one, doesn't matter which, as long as you explain said reasoning? NOT A SATISFYING ANSWER ALARIC | ||
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Numy
South Africa35471 Posts
On October 10 2014 23:33 Alaric wrote: Maybe the point is that there are a bunch of possible solutions and the goal is to see you apply reasoning to find one, doesn't matter which, as long as you explain said reasoning? This isn't a hippy question. It's just a dumb maths one. | ||
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red_
United States8474 Posts
On October 10 2014 23:24 Sufficiency wrote: Or you can take the biggest prime factor of each corner and multiply them. Then the answer is 12. That's what I thought before I read some of the other ideas, now I'm not sure which I think it is anymore. | ||
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