This is basically the upper side of this.
x = 6
y = 12
L1 = 12"
L2 = 10"
To find theta1, law of cosine again right? Then +90 to it? How about theta2?
Blogs > Raithed |
Raithed
China7077 Posts
This is basically the upper side of this. x = 6 y = 12 L1 = 12" L2 = 10" To find theta1, law of cosine again right? Then +90 to it? How about theta2? | ||
Saracen
United States5139 Posts
where are your x and y | ||
Chill
Calgary25938 Posts
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Raithed
China7077 Posts
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Saracen
United States5139 Posts
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skyglow1
New Zealand3962 Posts
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Purind
Canada3562 Posts
x = L1cos theta 1 + L2 cos (something that is not theta 2t) y = L1 sin theta 1 + L2 sin (some angle that is not theta 2) 2 equations, 2 unknowns The "angle that is not theta 2" is an angle that the second arm makes with the horizontal (so draw an imaginary line going in the x direction, starting at the "start" of arm 2) From this "angle that is not theta 2," you can find theta 2 I'm assuming x and y are the end coordintaes of the arm (the coords of where L2 is pointing to) | ||
Raithed
China7077 Posts
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Chill
Calgary25938 Posts
Please explain what the hell is going on in this picture. Edit: rofl what is Theta two? It's like I have a line segment terminating in another line. But now imagine if that line continued, what would that angle be? 180. Thats the definition of a line. --;; You really need to put some effort in explaining what the hell youre trying to do. Or draw a proper diagram. This is really frustrating because the actual problem is like some stuff tons of people here could solve if we were given proper background. | ||
Raithed
China7077 Posts
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Chill
Calgary25938 Posts
Theres something you aren't explaining properly. For example, you have given us a picture similar to this: It's not possible to solve without relating X and Y to it somehow. If it's a robot arm, shouldn't X=Y=R since the arm is constant length? Basically WHAT ARE X AND Y? In your diagram they are just fucking arbitrary lengths that don't relate to a goddamn thing. | ||
Chill
Calgary25938 Posts
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mjh
United States133 Posts
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Raithed
China7077 Posts
but i wouldnt expect you to understand it. R is the faded line. | ||
Purind
Canada3562 Posts
And is there anything wrong with my solution? I only assumed I knew what the question was because I've taken a robotics course and have done this stuff, so I can semi-guess what the question is asking, but I don't really know myself | ||
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