EPTMy Professor Plays SC2? - Page 2
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Otakusan
United States59 Posts
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wooozy
3813 Posts
On September 16 2010 15:54 Otakusan wrote: This professor is obviously a noob because 200 Zerglings and 800 Banelings = 500 supply. Impossible situation. Multiple players. | ||
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phosphorylation
United States2935 Posts
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Chairman Ray
United States11903 Posts
On September 16 2010 14:53 ooni wrote: I'm sure helping with homeworks is not allowed in this forum but here's the answer to it anyway + Show Spoiler + SPAWN MORE OVERLORDS He should use the more technical term - O-lords. | ||
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professorjoak
318 Posts
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Najda
United States3765 Posts
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Ghad
Norway2551 Posts
On September 16 2010 14:56 Thegilaboy wrote: It's a trick question, you can never have that many zerglings and banelings at a time! Lol, that is what i was thinking! This processor is made of win. | ||
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LeoTheLion
China958 Posts
let b_n and z_n be the number of b-lings and z-lings of the nth generation. inspection shows that if z_i - b_i > 0, then z_n - b_n is an unbounded monotone sequence as n grows. thus, we make our induction on the stronger assumption that z_n <= b_n. (this surely satisfies that z_n <= 2*b_n, since b_n < 2*b_n.) hypothesis: if z_n <= b_n, then z_n+1 <= b_n+1. prove that and you're done. you can rewrite it as b_n - z_n > 0. (there is a slight nuance if the difference is odd or even) | ||
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sob3k
United States7572 Posts
On September 16 2010 16:54 Ghad wrote: Lol, that is what i was thinking! This processor is made of win. On September 16 2010 16:54 Ghad wrote: Lol, that is what i was thinking! This processor is made of win. On September 16 2010 16:54 Ghad wrote: This processor is made of win. wat | ||
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Muirhead
United States556 Posts
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Klockan3
Sweden2866 Posts
Anyhow, it is easy to show that: The number of zlings after n+1 cycles is 200+600*2^n The number of blings after n cycles is 200+600*2^n | ||
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LeoTheLion
China958 Posts
On September 16 2010 17:03 Klockan3 wrote: Hahaha, it is a trick question, if you try to put the boundaries he wants you wouldn't get anything, you need to prove a stronger statement. Anyhow, it is easy to show that: The number of zlings after n+1 cycles is 200+600*2^n The number of blings after n cycles is 200+600*2^n 2nd generation 200 zlings mate with 200 blings = 200 zlings and 200 blings 600 blings left over, so 300 pairs = 600 blings and 300 zlings. total = 500 zlings and 800 blings, your formula doesn't work | ||
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VTArlock
United States1763 Posts
Answer not possible, 200z-lings and 800 b-lings are past the 200 supply limit cap. GG If he would give +1 point and not mark you incorrect...lmao Awesome Teacher | ||
tofucake
Hyrule19203 Posts
[edit] But if you see this on a test, you should write "You require more O-lords". | ||
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CheAse
Canada919 Posts
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Carnac
Germany / USA16648 Posts
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Plaaguu
United States406 Posts
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Bill Murray
United States9292 Posts
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Adeny
Norway1233 Posts
Hand in, ace it. | ||
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Count9
China10928 Posts
On September 16 2010 19:20 Carnac wrote: Do the math, write it down and then add something about SC2 imho or just challenge him to a SC2 match over your grades Might want to check his profile before that. | ||
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